Chapter 10: Problem 11
\(x^{2}+x-3=0\)
Short Answer
Expert verified
The solutions are \(x = 1\) and \(x = -3\).
Step by step solution
01
Identify the Type of Equation
Notice that the given equation \(x^2 + x - 3 = 0\) is a quadratic equation. It can be solved using factorization, completing the square, or the quadratic formula.
02
Check for Possible Factorization
Attempt to factor the equation \(x^2 + x - 3\). Look for two numbers that multiply to \(-3\) and add to \(1\). These numbers are \(3\) and \(-1\).
03
Factor the Quadratic Expression
Rewrite the middle term of the equation using the numbers found: \(x^2 + 3x - x - 3 = 0\). Then group: \((x^2 + 3x) - (x + 3)\) and factor by grouping: \([x(x+3) - 1(x+3)] = (x-1)(x+3)\).
04
Solve for x
Set each factor equal to zero: \(x - 1 = 0\) and \(x + 3 = 0\). Solve these simple equations to find the solutions: \(x = 1\) or \(x = -3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorization
Factorization is a way of breaking down a complex expression into simpler multiplicative components. When we deal with quadratic equations, these components often take the form of linear factors. The goal is to transform the expression into a product of simpler terms, which can then be easily set to zero to solve for the variable. In the exercise using factorization, we are given the equation \( x^2 + x - 3 = 0 \), and our task is to find numbers that will help us break apart the middle term. This is a strategic search where we look for two numbers that multiply to the constant term, which in this case is \(-3\), and add up to the coefficient of the linear term, which is \(1\).
Here’s a quick list that may help when attempting factorization:
Here’s a quick list that may help when attempting factorization:
- Identify the coefficients and constant term in the equation.
- Multiply factors to achieve the constant term.
- Add these factors to get the linear term's coefficient.
Solving Quadratic Equations
Solving quadratic equations involves finding the values of \(x\) that make the equation true. A quadratic equation is a polynomial equation of degree 2. This means its graph will form a parabola. The standard form of a quadratic equation is: \( ax^2 + bx + c = 0 \), where \(a\), \(b\), and \(c\) are constants.
There are several methods to solve a quadratic equation:
There are several methods to solve a quadratic equation:
- Factorization: If the equation can be nicely factored into linear terms.
- Quadratic Formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- Completing the Square: Rearranging and balancing the equation to form a perfect square trinomial.
Factoring by Grouping
Factoring by grouping is a tactical approach used for expressions that can be split into two pairs of terms, each of which shares a common factor. This method is particularly useful when simple factorization is not immediately obvious.
Here's a breakdown of the process used in the original exercise:
Here's a breakdown of the process used in the original exercise:
- First, rewrite the quadratic expression by substituting the middle term using numbers that satisfy the conditions: multiply to the constant term and add to the linear term's coefficient.
- For \( x^2 + x - 3 \), we split it as \( x^2 + 3x - x - 3 \).
- Group terms to find common factors: \((x^2 + 3x) - (x + 3)\).
- Factor out the common terms: \(x(x+3) - 1(x+3)\).
- Notice that \(x + 3\) is a common factor, leaving us with \((x-1)(x+3)\).