Chapter 10: Problem 5
Use the quadratic formula to solve each of the following quadratic equations. $$n^{2}-2 n-5=0$$
Short Answer
Expert verified
The solutions are \(x = 1 + \sqrt{6}\) and \(x = 1 - \sqrt{6}\).
Step by step solution
01
Identify coefficients
For the quadratic equation in the form of \( ax^2 + bx + c = 0 \), identify the coefficients. Here, \( a = 1 \), \( b = -2 \), and \( c = -5 \).
02
Write down the quadratic formula
The quadratic formula to find the roots of the quadratic equation \( ax^2 + bx + c = 0 \) is given by: \[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \]
03
Calculate the discriminant
Compute the discriminant, \( b^2 - 4ac \). Substituting \( b = -2 \), \( a = 1 \), and \( c = -5 \):\[b^2 - 4ac = (-2)^2 - 4(1)(-5) = 4 + 20 = 24.\]The discriminant is 24.
04
Substitute into the quadratic formula
Substitute the values of \( a \), \( b \), and the discriminant back into the quadratic formula:\[x = \frac{-(-2) \pm \sqrt{24}}{2(1)} = \frac{2 \pm \sqrt{24}}{2}.\]
05
Simplify the square root and fraction
Simplify \( \sqrt{24} \) as \( \sqrt{4 \times 6} = 2\sqrt{6} \). Substitute back:\[x = \frac{2 \pm 2\sqrt{6}}{2}.\] Divide each term by 2:\[x = 1 \pm \sqrt{6}.\]
06
State the final solutions
The solutions for the quadratic equation are:\(x = 1 + \sqrt{6} \quad \text{and} \quad x = 1 - \sqrt{6}.\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a type of polynomial equation that has the standard form: \[ ax^2 + bx + c = 0 \]where \( a \), \( b \), and \( c \) are coefficients, and \( a eq 0 \) because if \( a \) were 0, the equation would be linear, not quadratic. Quadratic equations are essential in algebra and are characterized by their highest exponent, which is a power of 2. This means that their graphs are parabolas, either opening upwards or downwards, depending on the sign of \( a \).
Common features of quadratic equations include:
Common features of quadratic equations include:
- The leading coefficient \( a \) determines the "width" and "direction" of the parabola.
- The constant term \( c \) affects the vertical position of the parabola on a graph.
Discriminant
The discriminant is a vital part of the quadratic formula and provides important information about the nature of the roots of a quadratic equation. It is derived from the formula \[ b^2 - 4ac \]and directly influences the number and type of roots:
- If the discriminant is positive (\( b^2 - 4ac > 0 \)), the quadratic equation has two distinct real roots.
- If it is zero (\( b^2 - 4ac = 0 \)), there is exactly one real root, indicating a perfect square scenario where the graph touches the x-axis at one point.
- If negative (\( b^2 - 4ac < 0 \)), the equation has no real roots, but two complex imaginary roots.
Roots of Equation
The roots of a quadratic equation are the solutions to the equation, or the values of \( x \) where the equation equals zero. These roots correspond to the x-values where the parabola of the quadratic equation intersects the x-axis. To find these roots, we use the quadratic formula, \[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \].Let's break down this process:
- Substitute the coefficients \( a \), \( b \), and \( c \) into the formula.
- Calculate the discriminant \( b^2 - 4ac \) to determine the nature of the roots.
- Plug the discriminant into the formula to find the values of \( x \).