Chapter 9: Problem 14
Complete each rule for exponents. $$ \frac{1}{x^{-m / n}}= \square $$
Short Answer
Expert verified
\(\frac{1}{x^{-m/n}} = x^{m/n}\).
Step by step solution
01
Recall the Negative Exponent Rule
The negative exponent rule states that a negative exponent indicates a reciprocal. Specifically, for any non-zero number \(a\) and any integer \(n\), \(a^{-n} = \frac{1}{a^n}\). In our problem, the exponent is \(-\frac{m}{n}\).
02
Convert the Negative Exponent
Apply the negative exponent rule to \(x^{-m/n}\). According to the rule, \(x^{-m/n} = \frac{1}{x^{m/n}}\).
03
Find the Reciprocal
Since \( \frac{1}{x^{-m/n}} \) is the expression we started with, we need to find the reciprocal of \(x^{-m/n}\). Based on Step 2, the reciprocal of \(x^{-m/n}\) is \(x^{m/n}\).
04
Verify the Solution
The expression \(\frac{1}{x^{-m/n}} = x^{m/n}\) can be verified by substituting back and ensuring both sides are equivalent. This confirms that the rule for the negative exponent is correctly applied.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Negative Exponent Rule
The negative exponent rule is a fundamental concept in the world of exponents. When you see an exponent that is negative, it's a signal to take the reciprocal of the base. This means you "flip" the base from the numerator to the denominator or vice versa. For example, any non-zero number \(a\) with a negative exponent \(-n\) can be expressed as \(a^{-n} = \frac{1}{a^n}\).
To understand why this works, imagine that negative exponents are like reminders to undo multiplication. So, when you have a number multiplied by itself "negative" times, you actually need to divide.
To understand why this works, imagine that negative exponents are like reminders to undo multiplication. So, when you have a number multiplied by itself "negative" times, you actually need to divide.
- Example: \(3^{-2} = \frac{1}{3^2} = \frac{1}{9}\)
- As another illustration: \(x^{-1} = \frac{1}{x}\)
Reciprocal
A reciprocal is what you get when you flip a fraction. If the original number is \(x\), its reciprocal is \(\frac{1}{x}\). This concept is tightly woven into the fabric of exponent rules, especially when dealing with negatives. When you encounter a negative exponent, you essentially need the reciprocal of the base.
This flipping mechanism is like a two-way street. If you begin with \(\frac{1}{x}\), the reciprocal is \(x\).
This flipping mechanism is like a two-way street. If you begin with \(\frac{1}{x}\), the reciprocal is \(x\).
- For instance, the reciprocal of \(5\) is \(\frac{1}{5}\).
- If you start with \(\frac{1}{4}\), its reciprocal is \(4\).
Rational Exponents
Rational exponents are another interesting concept to unravel. When the exponent is a fraction, like \(\frac{m}{n}\), it indicates both rooting and raising to a power simultaneously. The number \(m\) in the fraction \(\frac{m}{n}\) serves to raise the base to a power, while \(n\) denotes the root.
This means \(x^{\frac{m}{n}}\) is equivalent to taking the \(n\)-th root of \(x\) and then raising it to the \(m\)-th power. Alternatively, it can mean raising \(x\) to the \(m\)-th power first and then finding the \(n\)-th root.
This means \(x^{\frac{m}{n}}\) is equivalent to taking the \(n\)-th root of \(x\) and then raising it to the \(m\)-th power. Alternatively, it can mean raising \(x\) to the \(m\)-th power first and then finding the \(n\)-th root.
- For example: \(x^{\frac{1}{2}}\) is the square root of \(x\), and \(x^{\frac{3}{2}}\) can be seen as \(\sqrt{x^3}\) or \((\sqrt{x})^3\).
- Another way: \(x^{\frac{2}{3}}\) can be \((\sqrt[3]{x})^2\) or \(\sqrt[3]{x^2}\).