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Radioactive Decay. In 2 years, \(20 \%\) of a radioactive element decays. Find its half-life.

Short Answer

Expert verified
The half-life of the element is approximately 6.2 years.

Step by step solution

01

Understand Radioactive Decay

The decay of a radioactive element can be modeled using the formula \( N(t) = N_0 e^{-kt} \), where \( N(t) \) is the amount of substance remaining at time \( t \), \( N_0 \) is the initial amount of substance, \( k \) is the decay constant, and \( t \) is time. The half-life is the time it takes for half of the material to decay.
02

Set Up the Equation for Remaining Substance

Given that 20% of the element decays in 2 years, this means 80% remains. Set up the equation: \( 0.8N_0 = N_0 e^{-2k} \).
03

Simplify the Equation

Cancel \( N_0 \) from both sides: \( 0.8 = e^{-2k} \). Take the natural logarithm of both sides to solve for \( k \): \( \ln(0.8) = -2k \).
04

Solve for the Decay Constant \( k \)

Solve for \( k \) by dividing both sides by -2: \( k = -\frac{\ln(0.8)}{2} \). Calculate \( k \) using \( \ln(0.8) \approx -0.2231 \): \( k \approx \frac{0.2231}{2} \approx 0.11155 \).
05

Determine Half-life from \( k \)

The formula for half-life \( T_{1/2} \) is \( T_{1/2} = \frac{\ln(2)}{k} \). Substituting \( k \approx 0.11155 \) gives \( T_{1/2} = \frac{\ln(2)}{0.11155} \). Calculate \( \ln(2) \approx 0.6931 \) and then: \( T_{1/2} \approx \frac{0.6931}{0.11155} \approx 6.2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life
When we talk about half-life, it refers to the time required for half of a substance to undergo a process of decay. In the context of radioactive decay, this concept becomes particularly relevant. The half-life of a radioactive element is the period it takes for half of any given amount of the element to break down. Each radioactive substance has a unique half-life, which is constant and unaffected by external factors like temperature or pressure.

To find the half-life, we often use the decay constant, denoted by the symbol "\(k\)". The half-life \(T_{1/2}\) is given by the formula \(T_{1/2} = \frac{\ln(2)}{k}\). This formula is derived from the exponential decay process and the nature of logarithms. Understanding half-life helps predict how quickly a radioactive sample will diminish over time.
Exponential Decay Formula
Exponential decay occurs when a quantity decreases at a rate proportional to its current value. The general exponential decay formula is expressed as \(N(t) = N_0 e^{-kt}\). Here, \(N(t)\) represents the remaining quantity of the substance after time \(t\), \(N_0\) is the initial quantity, and "\(e\)" is the base of natural logarithms, approximately equal to 2.718.

This formula is crucial for calculating how much of a radioactive element remains after a certain time. It incorporates the decay constant "\(k\)" which helps determine the rate at which the element decays. In practical applications, this equation allows us to set up a relationship between the initial and remaining quantities of a material to solve for unknowns like decay constant or time. By understanding this core concept, we can predict changes in the amount of radioactive substance over a given period.
Decay Constant
The decay constant \(k\) is a fundamental parameter in the process of radioactive decay. It quantifies the rate at which a radioactive substance decays. The decay constant is derived from the formula \(k = -\frac{\ln(0.8)}{2}\) in the provided example, where the arithmetic is based on the natural logarithm of the remaining quantity after a specific time.

Understanding the decay constant involves recognizing that it is inversely related to half-life. A larger decay constant indicates a faster rate of decay, meaning the substance will reach its half-life quicker. Conversely, a smaller decay constant results in a slower decay process. The relationship between visible changes in a radioactive substance and its mathematical representation through \(k\) helps analyze and predict the behavior of radioactive materials over time.

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