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The average volunteer ambulance member is 45 years old and has 8 years of service, according to the Democrat \& Chronicle article "Unpaid ambulance workers could get 'pension"' (January 23,2005 ). The quoted statistics were based on the Penfield Volunteer Ambulance Squad of 80 members. If the Penfield Volunteer Ambulance Squad is considered representative of all upstate New York volunteer ambulance squads, determine a \(95 \%\) confidence interval for the mean age of all volunteer ambulance members in upstate New York. Assume the population standard deviation is 7.8 years.

Short Answer

Expert verified
The \(95 \%\) confidence interval for the mean age of all volunteer ambulance members in upstate New York is \(43.43 - 46.57\) years.

Step by step solution

01

Understanding the Problem

This problem involves finding a \(95 \%\ confidence\) interval for the mean age of all upstate New York ambulance volunteers. Here we know the mean age is 45 years, the standard deviation is 7.8 years, and the squad size, considered as sample size, is 80 members.
02

Understanding Confidence Interval

The formula to calculate Confidence Interval is \(X ± Z * (σ / √n)\), where \(X\) represents sample mean, \(Z\) represents Z-score (for \(95\%\) confidence interval, \(Z = 1.96\)), \(σ\) represents population standard deviation, and \(n\) represents number of observations or sample size.
03

Plugging in the Values

Now, we substitute the given values into our confidence interval formula i.e., \(45 ± 1.96 * (7.8 / √80)\)
04

Calculating the Confidence Interval

The calculation of \(45 ± 1.96 * (7.8 / √80)\) results in the confidence interval \(43.43 - 46.57\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics Education
Statistics plays a critical role in a wide range of disciplines, including healthcare, economics, and social sciences. Understanding statistics and its applications allows for informed decisions based on data analysis. In our current exercise, we delve into one particular statistical process: the calculation of a confidence interval. A confidence interval provides an estimated range of values that is likely to include an unknown population parameter. In this context, we've calculated a 95% confidence interval for the mean age of volunteers in ambulance squads based on a sample from the Penfield Volunteer Ambulance Squad.

It's essential for students to understand that the calculated interval does not promise that the true mean age falls within this range for 95 times out of 100 samples. Instead, it implies that if we were to take multiple samples and calculate a confidence interval for each, approximately 95% of those intervals would contain the true mean age. This is a subtle but fundamental concept in statistics education, emphasizing the probabilistic nature of confidence intervals.
Population Standard Deviation
The population standard deviation (\( \boldsymbol{\text{σ}} \) is a measure of how much individuals within a population vary from the population mean. If we think of it in terms of our example, it helps us quantify the variation in ages among all volunteer ambulance members across upstate New York. A smaller standard deviation would indicate that the ages are clustered closely around the mean, with less variability, while a larger standard deviation would suggest a wider age range.

Knowing the population standard deviation allows us to calculate the 'spread' of the confidence interval. The standard deviation plays a crucial part in the confidence interval formula, and in the absence of its true value, a sample standard deviation can be used as an estimate. However, in our exercise, it has been provided as 7.8 years. Here's an important point: while we often deal with sample data, the population standard deviation is a parameter that pertains to the entire population - all volunteer ambulance members, not just our sample of 80.
Volunteer Ambulance Squads Demographics
Understanding the demographics of volunteer ambulance squads, such as age, years of service, education, and geographic location can greatly help in forming policies or programs targeting their welfare and effectiveness. The example we are exploring uses demographics—specifically, the average age—to create a broader picture of the volunteer workforce. Demographics are not just statistics; they represent the very human attributes that can influence how services like emergency response are delivered.

The specific demographic characteristic in our exercise — the average age of 45 years — was identified from the Penfield Volunteer Ambulance Squad. This data point was used to make a broader inference about all similar squads in upstate New York. This inference is possible and valid only if the sample we're using is truly representative of the wider population, which leads us handily to our next concept.
Representative Sample
A representative sample is a subset of the population that accurately reflects the members of the entire population. In our case, we are presupposing that the 80 members of the Penfield Volunteer Ambulance Squad are reflective of all volunteer ambulance members in upstate New York in terms of age. The quality of being 'representative' is paramount, as it ensures that the confidence interval we calculate from our sample is likely to be relevant to the wider population.

It's worth noting, however, that 'representativeness' can often be a tricky assumption to confirm. The concept is more robust when the sample is randomly selected and sufficiently large, and all subgroups in the population are proportionally represented. Since over- or under-represented groups in the sample can skew results, obtaining a truly representative sample is one of the most important aspects when it comes to generalizing findings from a study.

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Most popular questions from this chapter

The owner of a local chain of grocery stores is always trying to minimize the time it takes her customers to check out. In the past, she has conducted many studies of the checkout times, and they have displayed a normal distribution with a mean time of 12 minutes and a standard deviation of 2.3 minutes. She has implemented a new schedule for cashiers in hopes of reducing the mean checkout time. A random sample of 28 customers visiting her store this week resulted in a mean of 10.9 minutes. Does she have sufficient evidence to claim the mean checkout time this week was less than 12 minutes? Use \(\alpha=0.02\)

In a large supermarket the customer's waiting time to check out is approximately normally distributed with a standard deviation of 2.5 minutes. A sample of 24 customer waiting times produced a mean of 10.6 minutes. Is this evidence sufficient to reject the supermarket's claim that its customer checkout time averages no more than 9 minutes? Complete this hypothesis test using the 0.02 level of significance. a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

Who says that the more you spend on a wristwatch, the more accurately the watch will keep time? Some say that you can now buy a quartz watch for less than \(\$ 25\) that keeps time just as accurately as watches that cost four times as much. Suppose the average accuracy for all watches being sold today, regardless of price, is within 19.8 seconds per month with a standard deviation of 9.1 seconds. A random sample of 36 quartz watches priced less than \(\$ 25\) is taken, and their accuracy check reveals a sample mean error of 22.7 seconds per month. Based on this evidence, complete the hypothesis test of \(H_{o}: \mu=20\) vs. \(H_{a}: \mu>20\) at the 0.05 level of significance using the probability-value approach. a. Define the parameter. b. State the null and alternative hypotheses. c. Specify the hypothesis test criteria. d. Present the sample evidence. e. Find the probability distribution information. f. Determine the results.

Suppose a hypothesis test is conducted using the \(p^{-}\) value approach and assigned a level of significance of \(\alpha=0.01\) a. How is the 0.01 used in completing the hypothesis test? b. If \(\alpha\) is changed to \(0.05,\) what effect would this have on the test procedure?

The weights of full boxes of a certain kind of cereal are normally distributed with a standard deviation of 0.27 oz. A sample of 18 randomly selected boxes produced a mean weight of 9.87 oz. a. Find the \(95 \%\) confidence interval for the true mean weight of a box of this cereal. b. Find the \(99 \%\) confidence interval for the true mean weight of a box of this cereal. c. What effect did the increase in the level of confidence have on the width of the confidence interval?

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