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If \(a\) and \(b\) are integers, not both of which are zero, verify that $$ \operatorname{gcd}(a, b)=\operatorname{gcd}(-a, b)=\operatorname{gcd}(a,-b)=\operatorname{gcd}(-a,-b) $$

Short Answer

Expert verified
Multiplying any number by -1 does not change its gcd with another number.

Step by step solution

01

Understand the gcd definition

The greatest common divisor (gcd) of two integers is the largest positive integer that divides both numbers without leaving a remainder.
02

Take gcd(a, b)

Denote the greatest common divisor of \(a\) and \(b\) as \(d\). Hence, \(d = \operatorname{gcd}(a, b)\). This means \(d\) divides both \(a\) and \(b\) exactly.
03

Verify gcd(-a, b)

Since multiplying an integer by -1 does not change the divisors of that integer, \(d\), which divides \(a\), will also divide \(-a\). Therefore, \(\operatorname{gcd}(-a, b) = \operatorname{gcd}(a, b)\).
04

Verify gcd(a, -b)

Similarly, \(d\) divides \(b\) and thus \(d\) will also divide \(-b\). Hence, \(\operatorname{gcd}(a, -b) = \operatorname{gcd}(a, b)\).
05

Verify gcd(-a, -b)

Since \(-a\) = \((-1)\times a\) and \(-b\) = \((-1)\times b\), all divisors of \(a\) and \(b\) will also be divisors of \(-a\) and \(-b\). Therefore, \(\operatorname{gcd}(-a, -b) = \operatorname{gcd}(a, b)\).
06

Conclude the equivalence

All calculations have shown that multiplying either \(a\) or \(b\) by \(-1\) does not change the greatest common divisor. Thus, we can conclude: \(\operatorname{gcd}(a, b) = \operatorname{gcd}(-a, b) = \operatorname{gcd}(a, -b) = \operatorname{gcd}(-a, -b)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integer Properties
Integers are a fundamental concept in mathematics, representing whole numbers that can be positive, negative, or zero. In the context of greatest common divisor (gcd) calculations, an important property of integers is their ability to be both positive and negative. This feature is particularly useful because it allows for consistent gcd results regardless of the sign of the integers involved.
To understand this better, consider how integers behave when multiplied by -1. Multiplying any integer by -1 simply changes its sign, not its value in terms of magnitude or divisibility. For instance, both 4 and -4 share the same divisors: 1, 2, and 4. Thus, this property helps in establishing that the gcd remains unchanged when either or both integers are negated.
This understanding stems from the definition of divisors, where a number is a divisor of another if it fits exactly into that number without leaving a remainder. Therefore, negating one or both integers does not impact the list of numbers that divide them without a remainder.
Divisibility
Divisibility is the ability of one integer to be divided by another integer without anything left over. When discussing the greatest common divisor, we refer to the greatest number that can divide two integers completely, leaving no remainder.
Understanding divisibility helps you see why the gcd of two numbers remains unchanged when both are negative. If a number, say 3, divides 9 with no remainder, it also divides -9 perfectly because division is concerned only with the absolute value, not the sign.
This concept of divisibility allows us to verify statements like \( \operatorname{gcd}(a, b) = \operatorname{gcd}(-a, b) = \operatorname{gcd}(a, -b) = \operatorname{gcd}(-a, -b) \). Since divisibility properties remain intact regardless of the numbers' signs, the gcd calculation remains the same.
Equivalence of Expressions
The equivalence of expressions in mathematics often involves showing that different expressions actually represent the same quantity or outcome. In the case of the gcd, we aim to prove that different combinations of negative signs in the input integers yield the same gcd.
This idea revolves around the understanding that the absolute value of integers determines the gcd, not the sign. Thus, \( \operatorname{gcd}(a, b) \) is equivalent to \( \operatorname{gcd}(-a, b) \), \( \operatorname{gcd}(a, -b) \), and \( \operatorname{gcd}(-a, -b) \).
To visualize this, think of any common divisor of two numbers. If this divisor divides both, it automatically divides their negatives as well, because multiplying the divisor by negative one still results in an integer. Therefore, all these expressions are equivalent in terms of their greatest common divisor.

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Most popular questions from this chapter

Given an odd integer \(a\), establish that $$ a^{2}+(a+2)^{2}+(a+4)^{2}+1 $$ is divisible by 12 .

Establish the inequality \(2^{n}<\left(\begin{array}{l}2 n \\\ n\end{array}\right)<2^{2 n}\), for \(n>1\). [Hint: Put \(x=2 \cdot 4 \cdot 6 \cdots(2 n), y=1 \cdot 3 \cdot 5 \cdots(2 n-1)\), and \(z=1 \cdot 2 \cdot 3 \cdots n ;\) show that \(x>y>z\), hence \(\left.x^{2}>x y>x z .\right]\)

Which of the following Diophantine equations cannot be solved? (a) \(6 x+51 y=22\). (b) \(33 x+14 y=115\) (c) \(14 x+35 y=93\)

Prove or disprove: If \(a \mid(b+c)\), then either \(a \mid b\) or \(a \mid c\).

Solve each of the puzzle-problems below: (a) Alcuin of York, 775. One hundred bushels of grain are distributed among 100 persons in such a way that each man receives 3 bushels, each woman 2 bushels, and each child \(\frac{1}{2}\) bushel. How many men, women, and children are there? (b) Mahaviracarya, 850 . There were 63 equal piles of plantain fruit put together and 7 single fruits. They were divided evenly among 23 travelers. What is the number of fruits in each pile? [Hint: Consider the Diophantine equation \(63 x+7=23 y\).] (c) Yen Kung, 1372. We have an unknown number of coins. If you make 77 strings of them, you are 50 coins short; but if you make 78 strings, it is exact. How many coins are there? [Hint: If \(N\) is the number of coins, then \(N=77 x+27=78 y\) for integers \(x\) and \(y .]\) (d) Christoff Rudolff, \(1526 .\) Find the number of men, women, and children in a company of 20 persons if together they pay 20 coins, each man paying 3 , each woman 2, and each child \(\frac{1}{3}\) (e) Euler, 1770 . Divide 100 into two summands such that one is divisible by 7 and the other by 11 .

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