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Many people who are involved with Major League Baseball believe that Yankees' baseball games tend to last longer than games played by other teams In order to test this theory, one other MLB team, the St. Louis Cardinals, was picked at random. The time of the game (in minutes) for 12 randomly selected Cardinals' games and 14 randomly selected Yankees' games was obtained. $$\begin{array}{cc} \text { Yankees } & \text { Cardinals } \\ \hline 155 & 208 \\\205 & 135 \\\190 & 161 \\\193 & 170 \\\232 & 150 \\\208 & 187 \\\174 & 200 \\\188 & 143 \\\229 & 154 \\\158 & 193 \\\202 & 128 \\\189 & 212 \\\232 & \\\211 & \\\\\hline\end{array}$$ Do these samples provide significant evidence to conclude that the mean time of Yankees' baseball games is significantly greater than the mean time of Cardinals' games? Use \(\alpha=0.05\).

Short Answer

Expert verified
The short answer can be found after performing the steps. If, as a result of these calculations, it is found that the t-statistic is greater than the critical value, the conclusion would be that the mean time of Yankees' games is indeed significantly greater than the mean time of Cardinals' games at a significance level of \(\alpha=0.05\). If the t-statistic is not greater, no such conclusion can be drawn.

Step by step solution

01

Calculate the Means

Calculate the mean time of games for each team. The mean is found by adding all of a set of values and then dividing by the number of values. Let's denote the mean time of Yankees' games as \( \mu_y \) and of Cardinals' games as \( \mu_c \).
02

Calculate the Standard Deviations

Calculate the sample standard deviation of game times for both teams. The standard deviation gives a measure of how spread out the numbers in a data set are. It is a square root of variance, which shows how much each number in a set differs from the mean. Let's denote the standard deviation of Yankees' games as \( \sigma_y \) and of Cardinals' games as \( \sigma_c \).
03

Calculate the t-Test Statistic

The formula for the t-statistic in an independent t-test is \(t = \frac{{\mu_y - \mu_c}}{{\sqrt{{\sigma_y^2/n_y + \sigma_c^2/n_c}}}}\), where \(n_y\) and \(n_c\) are the sample sizes of Yankees and Cardinals games respectively.
04

Compare t-Test Statistic with Critical Value

Compare the calculated t-statistic with the critical value from the t-distribution table. The critical value for a one-tailed test with \(\alpha=0.05\) and \(df=n_y+n_c-2\) degrees of freedom can be found in the table. If the calculated t-statistic is greater than the critical value, we reject the null hypothesis and conclude that there's significant evidence that mean time of Yankees' games is greater than Cardinals' games.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
The t-test is a statistical method used to determine if there is a significant difference between the means of two groups, which can be related in certain features. Here, we use it to compare the average game times of the Yankees and the Cardinals. The goal is to see whether the difference in their average (mean) game times is statistically meaningful. This is especially useful when the sample sizes are small, and the population variance is unknown. The t-test helps us decide whether to accept or reject the null hypothesis, which in this context states that the mean game times for the Yankees and the Cardinals are the same.
  • The t-test calculates a "t-statistic," a value that helps determine the probability of observing the data if the null hypothesis were true.
  • The greater the absolute value of the t-statistic, the more evidence there is against the null hypothesis.
  • In this problem, the test is one-tailed since we are specifically checking if Yankees' game times are greater.
sample mean
The sample mean is the average of a sample and is used to estimate the true population mean. In the exercise about the MLB games, we calculate the sample means for Yankees and Cardinals to compare them. To find the sample mean, sum up all the recorded game times for each team and then divide by the number of games. This gives us the average game time across the sampled matches. It's important because it acts as a simple summary of game durations and provides a centerpiece for making comparisons with other data sets.
  • For Yankees' games, sum all the times and divide by 14 (the number of Yankees games).
  • For Cardinals' games, sum all the times and divide by 12 (the number of Cardinals games).
  • The sample mean acts as the foundation for further statistical calculations, including the standard deviation and the t-test statistic.
standard deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation means that the values tend to be close to the mean of the set, while a high standard deviation means they are spread out over a wider range. In the context of the baseball game times, standard deviation lets us understand how consistent the game durations are for each team. Calculating the standard deviation involves several steps:
  • First, subtract the sample mean from each individual game time to find the "deviation" from the mean.
  • Then, square each deviation to eliminate negative values and emphasize larger deviations.
  • Average these squared deviations to find the variance.
  • Finally, take the square root of the variance to get the standard deviation. This measure is used in the t-test formula to assess the reliability of the sample mean.
critical value
A critical value is a point on the scale of the test statistic beyond which we reject the null hypothesis, and it corresponds to the significance level in hypothesis testing. It's essentially a threshold that determines the boundary of the rejection region for the test.In the example of Yankees and Cardinals game times, the critical value depends on the chosen significance level, \(\alpha=0.05\), and the degrees of freedom, which is calculated based on the sample sizes of both teams. You reference a t-distribution table to find the critical value.
  • The critical value tells you how extreme the t-statistic must be to consider the results statistically significant.
  • If the calculated t-statistic exceeds the critical value, the null hypothesis — that there is no difference in mean game times — is rejected.
  • In this exercise, since the test is one-tailed, we only look for if the Yankees' game times statistically significantly exceed the Cardinals'.

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Most popular questions from this chapter

Both parents and students have many concerns when considering colleges. One of the top three concerns, based on a College Partnership study, is "Choosing best major/career." Nineteen percent of the parents reported "Choosing best major/career" as a major concern whereas \(15 \%\) of students reported it as a major concern. If the study was conducted with a sample of 1750 students and their parents, test the hypothesis that "Choosing best major/career" was a bigger concern for the parents, at the 0.05 level of significance.

Calculate the estimate for the standard error of the difference between two proportions for each of the following cases:a. \( n_{1}=40, p_{1}^{\prime}=0.8, n_{2}=50,\) and \(p_{2}^{\prime}=0.8\) b. \( n_{1}=33, p_{1}^{\prime}=0.6, n_{2}=38,\) and \(p_{2}^{\prime}=0.65\)

Two independent random samples resulted in the following: Sample \(1: \quad n_{1}=12, s_{1}^{2}=190\) Sample \(2: \quad n_{2}=18, s_{2}^{2}=150\) Find the estimate for the standard error for the difference

State the null and alternative hypotheses that would be used to test the following claims: a. There is a difference between the mean age of employees at two different large companies. b. The mean of population 1 is greater than the mean of population 2 c. The mean yield of sunflower seeds per county in North Dakota is less than the mean yield per county in South Dakota. d. There is no difference in the mean number of hours spent studying per week between male and female college students.

Find the confidence coefficient, \(t\left(\mathrm{df}, \frac{\alpha}{2}\right),\) that would be used to find the maximum error for each of the following situations when estimating the difference between two means, \(\mu_{1}-\mu_{2}\) a. \(\quad 1-\alpha=0.95, n_{1}=25, n_{2}=15\) b. \(1-\alpha=0.98, n_{1}=43, n_{2}=32\) c. \(\quad 1-\alpha=0.99, n_{1}=19, n_{2}=45\)

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