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Chapter 3: Q. 407 (page 409)

The length of a rectangle is 36 feet and the width is 19 feet. Find the 鈸� perimeter 鈸� area.

Short Answer

Expert verified

Part a. The perimeter of the rectangle is 110feet.

Part b. The area of the rectangle is 684square feet.

Step by step solution

01

Part (a) Step 1. Given Information

Given that the length of a rectangle is 36feet and the width is role="math" localid="1647240833039" 19feet.

The objective is to find the perimeter and the area of the rectangle.

02

Part (a) Step 2. Find the perimeter

The perimeter of a rectangle is the sum of twice the length and twice the width: P=2L+2W.

So when the length is 36feet and width is 19feet, then the perimeter is given as

role="math" P=2脳36+2脳19P=72+38P=110

So the perimeter of the rectangle is110feet.

03

Part (b) Step 1. Find the area

The area of a rectangle is the length times the width: A=LW.

So when the length is 36feet and width is 19feet, then the area is given as

A=36脳19A=684

So the area of the rectangle is 684square feet.

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