Chapter 3: Problem 48
Solve \(5(x+1) \leq 2(x-3) .\) Write the solution set in interval notation and graph it.
Short Answer
Expert verified
The solution set is \((-\infty, \frac{-11}{3}]\).
Step by step solution
01
Distribute Terms
Distribute the constants outside the parentheses on both sides of the inequality: For the left side: \[ 5(x+1) = 5x + 5 \]For the right side: \[ 2(x-3) = 2x - 6 \]
02
Formulate the Inequality
Substitute the distributed expressions back into the inequality: \[ 5x + 5 \leq 2x - 6 \]
03
Isolate the Variable
Subtract \(2x\) from both sides to bring the terms involving \(x\) to one side: \[ 5x - 2x + 5 \leq -6 \]This simplifies to:\[ 3x + 5 \leq -6 \]Now, subtract 5 from both sides:\[ 3x \leq -11 \]
04
Solve for x
Divide each side of the inequality by 3 to solve for \(x\):\[ x \leq \frac{-11}{3} \]
05
Write the Solution in Interval Notation
The solution \( x \leq \frac{-11}{3} \) can be written in interval notation as:\[ (-\infty, \frac{-11}{3}] \]
06
Graph the Solution Set
To graph the solution set, draw a number line and shade the region to the left of \(\frac{-11}{3}\). Place a closed circle at \(\frac{-11}{3}\) to indicate that \(\frac{-11}{3}\) is included in the solution set.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation provides a concise way to express a range of values. It is especially useful in inequalities where the solution is not just a single number but a set of numbers. For example, when we solve the inequality \( x \leq \frac{-11}{3} \), it indicates that \( x \) can be any number less than or equal to \( \frac{-11}{3} \). Here is how interval notation comes into play:
- If a number is included in the solution set, it is represented with a square bracket \([ ) or ( ]\).
- If a number is *not* included, it is represented with a parenthesis \(( ) or )\).
- An infinity symbol \( \infty \) represents unbounded intervals.
Graphing Solutions
Graphing solutions to inequalities helps in visualizing the range of possible values for a variable. For the inequality \( x \leq \frac{-11}{3} \), start by drawing a number line.Here’s how to graph the solution step-by-step:
- Identify the point \( \frac{-11}{3} \) on the number line. This is your critical value.
- Place a closed circle at \( \frac{-11}{3} \) because the inequality includes this number. A closed circle means "including" the point.
- Shade the number line to the left of \( \frac{-11}{3} \) to indicate that all numbers less than \( \frac{-11}{3} \) are part of the solution set.
Distributive Property
The distributive property is a key concept for solving equations and inequalities efficiently. It allows you to multiply a single term by each term inside a parenthesis. In our exercise, we used the distributive property to expand the expressions \( 5(x+1) \) and \( 2(x-3) \).Here’s how the distributive property works:
- Multiply the term outside the parenthesis by each term within the parenthesis.
- For \( 5(x+1) \): Distribute the \( 5 \) as \( 5 \times x + 5 \times 1 = 5x + 5 \).
- For \( 2(x-3) \): Distribute the \( 2 \) as \( 2 \times x + 2 \times (-3) = 2x - 6 \).