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Find the area under the standard normal curve to the right of \(z=2.03, P(z>2.03).\)

Short Answer

Expert verified
The area under the standard normal curve to the right of \( z=2.03 \) is 0.0212. This means the probability \( P(z>2.03) = 0.0212 \).

Step by step solution

01

Understanding the problem setup

Recognize that the standard normal distribution is being used. This is implied when z-scores are used, and by the phrase 'standard normal curve.' This means that the distribution has a mean of 0 and standard deviation of 1.
02

Using a Z-score table or tool

Use a standard normal (Z-score) table, calculator, or online tool to find the area to the left of \( z=2.03 \). This will typically be given directly and one will find that \( P(Z < 2.03) \approx 0.9788 \).
03

Calculating the area to the right

The total area under the standard normal curve is 1. Therefore, to find the area to the right of \( z=2.03 \), subtract the area to the left of \( z=2.03 \) from 1: \( P(Z > 2.03) = 1 - P(Z < 2.03) = 1 - 0.9788 = 0.0212 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score
Understanding the z-score is crucial when working with standard normal distributions. It is a statistical measurement that describes a value's relationship to the mean of a group of values. In simpler terms, the z-score tells us how many standard deviations away a particular value is from the mean.

When a z-score is positive, it signifies that the value is above the mean. Conversely, a negative z-score indicates that the value is below the mean. To calculate a z-score, use the formula:
\( z = \frac{X - \mu}{\sigma} \),
where \( X \) is the value in question, \( \mu \) represents the mean, and \( \sigma \) is the standard deviation. In the exercise provided, a z-score of 2.03 means the value is 2.03 standard deviations above the mean of the distribution. This standardized value helps in comparing different data points and is used in finding probabilities within the normal distribution.
Normal Curve Area
The normal curve area refers to the proportion of data within a certain range under a normal distribution graph. The curve itself represents the bell-shaped distribution of data points, and is symmetrical about the mean. The total area under the curve corresponds to the probability of all possible outcomes and is equal to 1.

Understanding the distribution's area is vital because it helps in calculating the likelihood of certain observations occurring. For example, an area to the left of a z-score represents the probability that a random variable is less than that z-score. Conversely, the area to the right represents the probability that the variable is greater than that z-score. The exercise asked to calculate the area to the right of \( z = 2.03 \), which reflects the proportion of data points exceeding that z-score.
Probability in Normal Distribution
The probability in normal distribution represents the likelihood of a random variable falling within a specific range. A normal distribution is characterized by its mean and standard deviation, and it's important to remember that it's a continuous distribution, implying that the probability of the variable taking on any single, specific value is zero. Instead, probabilities are assessed over intervals.

Utilizing the z-score and the standard normal distribution table (also referred to as a z-table), we can find the probability to the left or right of any z-score. In our example, after finding the area to the left of \( z = 2.03 \), we calculated the probability of the variable being larger by subtracting this area from the total area under the curve. This process is rooted in the fact that the sum of probabilities for all possible outcomes in a probability distribution must equal 1.

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Most popular questions from this chapter

Find the values \(n p\) and \(n q\) (recall: \(q=1-p\) ) for a binomial experiment with \(n=100\) and \(p=0.02 .\) Does this binomial distribution satisfy the rule for normal approximation? Explain.

A soft drink vending machine can be regulated so that it dispenses an average of \(\mu\) oz of soft drink per cup. a. If the ounces dispensed per cup are normally distributed with a standard deviation of 0.2 oz, find the setting for \(\mu\) that will allow a 6 -oz glass to hold (without overflowing) the amount dispensed \(99 \%\) of the time. b. Use a computer or calculator to simulate drawing a sample of 40 cups of soft drink from the machine (set using your answer to part a).

a. Find the area under the standard normal curve to the left of \(z=0, P(z<0).\) b. Find the area under the standard normal curve to the right of \(z=0, P(z>0).\)

Find the area under the standard normal curve to the right of \(z=-2.35, P(z>-2.35).\)

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