/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 133 State the null and alternative h... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

State the null and alternative hypotheses used to test each of the following claims: a. The mean reaction time is less than 1.25 seconds. b. The mean score on that qualifying exam is different from 335. c. The mean selling price of homes in the area is no more than \(\$ 230,000\).

Short Answer

Expert verified
a. Null hypothesis, \(H_0: \mu = 1.25\); Alternative hypothesis, \(H_a: \mu < 1.25\). \n b. Null hypothesis, \(H_0: \mu = 335\); Alternative hypothesis, \(H_a: \mu \neq 335\). \n c. Null hypothesis, \(H_0: \mu = \$230,000\); Alternative hypothesis, \(H_a: \mu \leq \$230,000\).

Step by step solution

01

Claim a. Hypotheses

The claim specifies that the mean reaction time is less than 1.25 seconds. Thus, the null hypothesis, \( H_0 \), is that the mean reaction time is equal to 1.25 seconds, and the alternative hypothesis, \( H_a \), is the mean less than 1.25 seconds. Formally, we can write:\n Null Hypothesis: \( H_0: \mu = 1.25 (seconds) \) \n Alternative Hypothesis: \( H_a: \mu < 1.25 (seconds) \).
02

Claim b. Hypotheses

The claim implies that the mean score on the qualifying exam is different from 335. Hence, the null hypothesis, \( H_0 \), is the mean score being equal to 335, and the alternative hypothesis, \( H_a \), is the mean not equal to 335. We can express this as:\n Null Hypothesis: \( H_0: \mu = 335 \) \nAlternative Hypothesis: \( H_a: \mu \neq 335 \).
03

Claim c. Hypotheses

The claim points out that the mean selling price of homes in the area is no more than $230,000. Therefore, the null hypothesis, \( H_0 \), is the mean selling price equal to $230,000, and the alternative hypothesis, \( H_a \), is the mean less than or equal to $230,000. In formal terms:\n Null Hypothesis: \( H_0: \mu = \$230,000 \) \nAlternative Hypothesis: \( H_a: \mu \leq \$230,000 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis is a fundamental concept in the realm of hypothesis testing, serving as a default statement that there is no effect or no difference. It's a starting point for statistical analysis, where researchers presume that any kind of effect they are analyzing does not exist. For instance, if scientists are studying a new drug, they start by assuming that the drug has no effect and that any change is due to random chance.

When formulating a null hypothesis, one uses the symbol H_0 to represent this claim. In the context of a claim that a mean reaction time is less than 1.25 seconds, as seen in the original exercise, the null hypothesis states precisely and mathematically that the mean is exactly 1.25 seconds: H_0: \( \mu = 1.25 \). The null hypothesis is essentially a skeptical perspective, requiring evidence to reject it and support the alternative hypothesis.
Alternative Hypothesis
Contrary to the null hypothesis, the alternative hypothesis (H_a or H_1) is the statement that researchers really want to test and provide evidence for. This hypothesis asserts that there is an effect or difference, and it is formulated in opposition to the null hypothesis.

Depending on the research question, the alternative hypothesis can take many forms: it might suggest that a parameter is larger, smaller, or different than the null hypothesis value. For example, in testing whether the mean selling price of homes is no more than \$230,000, the alternative hypothesis implies that the true mean could be less than this value, shown formally as H_a: \( \mu \leq \$230,000 \). The goal of hypothesis testing is to determine whether there's enough evidence to favor this hypothesis over the null.
Mean Difference
The concept of mean difference is central to many hypothesis tests. It represents the difference between the sample mean and a hypothesized or known population mean. In essence, the mean difference speaks to the question, 'How much does our sample deviate from the expected norm?'. This measurement is crucial when comparing groups or treatments in studies.

A key task for researchers is to calculate this mean difference and determine if any observed difference is statistically significant. In scenario-b from the exercise, researchers are interested in determining if the mean score on a qualifying exam is different from 335. They calculate the mean of their sample data and compare it to 335. The 'difference' is what they test statistically to conclude whether the observed mean is just a result of sampling variability or a true deviation from the hypothesized population mean.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Waiting times (in hours) at a popular restaurant are believed to be approximately normally distributed with a variance of 2.25 during busy periods. a. A sample of 20 customers revealed a mean waiting time of 1.52 hours. Construct the \(95 \%\) confidence interval for the population mean. b. Suppose that the mean of 1.52 hours had resulted from a sample of 32 customers. Find the \(95 \%\) confidence interval. c. What effect does a larger sample size have on the confidence interval?

A normally distributed population is known to have a standard deviation of \(5,\) but its mean is in question. It has been argued to be either \(\mu=80\) or \(\mu=90,\) and the following hypothesis test has been devised to settle the argument. The null hypothesis, \(H_{o}: \mu=80,\) will be tested by using one randomly selected data value and comparing it with the critical value of \(86 .\) If the data value is greater than or equal to \(86,\) the null hypothesis will be rejected. a. Find \(\alpha,\) the probability of the type I error. b. Find \(\beta,\) the probability of the type II error.

Because the size of the type I error can always be made smaller by reducing the size of the critical region, why don't we always choose critical regions that make \(\alpha\) extremely small?

Women own an average of 15 pairs of shoes. This is based on a survey of female adults by Kelton Research for Eneslow, the New York City-based Foot Comfort Center. Suppose a random sample of 35 newly hired female college graduates was taken and the sample mean was 18.37 pairs of shoes. If \(\sigma=6.12,\) does this sample provide sufficient evidence that young female college graduates' mean number of shoes is greater than the overall mean number for all female adults? Use a 0.10 level of significance.

We are interested in estimating the mean life of a new product. How large a sample do we need to take to estimate the mean to within \(\frac{1}{10}\) of a standard deviation with \(90 \%\) confidence?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.