Chapter 9: Problem 120
$$ \text { a. } \sqrt{-64} \text { b. } \sqrt[3]{-64} $$
Short Answer
Expert verified
a. \( 8i \); b. \( -4 \).
Step by step solution
01
Understanding Square Roots of Negative Numbers
When dealing with the square root of a negative number, recognize that the square root of any negative number requires the use of imaginary numbers. The imaginary unit is represented as \( i \), where \( i = \sqrt{-1} \). This allows us to rewrite \( \sqrt{-64} \) as \( \sqrt{64} \times \sqrt{-1} \).
02
Simplifying \( \sqrt{-64} \) Using Imaginary Numbers
Calculate \( \sqrt{64} \), which is 8. Since \( \sqrt{-1} = i \), we can express \( \sqrt{-64} \) as \( 8i \).
03
Understanding Cube Roots of Negative Numbers
Cube roots of negative numbers are real numbers. This is because multiplying a negative number by itself twice results in a positive number, and multiplying again by the same negative number results in a negative number. For instance, calculate \( (-a)^3 = -a^3 \).
04
Calculating \( \sqrt[3]{-64} \)
We need to find a number \( x \) such that \( x^3 = -64 \). Since \( (-4)^3 = -64 \), it follows that \( \sqrt[3]{-64} = -4 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Roots of Negative Numbers
When faced with the square root of a negative number, it's important to remember that standard real numbers don't apply. In the field of mathematics, the square root of a negative number would not exist without the concept of imaginary numbers. For example, trying to directly solve \( \sqrt{-64} \) using only positive or negative real numbers will lead to confusion.
Imaginary numbers offer a solution by introducing a new component denoted by the imaginary unit \( i \), where \( i = \sqrt{-1} \). So, when tackling \( \sqrt{-64} \), you first break it down into \( \sqrt{64} \) and \( \sqrt{-1} \).
Here's how it works:
Imaginary numbers offer a solution by introducing a new component denoted by the imaginary unit \( i \), where \( i = \sqrt{-1} \). So, when tackling \( \sqrt{-64} \), you first break it down into \( \sqrt{64} \) and \( \sqrt{-1} \).
Here's how it works:
- Find \( \sqrt{64} \), which is a straightforward 8. This part remains a real number.
- Recognize \( \sqrt{-1} \) as the imaginary unit \( i \).
- Combine them to express the square root of the negative number: \( \sqrt{-64} = 8i \).
Cube Roots of Negative Numbers
Unlike the square roots, cube roots of negative numbers remain within the real number system. This is because a negative number, when cubed, cycles through positive and negative intermediate results, ultimately returning to a negative result.
To solve \( \sqrt[3]{-64} \), we need to find a real number that, when cubed, equals the original negative value. Interestingly, multiplying three wholes of a negative number yields a negative outcome:
To solve \( \sqrt[3]{-64} \), we need to find a real number that, when cubed, equals the original negative value. Interestingly, multiplying three wholes of a negative number yields a negative outcome:
- Calculate the cube root of \(-64\) by determining which number cubed will equal \(-64\).
- Notice that \((-4)^3 = -64\), through the operation: \((-4) \times (-4) \times (-4)\) results in \(-64\).
Imaginary Unit i
The imaginary unit, denoted as \( i \), is a mathematical construct that allows us to extend our number system beyond the real numbers and tackle equations that otherwise would have no real solution.
By definition, \( i \) is equal to the square root of \(-1\) or \( i = \sqrt{-1} \). This might seem abstract at first, but it holds a specific purpose: to simplify the square roots of negative numbers where typical operations break down.
By definition, \( i \) is equal to the square root of \(-1\) or \( i = \sqrt{-1} \). This might seem abstract at first, but it holds a specific purpose: to simplify the square roots of negative numbers where typical operations break down.
- Using \( i \), complex numbers are formed as a combination of real numbers and imaginary numbers, e.g., \( a + bi \).
- This can be quite useful in engineering, physics, and other disciplines where variables may oscillate between states.