Chapter 4: Problem 47
Determine whether \(S\) is a basis for \(P_{3}\) $$S=\left\\{4-t, t^{3}, 6 t^{2}, t^{3}+3 t, 4 t-1\right\\}$$
Short Answer
Expert verified
No, \(S\) is not a basis for \(P_{3}\) as it fails to span \(P_{3}\).
Step by step solution
01
Check for linear independence
Represent the set of vectors using augmented matrix and perform Gaussian Elimination: \[ \begin{bmatrix} -1 & 0 & 0 & 0 & 4 \ 0 & 1 & 6 & 1 & 0 \ 0 & 0 & 0 & 3 & 0 \ 4 & 0 & 0 & 0 & -1 \end{bmatrix} \]. After Gaussian Elimination, we get the reduced row echelon form as: \[ \begin{bmatrix} 1 & 0 & 0 & 0 & -4 \ 0 & 1 & 0 & 0 & 0 \ 0 & 0 & 1 & 0 & 0 \ 0 & 0 & 0 & 1 & 0 \end{bmatrix} \]. Here the system has only trivial solutions, hence, the vectors are linearly independent.
02
Check if the vectors span \(P_{3}\)
\(\)The vector space \(P_{3}\) has a dimension of 4 (polynomials of degree 3 or less), but S is a set of 5 vectors. It is impossible for 5 vectors to form a basis in a 4-dimensional vector space. Therefore, S does not span \(P_{3}\).
03
Formulate an answer
From Step 1, the vectors in S are linearly independent; however, from Step 2, S does not span \(P_{3}\). Therefore, S cannot be a basis for \(P_{3}\) as a basis has to both span and be linearly independent.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Basis for Vector Space
A basis for a vector space is a set of vectors that serves as the "building blocks" for that space. In other words, each vector in the space can be expressed as a linear combination of the basis vectors. The key properties of a basis are that it must span the vector space and be linearly independent. If we can take a set of vectors and combine them in various ways to get any possible vector from the vector space, while ensuring no redundant vectors, we have a basis. For example, the standard basis for a 3-dimensional Euclidean space (\(\mathbb{R}^3\)) consists of \(\{(1,0,0), (0,1,0), (0,0,1)\}\).
- Spanning: Means that any vector in the space can be formed by a combination of basis vectors.
- Linear independence: No vector in the basis can be created by combining others from the set.
Linear Independence
Linear independence is a crucial concept in determining the basis of a vector space. A set of vectors is said to be linearly independent if no vector in the set is a linear combination of the others. In simpler terms, each vector adds new information or a dimension to the set. For linearly independent vectors, the mathematical condition is: \[c_1\mathbf{v}_1 + c_2\mathbf{v}_2 + \ldots + c_n\mathbf{v}_n = \mathbf{0}\] implies \(c_1 = c_2 = \ldots = c_n = 0\).
- This means the only way to sum these vectors to get the zero vector is to have all the coefficients equal to zero.
- This concept ensures that none of the vectors can be expressed as scaling (multiplying by a constant) and/or adding up the others.
Dimension of Vector Space
The dimension of a vector space is an integer that represents the number of vectors it takes to span that space, meaning the minimum number of vectors needed to form a basis. It's an essence of the vector space that highlights how many directions it extends.
- For example, a 2-dimensional plane in \(\mathbb{R}^3\) is spanned by exactly two vectors, showing it is two-dimensional.
- For polynomial space like \(P_3\) (polynomials of degree 3 or less), the dimension is 4 because the basis sets feature constants, \(t\), \(t^2\), and \(t^3\), yielding four independent directions.
Gaussian Elimination
Gaussian elimination is a method used to solve systems of linear equations. It is especially useful in linear algebra for transforming a set of vectors into an easier-to-manage form, such as reduced row echelon form (RREF). It systematically performs row operations to simplify a matrix. These operations include:
- Row switching: Swap the positions of two rows.
- Row multiplication: Multiply all elements in a row by a nonzero scalar.
- Row addition: Add or subtract the multiples of rows from each other to form zeros in crucial positions.