Chapter 3: Problem 48
Use the intercept method to graph each equation. $$ 4 x+3 y=0 $$
Short Answer
Expert verified
The graph of the equation \(4x + 3y = 0\) is a line passing through the origin \((0,0)\).
Step by step solution
01
Understand the Equation
The equation given is in the form of a standard linear equation, which is \(4x + 3y = 0\). To use the intercept method, we need to find the x-intercept and the y-intercept.
02
Find the X-Intercept
The x-intercept occurs when \(y = 0\). Substitute \(y = 0\) into the equation and solve for \(x\): \[4x + 3(0) = 0\] \[4x = 0\] \[x = 0\] Hence, the x-intercept is at \((0,0)\).
03
Find the Y-Intercept
The y-intercept occurs when \(x = 0\). Substitute \(x = 0\) into the equation and solve for \(y\): \[4(0) + 3y = 0\] \[3y = 0\] \[y = 0\]Hence, the y-intercept is also at \((0,0)\).
04
Plot the Intercepts
Plot the intercepts on a coordinate plane. Since both the x-intercept and y-intercept are at \((0,0)\), the line passes through the origin.
05
Draw the Line
Draw a straight line through the point \((0,0)\). Since the equation is homogenous, it directly passes through the origin, making it the same point for both intercepts.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
graphing linear equations
Graphing linear equations is a fundamental skill in mathematics that allows us to visualize relationships between variables. A linear equation forms a straight line when plotted on a coordinate plane. The general form of a linear equation is \( ax + by = c \). In this format, \( a \), \( b \), and \( c \) are real numbers, and \( x \) and \( y \) are variables.
To graph a linear equation using the intercept method, you typically need to find two points - the x-intercept and the y-intercept. Once these intercepts are plotted, you can draw a line through them to represent the equation.
To graph a linear equation using the intercept method, you typically need to find two points - the x-intercept and the y-intercept. Once these intercepts are plotted, you can draw a line through them to represent the equation.
- The slope of the line is the ratio of the change in \( y \) to the change in \( x \). If the slope is positive, the line rises from left to right; if negative, it falls.
- In the given equation \( 4x + 3y = 0 \), notice that both intercepts are at the same point, the origin \((0, 0)\).
x-intercept
The x-intercept is the point where a graph crosses the x-axis. At this intersection, the value of \( y \) is always zero. This point is crucial because it helps establish where the line "hits" or "intersects" the x-axis.
To find the x-intercept, set \( y = 0 \) and solve for \( x \). For the equation \( 4x + 3y = 0 \), substitute \( y = 0 \) to get:
In most linear equations, the x-intercept will not be the same as the y-intercept. However, in this special case where the equation passes through the origin, they coincide. This means the line directly passes through the origin without any shifts along the axes.
To find the x-intercept, set \( y = 0 \) and solve for \( x \). For the equation \( 4x + 3y = 0 \), substitute \( y = 0 \) to get:
- \(4x + 3(0) = 0\)
- \(4x = 0\)
- \(x = 0\)
In most linear equations, the x-intercept will not be the same as the y-intercept. However, in this special case where the equation passes through the origin, they coincide. This means the line directly passes through the origin without any shifts along the axes.
y-intercept
The y-intercept is where the graph crosses the y-axis. At this point, the value of \( x \) is always zero. Understanding the y-intercept gives insight into where a line begins on the y-axis if extended across the coordinate plane.
Finding the y-intercept involves setting \( x = 0 \) and solving for \( y \). In the equation \( 4x + 3y = 0 \), replace \( x = 0 \) to get:
This unique situation, where both intercepts are at the origin, shows that the line does not move away from the origin. In general, the y-intercept helps define the starting point of the line on the y-axis in many linear representations. However, in this case, the origin is the starting point for both intercepts.
Finding the y-intercept involves setting \( x = 0 \) and solving for \( y \). In the equation \( 4x + 3y = 0 \), replace \( x = 0 \) to get:
- \(4(0) + 3y = 0\)
- \(3y = 0\)
- \(y = 0\)
This unique situation, where both intercepts are at the origin, shows that the line does not move away from the origin. In general, the y-intercept helps define the starting point of the line on the y-axis in many linear representations. However, in this case, the origin is the starting point for both intercepts.