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use the matrix \(P\) to show that the matrices \(A\) and \(A^{\prime}\) are similar. $$ P=A=A^{\prime}=\left[\begin{array}{rr} 1 & -12 \\ 0 & 1 \end{array}\right] $$

Short Answer

Expert verified
From the computations, it is apparent that the matrices \(A\) and \(A^{\prime}\) are similar as given that \(A^{\prime} = P^{-1}AP\).

Step by step solution

01

Find the Inverse of \(P\)

Since \(P = A = A^{\prime} = \left[\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}\right]\), we can solve for its inverse. For a 2x2 matrix \(\left[\begin{array}{cc} a & b \ c & d \end{array}\right]\), the inverse can be found using the formula \(\frac{1}{ad-bc}\left[\begin{array}{cc} d & -b \ -c & a \end{array}\right]\). Given that \(a = d = 1\) and \(b = c = -12\), then the denominator \(ad - bc = 1 * 1 - (-12 * 0) = 1\). Hence the inverse \(P^{-1} = \left[\begin{array}{cc} 1 & 12 \ 0 & 1 \end{array}\right]\)
02

Compute \(P^{-1}AP\).

To compute \(P^{-1}AP\), first compute the product \(AP = \left[\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}\right]\left[\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}\right] = \left[\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}\right]\). Then, compute \(P^{-1}AP = \left[\begin{array}{cc} 1 & 12 \ 0 & 1 \end{array}\right]\left[\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}\right] = \left[\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}\right]\) which is equal to \(A^{\prime}\).
03

Comparison.

Compare the results of \(P^{-1}AP = A^{\prime}\) and \(A^{\prime} = A\) to check if they're equal. Since both results are the same, and \(A = A^{\prime}\), we can conclude that the matrices \(A\) and \(A^{\prime}\) are similar.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse of a Matrix
When discussing matrices, one important concept is the inverse of a matrix. Just like inverses in arithmetic balance out numbers by bringing them back to their original value, the inverse of a matrix is used in similar ways for matrices.

An important point to remember is that not all matrices have inverses. For a square matrix, having a non-zero determinant is a requirement for the existence of an inverse. Inverse of a 2x2 matrix
  • Take a 2x2 matrix \[ \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \]
  • Its inverse is given by \[ \frac{1}{ad-bc}\left[ \begin{array}{cc} d & -b \ -c & a \end{array} \right] \]
  • The term \( ad - bc \) is called the determinant of the matrix.
In the example exercise, for the matrix \( P \) which is \([\begin{array}{cc} 1 & -12 \ 0 & 1 \end{array}]\), the determinant is \(1\), thus the inverse \( P^{-1} = \left[\begin{array}{cc} 1 & 12 \ 0 & 1 \end{array}\right] \).
Matrix Multiplication
Matrix multiplication is a fundamental operation among matrices. Unlike regular multiplication which is commutative, meaning the order doesn't impact the result, matrix multiplication isn't. The order in which you multiply matrices matters.
  • To multiply two matrices, say \( A \) and \( B \), the number of columns in \( A \) must equal the number of rows in \( B \).
  • Each element of the resultant matrix is computed as the dot product of corresponding row from the first matrix and column from the second matrix.
In mathematical terms:
For two 2x2 matrices \( \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \) and \( \left[ \begin{array}{cc} e & f \ g & h \end{array} \right] \), the product is:
\[\left[ \begin{array}{cc} ae+bg & af+bh \ ce+dg & cf+dh \end{array} \right]\]Thus, for any exercise involving matrix multiplication, pay special attention to the dimensions and the order to compute the correct result. In our exercise, both \( P^{-1}AP \) and \( A' \) were calculated using this process.
2x2 Matrices
2x2 matrices are a simpler and more manageable form of larger matrix operations, relevant in educational contexts and basic applications. They're often used because they still illustrate a lot of the interesting properties of larger matrices, or when particular dimensions fit the application.

  • For instance, they can represent linear transformations in two-dimensional space, like rotations or reflections.
  • Their determinant, applicable for obtaining inverses and assessing solvability, is calculated as \( ad-bc \) for a matrix \( \left[\begin{array}{cc} a & b \ c & d \end{array}\right]\).
Because of this small size and simplicity, they are regularly used as a teaching tool to introduce core concepts like inverses, eigenvalues, and similarity in linear algebra.
So, while 2x2 matrices serve as a good starting ground, the techniques and concepts apply across matrices of any size.

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