Chapter 4: Problem 47
Identify and sketch the graph. $$x^{2}+4 y^{2}+4 x+32 y+64=0$$
Short Answer
Expert verified
The equation represents an ellipse centered at (-2, -4) with a semi-major axis of length 2 and a semi-minor axis of length 1. The sketch would show an oval shape wider along the x-axis.
Step by step solution
01
Rearrange into Standard Form of Ellipse
The standard form of an ellipse is \((x-h)^2/a^2 + (y-k)^2/b^2 = 1\), where \((h,k)\) is the center and \(a\) and \(b\) are the lengths of the semi-major axis and semi-minor axis respectively.\n To get this form we first need to group the \(x\) and \(y\) terms separately in the equation: \[(x^2+4x) + (4y^2+32y) = -64\] Then, complete the square for the \(x\) and \(y\) groups: \[(x^2+4x+4) + 4(y^2+8y+16) = -64+4+64\] This gives: \[(x+2)^2 + 4(y+4)^2 = 4\] Simplify by dividing through by 4: \[(x+2)^2/4 + (y+4)^2=1\].
02
Identify Parameters for Sketching
From the standard form of the ellipse, we identify the following:\n - The center of ellipse is at (-2, -4)\n - The semi-major axis has length 2\n - The semi-minor axis has length 1.
03
Sketch the Ellipse
On a graph, mark the center at (-2, -4). Draw the semi-major axis 2 units to the right and left of the center, and draw the semi-minor axis 1 unit above and below the center. Then sketch the ellipse.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form of Ellipse
The standard form of an ellipse equation is \[\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\]where:
- \((h, k)\) is the center of the ellipse,
- \(a\) is the semi-major axis length,
- \(b\) is the semi-minor axis length.
Completing the Square
Completing the square is a mathematical process used to transform a quadratic expression into a perfect square trinomial.This step is crucial in rewriting the given ellipse equation into its standard form.In the example given, we started with:\[x^2 + 4y^2 + 4x + 32y + 64 = 0\]First, group the terms with the same variables:
- \((x^2 + 4x)\)
- \((4y^2 + 32y)\)
Graphing Ellipses
Graphing an ellipse from its standard form can be straightforward.First, determine the center of the ellipse from the equation.In our case, the equation was transformed into:\[\frac{(x+2)^2}{4} + (y+4)^2 = 1\]From this, the center is at \((-2, -4)\).Identify the lengths of the semi-major and semi-minor axes:
- Semi-major axis \(a = 2\)
- Semi-minor axis \(b = 1\)
- Start at the center.
- Move \(a\) units along the x-axis both left and right.
- Move \(b\) units along the y-axis both up and down.
Equation Transformation
Transforming an equation into the standard form of an ellipse is a critical step.The initial equation is often not in a form that's easy to interpret.For example, we started from:\[x^2 + 4y^2 + 4x + 32y + 64 = 0\]The transformation starts by grouping terms to focus on each variable separately.Then, through completing the square, we reformed the separate group equations into perfect squares.Such as transforming \(x^2 + 4x\) into \((x+2)^2\).Once added to the equivalent expression for \(y\) and factoring out coefficients, you’re ready to convert to standard form by scaling.Finally, place it into the form:\[\frac{(x+2)^2}{4} + \frac{(y+4)^2}{1} = 1\]Understanding these steps helps solidify your grasp on ellipse equations.Mastering this lets you switch between forms and interpret characteristics quickly.