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Professor Hart does not believe the statement "The mean distance commuted daily by the nonresident students at our college is no more than 9 miles." State the null and alternative hypotheses he would use to challenge this statement.

Short Answer

Expert verified
The null hypothesis H0: \(\mu \leq 9\) miles (The mean daily commute distance of the non-resident students is equal to or less than 9 miles). The alternative hypothesis H1: \(\mu > 9\) miles (The mean daily commute distance of the non-resident students is more than 9 miles).

Step by step solution

01

Understanding the statement

First, analyze the statement of Professor Hart. He does not believe that the mean distance commuted daily by non-resident students is no more than 9 miles. This disbelief indicates that he thinks the mean distance is more than 9 miles.
02

Formulate the Null Hypothesis (H0)

The Null Hypothesis (H0) usually represents the status quo or a statement of no effect or no difference. Here, the statement that needs to be tested is 'The mean distance commuted daily by the non-resident students at our college is no more than 9 miles.' Therefore, H0 would be: The mean distance is equal to or less than 9 miles. In terms of notation, if we let \(\mu\) represent the mean distance travelled, we would write H0 as \(\mu \leq 9\).
03

Formulate the Alternative Hypothesis (H1)

The Alternative Hypothesis (H1) represents a statement that contradicts the Null Hypothesis. In this case, it reflects Professor Hart's disbelief and thus would be: The mean distance travelled is more than 9 miles. In notation, this would be written as H1 as \(\mu > 9\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
When delving into statistical hypothesis testing, the null hypothesis (\textsc{H0}) is the initial claim we wish to test. It's essentially the default position that assumes no difference or no effect. In the context of Professor Hart's disbelief, the null hypothesis would be that the mean distance commuted daily by non-resident students is no more than 9 miles, meaning it could be less than or exactly 9, but not more. Formally stated, the \textsc{H0} for our problem is \(\mu \leq 9\). It's critical for students to understand that in hypothesis testing, we are not proving the null hypothesis; rather, we are looking for evidence to refute it in favor of the alternative hypothesis.

It's important to note that the null hypothesis is always stated with an equal sign (or an inequality that includes equality), and it's the assumption we subject to scrutiny during hypothesis testing.
Alternative Hypothesis
The alternative hypothesis (\textsc{H1} or \textsc{Ha}), on the other hand, is the statement we are seeking to provide evidence for. It's the hypothesis that suggests a new effect or difference that counters the null hypothesis. Based on Professor Hart's suspicion, the alternative hypothesis would claim that the mean distance commuted is actually more than 9 miles. Symbolically, it is expressed as \(\mu > 9\). This would be the statement supported if the data provide sufficient evidence against the null hypothesis. Students should comprehend that the alternative hypothesis is the research hypothesis - the claim that one hopes to support with statistical evidence.

In practice, formulating the alternative hypothesis directly relates to the research question or the skepticism about the status quo. It invariably specifies an outcome that would be considered statistically significant if the null hypothesis were rejected.
Statistical Significance
Statistical significance plays a pivotal role in hypothesis testing. It refers to the probability that the observed data would be at least as extreme as it is due to random chance alone, assuming the null hypothesis is true. When we say a result is statistically significant, we mean that there is statistical evidence to suggest that there is a true difference (or effect), and it's not just due to random variability.

In the exercise involving Professor Hart and the commuting distances of students, we aim to determine if there's significant evidence to conclude that the mean distance is indeed greater than 9 miles. The level of significance, usually denoted by \(\alpha\), is a threshold set by the researcher that defines the probability of rejecting the null hypothesis when it's actually true (Type I error). Common choices for \(\alpha\) are 0.05, 0.01, or even 0.10. A result is statistically significant if the p-value (probability) calculated from the test is less than the chosen \(\alpha\) level.
Hypothesis Testing
Hypothesis testing is a systematic method to decide whether to accept or reject the null hypothesis (\textsc{H0}), based on sample data. It's a core component of statistical inference. The process involves several steps, starting with stating both the null and alternative hypotheses, selecting a level of significance (such as 0.05), and choosing the appropriate test statistic based on the data and the hypotheses.

In our educational scenario with Professor Hart, the procedure would first involve collecting data on the commuting distances of the nonresident students. Then, statistical analysis would be performed to calculate a test statistic (such as a t-test if the sample is small or a z-test if the sample is large and the population standard deviation is known). If this test statistic yields a p-value less than the set \(\alpha\) level, the null hypothesis would be rejected, supporting Professor Hart's suspicion that the students commute more than 9 miles on average.

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Most popular questions from this chapter

A manufacturer of stone-ground, deli-style mustard uses a high-speed machine to fill jars. The amount of mustard dispensed into the jars forms a normal distribution with a mean 290 grams and a standard deviation 4 grams. Each hour a random sample of 12 jars is taken from that hour's production. If the sample mean is between 287.74 and \(292.26,\) that hour's production is accepted; otherwise, it is rejected and the machine is recalibrated before continuing. a. What is the probability of the type I error by rejecting the previous hour's production when the mean jar weight is 290 grams? b. What is the probability of the type II error by accepting the previous hour's production when the mean jar weight is actually 288 grams?

a. If \(\alpha\) is assigned the value \(0.001,\) what are we saying about the type I error? b. If \(\alpha\) is assigned the value \(0.05,\) what are we saying about the type I error? c. If \(\alpha\) is assigned the value \(0.10,\) what are we saying about the type I error?

Assume that \(z\) is the test statistic and calculate the value of \(z \star\) for each of the following: a. \(\quad H_{o}: \mu=10, \sigma=3, n=40, \bar{x}=10.6\) b. \(\quad H_{o}: \mu=120, \sigma=23, n=25, \bar{x}=126.2\) c. \(\quad H_{o}: \mu=18.2, \sigma=3.7, n=140, \bar{x}=18.93\) d. \(\quad H_{o}: \mu=81, \sigma=13.3, n=50, \bar{x}=79.6\)

We are interested in estimating the mean life of a new product. How large a sample do we need to take to estimate the mean to within \(\frac{1}{10}\) of a standard deviation with \(90 \%\) confidence?

Ponemon Institute, along with Intel, published "The cost of a Lost Laptop" study in April 2009. With an increasingly mobile workforce carrying around more sensitive data on their laptops, the loss involves much more than the laptop itself. The average cost of a lost laptop based on cases from various industries is \(\$ 49,246 .\) This figure includes laptop replacement, data breach cost, lost productivity cost, and other legal and forensic costs. A separate study conducted with respect to 30 cases from health care industries produced a mean of \(\$ 67,873 .\) Assuming that \(\sigma=\$ 25,000,\) is there sufficient evidence to support the claim that health care laptop replacement costs are higher in general? Use a 0.001 level of significance.

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