Chapter 23: Problem 6
In each exercise, obtain the Fourier cosine series for the given function over the stipulated interval and sketch the function to which the series converges. $$ \begin{aligned} \text { Interval, } 0< x<1 ; \text { function, } f(x) &=0, & 0< x< \frac{1}{2}, \\ &=1, & \frac{1}{2}< x< 1 . \end{aligned} $$
Short Answer
Step by step solution
Set up the Fourier cosine series formula
Compute the constant term a_0
Compute the cosine coefficients a_n
Write down the Fourier cosine series
Sketch the function and the series convergence
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Functions
- For the interval \( 0 < x < \frac{1}{2} \), the function \( f(x) \) is equal to 0.
- For the interval \( \frac{1}{2} < x < 1 \), \( f(x) \) is equal to 1.
Interval Analysis
- From \( 0 < x < \frac{1}{2} \); the function does not change and remains constant at 0.
- From \( \frac{1}{2} < x < 1 \); the function jumps to a constant value of 1.
Fourier Coefficients Calculation
- The constant term \( a_0 \) which is the average value of the function over its entire interval. For our piecewise function, it is computed as \( a_0 = \frac{1}{2} \).
- The coefficients \( a_n \), which need a more detailed integral calculation through the formula: \[ a_n = 2 \int_{0}^{1} f(x) \cos(n\pi x) \, dx \]By computing individually from \( \frac{1}{2} \) to 1, since \( f(x) = 0\) for the first part, \( a_n \) were determined as \( \frac{2(-1)^{n+1}}{n\pi} \).