Chapter 23: Problem 7
In each exercise, obtain the Fourier cosine series for the given function over the stipulated interval and sketch the function to which the series converges. $$ \begin{aligned} \text { Interval, } 0< x< 1 ; \text { function, } f(x) &=0, & & 0< x< \frac{1}{2}, \\ &=x-\frac{1}{2}, & & \frac{1}{2}< x< 1 \end{aligned} $$
Short Answer
Step by step solution
Recognize Problem Requirements
Express the Function in a More Convenient Form
Identify Fourier Cosine Series Components
Calculate Coefficients \(a_0\) and \(a_n\)
Form the Fourier Cosine Series
Sketch the Function
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Function
Here, the function is specified as:
- For the range \( 0 < x < \frac{1}{2} \), the function \( f(x) \) equals 0.
- For the range \( \frac{1}{2} < x < 1 \), the function transforms into \( f(x) = x - \frac{1}{2} \).
Interval Analysis
In this exercise, we engage with the interval \( 0 < x < 1 \). The function acts differently within two sub-intervals:
- First interval: \( 0 < x < \frac{1}{2} \), where \( f(x) = 0 \).
- Second interval: \( \frac{1}{2} < x < 1 \), where \( f(x) = x - \frac{1}{2} \).
Fourier Coefficients
Let's look into our example:
- \( a_0 \) is calculated using the formula: \( a_0 = \frac{2}{L} \int_0^L f(x) \, dx \), with \( L = 1 \). Here, we find \( a_0 = 1 \).
- \( a_n \) is computed as follows: \( a_n = \frac{2}{L} \int_0^L f(x) \cos\left(\frac{n\pi x}{L}\right) \, dx \). In this specific piecewise function, \( a_n \) is zero for all \( n \geq 1 \), rendering the series heavily dependent on the constant term.
Function Sketching
In this given problem, we first illustrate the piecewise function across the interval \(0 < x < 1\):
- From \(0 \) to \(\frac{1}{2}\), the function holds constant at zero.
- From \(\frac{1}{2} \) to 1, it draws a straight line with the formula \( f(x) = x - \frac{1}{2} \), sloping upwards.
By sketching both, one can easily understand how the Fourier series approximates the piecewise function by smoothing it into a single constant value across the whole interval. This visualization aids in grasping not only the behavior of the original function but also the impact of applying the Fourier cosine series.