91Ó°ÊÓ

Graph equation. Solve for \(y\) first, when necessary. \(7 x-y=1\)

Use either the slope-intercept form (from Section 3.5) or the point-slope form (from Section 3.6) to find an equation of each line. Write each result in slope-intercept form, if possible. Slope \(1.7, y\) -intercept \((0,-2.8)\)

Determine whether the lines through each pair of points are parallel, perpendicular, or neither. See Example 8. \((-4,-2)\) and \((2,-3)\) \((7,1)\) and \((8,7)\)

Use either the slope-intercept form (from Section 3.5) or the point-slope form (from Section 3.6) to find an equation of each line. Write each result in slope-intercept form, if possible. Slope \(9.5, y\) -intercept \((0,-14.3)\)

For each pair of equations, determine whether their graphs are parallel, perpendicular, or neither. See Example 6 $$ \begin{aligned} &y=-9 x-3\\\ &y=-9 x \end{aligned} $$

In your own words, what is a function?

Determine whether the lines through each pair of points are parallel, perpendicular, or neither. See Example 8. \((-2,4)\) and \((6,-7)\) \((-6,4)\) and \((5,12)\)

Graph equation. Solve for \(y\) first, when necessary. \(2 x-y=-3\)

Graph each equation. $$ x=50-5 y $$

A dentist's office schedules 1 -hour long appointments for adults and \(\frac{3}{4}\) -hour long appointments for children. The appointment times do not overlap. Let \(c\) represent the number of appointments scheduled for children and a represent the number of appointments scheduled for adults. The graph of \(\frac{3}{4} c+a \leq 9\) shows the possible ways the time for seeing patients can be scheduled so that it does not exceed 9 hours per day. Graph the inequality. Label the horizontal axis \(c\) and the vertical axis \(a .\) Then find three possible combinations of children/adult appointments.