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Finding the Standard Matrix and the Image In Exercises \(11-22,\) (a) find the standard matrix \(A\) for the linear transformation \(T,\) (b) use \(A\) to find the image of the vector \(\mathbf{v},\) and (c) sketch the graph of \(\mathbf{v}\) and its image. \(T\) is the reflection in the line \(y=x\) in \(R^{2}: T(x, y)=(y, x)\) \(\mathbf{v}=(3,4)\)

Short Answer

Expert verified
The standard matrix A for the given transformation is \( \begin{bmatrix} 0 & 1 \ 1 & 0 \end{bmatrix} \). Image of the vector \( \mathbf{v}=(3,4) \) under the transformation is \( (4,3) \).

Step by step solution

01

Calculation of matrix A

To calculate standard matrix A, we apply the transformation T to vectors along the x-axis (1,0) and y-axis (0,1) in the Euclidean plane. For T(x, y)=(y, x), we get T(1, 0)=(0, 1) and T(0, 1)=(1, 0). Therefore, the standard matrix A is \( \begin{bmatrix} 0 & 1 \ 1 & 0 \end{bmatrix} \).
02

Calculate the image of the vector \( \mathbf{v} \)

Now we apply transformation T to \( \mathbf{v}=(3,4) \). We perform matrix multiplication Av. Therefore, the image of the vector \( \mathbf{v} \) \( A\mathbf{v} = \begin{bmatrix} 0 & 1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 3 \ 4 \end{bmatrix} = \begin{bmatrix} 4 \ 3 \end{bmatrix} \). So the image of the vector \( \mathbf{v} \) under the transformation T is \( (4,3) \)
03

Sketch the graph

A sketch of vector \( \mathbf{v}=(3,4) \) would start at the origin and end at the point (3,4) and for its image (4,3), it would start at the origin and end at the point (4,3) in Euclidean plane.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Matrix
In linear algebra, the standard matrix provides a concrete representation of a linear transformation. When finding a standard matrix for a particular transformation, it captures how the transformation affects the unit basis vectors.

In the context of the exercise given, the linear transformation is a reflection transformation over the line defined by the equation \( y = x \). To determine the standard matrix \( A \), we check how the transformation \( T \) influences the standard unit vectors along the x and y axes, specifically \( (1,0) \) and \( (0,1) \).
  • Applying \( T \) to \( (1,0) \) results in \( (0,1) \)
  • Applying \( T \) to \( (0,1) \) results in \( (1,0) \)
This means that the standard matrix \( A \) reflects these basis vectors as columns:
\[ A = \begin{bmatrix} 0 & 1 \ 1 & 0 \end{bmatrix} \] Reflecting the function's properties, it switches the positions of the x and y components.
Reflection Transformation
A reflection transformation is a type of linear transformation that "flips" elements across a specified line or plane, keeping the respective distances constant. In two dimensions, reflecting across the line \( y = x \) swaps the coordinates of any point \( (x, y) \) into \( (y, x) \). This type of transformation keeps points equidistant from the line \( y = x \).

Here's how the process works in our specific example:
  • Our transformation function \( T(x, y) = (y, x) \) flips any two-dimensional vector along this line.
  • If an initial vector \( \mathbf{v} = (3, 4) \) is subjected to our transformation, it effectively swaps its x and y coordinates, yielding a new position at \( (4, 3) \).
This ensures symmetry with respect to the line \( y = x \), which is a critical feature of reflection transformations.
Vector Image
The vector image is the result of applying a linear transformation to an original vector. It provides a new vector where each component has transformed based on the rules set by the standard matrix. Understanding the vector image is essential for visualizing how transformations alter geometrical and algebraic properties of vectors.

In our context:
  • Original vector: \( \mathbf{v} = (3,4) \)
  • Standard matrix for transformation: \( A = \begin{bmatrix} 0 & 1 \ 1 & 0 \end{bmatrix} \)
  • Resulting vector image: after applying the transformation \( A\mathbf{v} = \begin{bmatrix} 4 \ 3 \end{bmatrix} \)
This illustrates how the initial vector \( \mathbf{v} \) gets repositioned within the plane, maintaining the geometric characteristics induced by the reflection.
Euclidean Plane
The Euclidean plane is the flat two-dimensional surface where geometry exists in linear algebra and is inhabited by vectors, lines, and shapes. It's characterized by its Cartesian coordinates which allow precise determination of geometrical entities’ positions.

In solving transformations:
  • The Euclidean plane acts as the foundation where transformations and vector operations occur.
  • Vectors, such as \( \mathbf{v} =(3,4) \), are points in this plane that can be moved, flipped, or scaled by transformations.
Visualizing the plane involves considering horizontal and vertical axes along which the vectors operate and transform. This aspect is critical when sketching both the original vectors and their transformed versions, helping to beautifully demonstrate the underlying principles of geometry through basic visual formats.

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Most popular questions from this chapter

use the matrix \(P\) to show that the matrices \(A\) and \(A^{\prime}\) are similar. $$ P=\left[\begin{array}{lll} 5 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 3 \end{array}\right], A=\left[\begin{array}{lll} 5 & 10 & 0 \\ 8 & 4 & 0 \\ 0 & 9 & 6 \end{array}\right], A^{\prime}=\left[\begin{array}{rrr} 5 & 8 & 0 \\\ 10 & 4 & 0 \\ 0 & 12 & 6 \end{array}\right] $$

Determine whether each statement is true or false. If a statement is true, give a reason or cite an appropriate statement from the text. If a statement is false, provide an example that shows the statement is not true in all cases or cite an appropriate statement from the text. (a) The function \(f(x)=\cos x\) is a linear transformation from \(R\) into \(R\). (b) For polynomials, the differential operator \(D_{x}\) is a linear transformation from \(P_{n}\) into \(P_{n-1}\).

Prove that \(T: V \rightarrow W\) is a linear transformation if and only if \(T(a \mathbf{u}+b \mathbf{v})=a T(\mathbf{u})+b T(\mathbf{v})\) for all vectors \(\mathbf{u}\) and \(\mathbf{v}\) and all scalars \(a\) and \(b\) Getting Started: This is an "if and only if" statement, so you need to prove the statement in both directions. To prove that \(T\) is a linear transformation, you need to show that the function satisfies the definition of a linear transformation. In the other direction, let \(T\) be a linear transformation. Use the definition and properties of a linear transformation to prove that \(T(a \mathbf{u}+b \mathbf{v})=a T(\mathbf{u})+b T(\mathbf{v})\). (i) Let \(T(a \mathbf{u}+b \mathbf{v})=a T(\mathbf{u})+b T(\mathbf{v}),\) Show that \(T\) preserves the properties of vector addition and scalar multiplication by choosing appropriate values of \(a\) and \(b\). (ii) To prove the statement in the other direction, assume that \(T\) is a linear transformation. Use the properties and definition of a linear transformation to show that \(T(a \mathbf{u}+b \mathbf{v})=a T(\mathbf{u})+b T(\mathbf{v})\).

use the matrix \(P\) to show that the matrices \(A\) and \(A^{\prime}\) are similar. $$ P=A=A^{\prime}=\left[\begin{array}{rr} 1 & -12 \\ 0 & 1 \end{array}\right] $$

let \(A\) be the matrix for \(T: R^{3} \rightarrow R^{3}\) relative to the standard basis. Find the diagonal matrix \(A^{\prime}\) for \(T\) relative to the basis \(B^{\prime}\) $$ \begin{aligned} &A=\left[\begin{array}{rrr} \frac{3}{2} & -1 & -\frac{1}{2} \\\ -\frac{1}{2} & 2 & \frac{1}{2} \\ \frac{1}{2} & 1 & \frac{5}{2} \end{array}\right]\\\ &B^{\prime}=\\{(1,1,-1),(1,-1,1),(-1,1,1)\\} \end{aligned} $$

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