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Chapter 3: Q. 408 (page 409)

A sidewalk in front of Kathy鈥檚 house is in the shape of a rectangle four feet wide by 45feet long. Find the 鈸� perimeter 鈸� area.

Short Answer

Expert verified

Part a. The perimeter of the rectangle is 98feet.

Part b. The area of the rectangle is 180square feet.

Step by step solution

01

Part (a) Step 1. Given Information

Given that a sidewalk is in the shape of a rectangle four feet wide by 45feet long.

The objective is to find the perimeter and the area of the rectangle.

02

Part (a) Step 2. Find the perimeter 

The perimeter of a rectangle is the sum of twice the length and twice the width: P=2L+2W

So when the length is localid="1655803616557" 45feet and width is localid="1655803620164" 4feet, then the perimeter is given as

P=2脳45+2脳4P=90+8P=98

So the perimeter of the rectangle islocalid="1655803624957" 98feet.

03

Part (b) Step 1. Find the area

The area of a rectangle is the length times the width: A=LW.

So when the length is 45feet and width is 4feet, then the area is given as

A=45脳4A=180

So the area of the rectangle is 180square feet.

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