/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 Of all the trees planted by a la... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Of all the trees planted by a landscaping firm, \(90 \%\) survive. What is the probability that 8 or more of the 10 trees they just planted will survive? (Find the answer by using a table.)

Short Answer

Expert verified
The probability that 8 or more out of the 10 trees will survive can be calculated by summing up the probabilities for 8, 9, and 10 trees surviving. These calculations involve the binomial distribution and combinatory mathematics. It is crucial to remember that 'at least 8 trees' includes the probabilities for exactly 8, 9, and 10 trees.

Step by step solution

01

Identify the Relevant Parameters

First, allocate the parameters provided in the exercise. The number of trials (n) is 10, and the probability of survival (p) is 0.90.
02

Probabilities Calculation

Let's find the probability of exactly 8, 9, and 10 trees surviving. The probability mass function for a binomial distribution is: \(\ P(X=k) = C(n, k) * p^k * (1-p)^(n-k) \) where \(P(X=k)\) is the probability of \( k \) successes in \( n \) trials, \( C(n, k) \) is a combination which calculates the number of ways you can choose \( k \) successes from \( n \) trials. Apply this formula for k=8,9,10.
03

Calculation of Binomial Coefficient

The binomial coefficient is calculated as: \(\ C(n, k) = n! / [(n-k)!*k!] \) where '!' stands for factorial. When you replace n with 10 and k with each of 8, 9, and 10, then calculate individually for these values. This will give us the number of ways 8, 9, and 10 trees can survive among 10 planted trees.
04

Final Result

Calculate the probabilities for 8, 9, and 10 trees surviving and then add up these probabilities to get the probability of 8 or more trees surviving. This final summation represents the total probability that 8, 9, or 10 trees will survive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
The concept of probability revolves around quantifying the chance of an event occurring. In many daily situations, we use probability to predict likelihoods, such as the weather or the outcome of a game. When faced with a binomial distribution problem, calculating these chances involves determining the probability of a certain number of successes across a given number of trials.
In our exercise, each tree either survives or it doesn't, making it a classic scenario for binomial probability. The probability of an individual event (a tree surviving) is given as 0.90. We want to find the probability that 8 or more trees out of 10 survive. This involves computing individual probabilities for exactly 8, 9, and 10 trees surviving, then summing these probabilities.

  • The sum of these probabilities indicates the likelihood of having 8 or more successes (surviving trees) in our sequence of 10 trials.
  • Probabilities are real numbers between 0 and 1, where 0 is impossible and 1 is certain.
  • Adding up probabilities of multiple events means we're looking at the cumulative probability of these events.
Understanding probability is fundamental to grasp how likely it is for certain outcomes to occur under specific conditions.
Success Trials
In the context of a binomial distribution, trials refer to the attempts or experiments we're considering. Each trial has two possible outcomes: success or failure. When discussing 'success trials', we're focusing on the trials where the desired outcome occurs, like a tree surviving.
A key feature of binomial distributions is that trials are independent, meaning the result of one trial doesn't affect the others. For our example:
  • Each of the 10 trees planted is an independent trial.
  • "Success" is defined by a tree's survival.
  • The probability of success for each tree (or trial) is 0.90.
    Thus, **success trials** help us determine how many successes (survivals) occur throughout our trials.
The concept of success trials provides the foundation for working with binomial distributions because it defines what counts as a success, what doesn’t, and how likely these successes are.
Factorial Calculation
Factorial calculations are an essential part of determining binomial coefficients in probability and statistics. A factorial, represented by !, defines the product of all positive integers up to a specified number. For instance, 5! equals 5 × 4 × 3 × 2 × 1 = 120.
Factorials become particularly useful when calculating combinations, such as how many ways we can choose a subset of items from a larger set without regard to order.

In the binomial distribution, calculating combinations helps find the probability of a certain number of successes, as illustrated in the formula:\( C(n, k) = \frac{n!}{(n-k)!k!} \)
  • Here, \( C(n, k) \) is the number of ways to choose \( k \) successes from \( n \) trials.
  • Factorials simplify the computations needed to determine these coefficients.
  • In our exercise, using this formula with \( n = 10 \) calculates the ways different numbers of trees survive, giving each scenario a weight in probability terms.
Factorial calculations are foundational for understanding combinatorics and their applications in probability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If you could stop time and live forever in good health, what age would you pick? Answers to this question were reported in a USA Today Snapshot. The average ideal age for each age group is listed in the following table; the average ideal age for all adults was found to be \(41 .\) Interestingly, those younger than 30 years want to be older, whereas those older than 30 years want to be younger. $$\begin{array}{l|cccccc} \hline \begin{array}{l} \text { Age Group } \\ \text { Ideal Age } \end{array} & \begin{array}{c} 18-24 \\ 27 \end{array} & \begin{array}{c} 25-29 \\ 31 \end{array} & \begin{array}{c} 30-39 \\ 37 \end{array} & \begin{array}{c} 40-49 \\ 40 \end{array} & \begin{array}{c} 50-64 \\ 44 \end{array} & \begin{array}{c} 65+ \\ 59 \end{array} \\ \hline \end{array}$$ Age is used as a variable twice in this application. a. The age of the person being interviewed is not the random variable in this situation. Explain why and describe how "age" is used with regard to age group. b. What is the random variable involved in this study? Describe its role in this situation. c. Is the random variable discrete or continuous? Explain.

A March 11,2009, USA Today article titled "College freshmen study booze more than books" presents the following chart depicting average hours per week spent on various activities by college freshmen. The study's sponsor, Outside the Classroom, surveyed more than 30,000 first-year students on 76 campuses. $$\begin{array}{lc} \text { Activity } & \text { Average Amount of Time/Week } \\\ \hline \text { Partying } & 10.2 \text { hours } \\ \text { Studying } & 8.4 \text { hours } \\ \text { Exercising } & 5.0 \text { hours } \\ \text { Online social networking or } & 4.1 \text { hours } \\ \text { playing video games } & \\ \text { Social networking } & 2.5 \text { hours } \\ \text { Working for pay } & 2.2 \text { hours } \\ \hline \end{array}$$ a. What is the random variable involved in this study? b. Is the random variable discrete or continuous? Explain.

The number of ships to arrive at a harbor on any given day is a random variable represented by \(x .\) The probability distribution for \(x\) is as follows: $$\begin{array}{l|lllll}\hline \boldsymbol{x} & 10 & 11 & 12 & 13 & 14 \\\\\boldsymbol{P}(\boldsymbol{x}) & 0.4 & 0.2 & 0.2 & 0.1 & 0.1 \\\\\hline\end{array}$$ Find the mean and standard deviation of the number of ships that arrive at a harbor on a given day.

Above-average hot weather extended over the northwest on August \(3,2009 .\) The day's forecasted high temperatures in four cities in the affected area were: $$\begin{array}{lc} \text { City } & \text { Temperature } \\ \hline \text { Boise, } 1 \mathrm{D} & 100^{\circ} \\ \text { Spokane, WA } & 95^{\circ} \\\ \text { Portland, OR } & 91^{\circ} \\ \text { Helena, } \mathrm{MT} & 91^{\circ} \\ \hline \end{array}$$ a. What is the random variable involved in this study? b. Is the random variable discrete or continuous? Explain.

An archer shoots arrows at the bull's-eye of a target and measures the distance from the center of the target to the arrow. Identify the random variable of interest, determine whether it is discrete or continuous, and list its possible values.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.