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91Ó°ÊÓ

Find \(f(x)\) and \(g(x)\) such that \(h(x)=(f \circ g)(x) .\) Answers may vary. $$ h(x)=x^{5}+9 $$

Short Answer

Expert verified
One possible solution is \(f(x) = x^5 + 9\) and \(g(x) = x\).

Step by step solution

01

Understand the Composition Function

The problem asks for two functions, \(f(x)\) and \(g(x)\), such that the composition \((f \circ g)(x)\) equals \(h(x) = x^5 + 9\). This requires finding functions where applying \(g(x)\) first and then \(f(x)\) gives us \(h(x)\).
02

Choose a Simple Function for g(x)

To simplify the problem, we can choose \(g(x)\) as a straightforward identity or linear function of \(x^n\). A reasonable choice is \(g(x) = x \), so we are effectively looking for an \(f(x)\) that directly produces \(h(x)\).
03

Determine Function f(x)

Given \(g(x) = x\), we substitute \(x\) into \(f(x)\), leading to \(f(g(x)) = f(x) = x^5 + 9\). Thus, we choose \(f(x) = x^5 + 9 \) because this function, when applied to \(g(x) = x\), reproduces \(h(x)\).
04

Verification

Verify the chosen functions by calculating \( (f \circ g)(x) = f(g(x)) = f(x)\). Since we selected \(f(x) = x^5 + 9\) and \(g(x) = x\), we find \((f \circ g)(x) = (x^5 + 9) = h(x) \). This confirms our functions correctly match the original \(h(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Polynomial Functions
Polynomial functions are a key concept in algebra. They are expressions consisting of variables and coefficients, involving only operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.
For example, a typical polynomial function may look like this:
\[ P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0 \]
  • Exponents: Only whole numbers are allowed as exponents in polynomial functions.
  • Coefficients: These are the numerical factors before each term, such as \(a_n, a_{n-1}, \) etc.
  • Terms: Each part of the polynomial such as \(a_nx^n\) is known as a term.

Polynomial functions can be as simple as \(x + 1\), or complex like our function \(h(x) = x^5 + 9\). Each has a degree determined by the highest exponent, which in this case is 5. This means \(h(x)\) is a 5th-degree polynomial.
Exploring Function Decomposition
Function decomposition is the process of breaking down a complex function into simpler component functions. A function like \(h(x) = (f \circ g)(x)\) means we apply the function \(g(x)\) first, and then apply the function \(f(x)\).

Why Decompose Functions?

- **Simplification:** It helps simplify complex functions by analyzing smaller parts.
- **Insight:** Gives insights into the behavior and transformation of functions.
In our example, we want to find \(f(x)\) and \(g(x)\) such that their composition equals \(h(x) = x^5 + 9\). By selecting \(g(x) = x\), we are saying "apply \(g\) and change nothing about \(x\)." This allows us to focus on defining \(f(x)\) as the polynomial \(x^5 + 9\).
Understanding Algebraic Expressions
Algebraic expressions form the building blocks for both polynomial functions and composition. These expressions consist of variables, coefficients, and operational symbols like \(+\), \(-\), \(\times\), and division.
- **Variables:** Symbols like \(x\), representing unknown quantities.
- **Coefficients:** Numbers attached to variables, such as in \(5x\).
- **Constants:** Standalone numbers, like 9 in our function \(h(x) = x^5 + 9\).
Algebraic expressions can be combined through function composition. In our problem, by combining expressions \(f(x)\) and \(g(x)\) via composition, we mold \(h(x)\) in a way that characterizes both polynomial structure and algebraic manipulation. This highlights the versatile nature of algebraic expressions.

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