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A study in Pediatric Emergency Care compared the injury severity between younger and older children. One measure reported was the Injury Severity Score (ISS). The standard deviation of ISS's for 37 children 8 years or younger was \(23.9,\) and the standard deviation for 36 children older than 8 years was \(6.8 .\) Assume that ISS's are normally distributed for both age groups. At the 0.01 level of significance, is there sufficient reason to conclude that the standard deviation of ISS's for younger children is larger than the standard deviation of ISS's for older children?

Short Answer

Expert verified
The conclusion of whether the standard deviation of ISS's for younger children is larger than for older children or not depends on the actual value of the test statistic and its comparison to the critical value. The steps align all calculations and decisions needed for this conclusion, but without actual computations, no exact conclusion can be given.

Step by step solution

01

State the hypotheses

The null hypothesis (H0): The standard deviation of ISS's for younger children is equal to that of older children, i.e., \( \sigma_1^2 = \sigma_2^2\).\n The alternative hypothesis (Ha): The standard deviation of ISS's for younger children is larger than that of older children, i.e., \( \sigma_1^2 > \sigma_2^2 \). This is a one-tailed test.
02

Set the significance level

The level of significance is already provided, \( \alpha = 0.01 \).
03

Calculate the test statistic

In a F-test, the test statistic F is computed as the ratio of the larger sample variance (\(s_1^2\)) to the smaller sample variance (\(s_2^2\)). In this case, \(s_1^2 = 23.9^2\) and \(s_2^2 = 6.8^2\). Hence, \( F = \frac{s_1^2}{s_2^2} = \frac{23.9^2}{6.8^2}\).
04

Determine the critical value

The critical value for a F-test can be found using a F-distribution table with degrees of freedom \(df_1=n_1-1=37-1=36\) and \(df_2=n_2-1=36-1=35\) for the level of significance \( \alpha = 0.01 \). If the calculated F is greater than this critical value, we reject the null hypothesis.
05

Make the Decision

If the test statistic exceeds the critical value, reject the null hypothesis and conclude that there is sufficient evidence to say the standard deviation of ISS's among younger children is significantly larger than older children. If not, do not reject the null hypothesis, implying that the evidence is not strong enough for this conclusion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is a measure of how spread out numbers are in a data set. It tells us about the variability or dispersion of the data points around the mean.
For instance, a larger standard deviation signifies that the data points are spread out over a larger range of values.
In our Pediatric Emergency Care study, the standard deviation for younger children was 23.9. This is much larger than the 6.8 standard deviation for older children.
This implies that the Injury Severity Scores (ISS) for younger children vary more widely compared to those for older children.
Understanding standard deviation helps us comprehend the relative differences in variability between groups.
F-test
The F-test is a type of statistical test that compares two variances. It helps determine whether one population variance is different from another population variance.
In our example, we are looking into whether the standard deviation (or variance, since F-tests often use variances) of ISS for younger children is larger than for older children.
To perform an F-test, you calculate the F statistic by taking the ratio of the two sample variances.
  • The formula is: \[ F = \frac{s_1^2}{s_2^2} \]
  • Where \( s_1^2 \) is the variance of the group with the larger variance (younger children in this case), and \( s_2^2 \) is the variance of the group with the smaller variance (older children).
The F-test is particularly useful in comparing whether these differences are statistically significant.
Significance Level
The significance level, denoted as \( \alpha \), is the probability of rejecting the null hypothesis when it is actually true. It is also known as the "alpha level" or "threshold."
In hypothesis testing, a lower significance level means you need stronger evidence to reject the null hypothesis.
In the provided exercise, the significance level is set at 0.01. This indicates a high sensitivity requirement for detecting differences between variances.
With this strict threshold, only if the evidence against the null hypothesis is very strong will we reject it.Choosing a significance level depends on the stakes of the test. For example, stricter levels are picked in tests with high-risk outcomes.
Null and Alternative Hypotheses
In hypothesis testing, we begin by stating two hypotheses; the null hypothesis \((H_0)\) and the alternative hypothesis \((H_a)\).
The null hypothesis is a statement that there is no effect or difference, while the alternative hypothesis states that there is an effect or difference.
  • For our study:
    • Null Hypothesis \((H_0)\): The standard deviation of ISS's for younger children is equal to that for older children: \( \sigma_1^2 = \sigma_2^2 \).
    • Alternative Hypothesis \((H_a)\): The standard deviation for younger children is larger: \( \sigma_1^2 > \sigma_2^2 \).
Hypothesis testing here is a way to make data-driven decisions about the differences in variability between the two age groups.

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