Chapter 9: Problem 558
In the following exercises, simplify. (a) \(32^{\frac{2}{5}}\) (b) \(27^{-\frac{2}{3}}\) (c) \(25^{-\frac{3}{2}}\)
Short Answer
Expert verified
(a) 4 (b) \frac{1}{9} (c) \frac{1}{125}
Step by step solution
01
Simplify the Expression for Part (a)
For the expression \(32^{\frac{2}{5}}\), rewrite it using the property of exponents: \(a^{\frac{m}{n}} = \sqrt[n]{a^m}\). Therefore, we have: \ 32^{\frac{2}{5}} = (32^{1/5})^2 \.
02
Simplify the Base for Part (a)
Calculate \(32^{1/5}\). Since \(32 = 2^5\), we have: \ (2^5)^{1/5} = 2 \.
03
Raise to the Power for Part (a)
Now, raise the simplified base to the power of 2: \ 2^2 = 4 \. So, \(32^{\frac{2}{5}} = 4\).
04
Simplify the Expression for Part (b)
For the expression \(27^{-\frac{2}{3}}\), rewrite it using the property of exponents: \(a^{\frac{m}{n}} = \sqrt[n]{a^m}\). Therefore, we have: \ 27^{-\frac{2}{3}} = \frac{1}{27^{\frac{2}{3}}} \.
05
Simplify the Base for Part (b)
Calculate \(27^{\frac{2}{3}}\). Since \(27 = 3^3\), we have: \ (3^3)^{2/3} = 3^2 = 9 \.
06
Inverse the Fraction for Part (b)
Taking the inverse: \ \frac{1}{9} \. So, \(27^{-\frac{2}{3}} = \frac{1}{9}\).
07
Simplify the Expression for Part (c)
For the expression \(25^{-\frac{3}{2}}\), rewrite it using the property of exponents: \(a^{\frac{m}{n}} = \sqrt[n]{a^m}\). Therefore, we have: \ 25^{-\frac{3}{2}} = \frac{1}{25^{\frac{3}{2}}} \.
08
Simplify the Base for Part (c)
Calculate \(25^{\frac{3}{2}}\). Since \(25 = 5^2\), we have: \ (5^2)^{3/2} = 5^3 \.
09
Compute the Final Value for Part (c)
Raise the base to the power of 3: \ 5^3 = 125 \. Taking the inverse, we get: \ \frac{1}{125} \. So, \(25^{-\frac{3}{2}} = \frac{1}{125}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Properties of Exponents
Exponents are a fundamental part of algebra and mathematics in general. They help in simplifying expressions and solving equations efficiently. Understanding their properties makes many algebraic operations easier. Some basic properties are:
These properties will help you simplify exponential expressions with ease. For instance, in the given exercises, we use the power of a product, negative exponents, and fractional exponents.
- \textbf{Product of Powers:} When multiplying two exponents with the same base, add the exponents: \[a^m \times a^n = a^{m+n}\]
- \textbf{Power of a Power:} When raising an exponent to another exponent, multiply the exponents: \[ (a^m)^n = a^{mn} \]
- \textbf{Power of a Product:} When raising a product to an exponent, distribute the exponent to each factor: \[ (ab)^m = a^m \times b^m \]
- \textbf{Quotient of Powers:} When dividing two exponents with the same base, subtract the exponents: \[ \frac{a^m}{a^n} = a^{m-n} \]
- \textbf{Negative Exponent:} A negative exponent indicates a reciprocal: \[ a^{-n} = \frac{1}{a^n} \]
- \textbf{Zero Exponent:} Any nonzero base raised to the zero power is 1: \[ a^0 = 1 \]
These properties will help you simplify exponential expressions with ease. For instance, in the given exercises, we use the power of a product, negative exponents, and fractional exponents.
Rational Exponents
Rational exponents are simply another way to represent roots and powers. A rational exponent is an exponent that is a fraction. For example, \[ a^{\frac{m}{n}} \] represents the nth root of a raised to the power of m. This can be split into two steps:
Let's break down the steps for the given exercises using rational exponents:
For \[ 32^{\frac{2}{5}} \], rewrite it as \[ \left(32^{\frac{1}{5}}\right)^2 \]. This is \[ \left(2\right)^2 = 4 \], because \[ 32 = 2^5 \].
For \[ 27^{-\frac{2}{3}} \], rewrite it as a reciprocal: \[ \frac{1}{27^{\frac{2}{3}}} \]. Simplifying inside the denominator gives: \[ \frac{1}{\left(27^{\frac{1}{3}}\right)^2} = \frac{1}{\left(3\right)^2} = \frac{1}{9} \], because \[ 27 = 3^3 \].
Lastly, for \[ 25^{-\frac{3}{2}} \], rewrite it as a reciprocal again: \[ \frac{1}{25^{\frac{3}{2}}} \]. Simplifying the base gives: \[ \frac{1}{\left(25^{\frac{1}{2}}\right)^3} = \frac{1}{\left(5\right)^3} = \frac{1}{125} \], because \[ 25 = 5^2 \].
- \textbf{Root Step:} Take the nth root of the base (a).
- \textbf{Exponent Step:} Raise the result to the power of m.
Let's break down the steps for the given exercises using rational exponents:
For \[ 32^{\frac{2}{5}} \], rewrite it as \[ \left(32^{\frac{1}{5}}\right)^2 \]. This is \[ \left(2\right)^2 = 4 \], because \[ 32 = 2^5 \].
For \[ 27^{-\frac{2}{3}} \], rewrite it as a reciprocal: \[ \frac{1}{27^{\frac{2}{3}}} \]. Simplifying inside the denominator gives: \[ \frac{1}{\left(27^{\frac{1}{3}}\right)^2} = \frac{1}{\left(3\right)^2} = \frac{1}{9} \], because \[ 27 = 3^3 \].
Lastly, for \[ 25^{-\frac{3}{2}} \], rewrite it as a reciprocal again: \[ \frac{1}{25^{\frac{3}{2}}} \]. Simplifying the base gives: \[ \frac{1}{\left(25^{\frac{1}{2}}\right)^3} = \frac{1}{\left(5\right)^3} = \frac{1}{125} \], because \[ 25 = 5^2 \].
Simplifying Expressions
Simplifying algebraic expressions often involves using properties of exponents and understanding rational exponents. Here are some key steps to simplify expressions:
In the exercises provided:
1. For \[ 32^{\frac{2}{5}} \], we expressed it as \[ \left( 32^{\frac{1}{5}} \right)^2 = 4 \], knowing \[ 32 = 2^5 \].
2. For \[ 27^{-\frac{2}{3}} \], we first rewrote it as \[ \frac{1}{27^{\frac{2}{3}}} = \frac{1}{\left( 27^{\frac{1}{3}} \right)^2} = \frac{1}{9} \], using \[ 27 = 3^3 \].
3. For \[ 25^{-\frac{3}{2}} \], we expressed it as \[ \frac{1}{25^{\frac{3}{2}}} = \frac{1}{\left( 25^{\frac{1}{2}} \right)^3} = \frac{1}{125} \], knowing \[ 25 = 5^2 \].
By breaking down the expressions into more manageable parts and using the properties of exponents, simplifying complex expressions becomes more approachable.
- Identify the base and the exponent.
- Look for opportunities to use exponent properties (such as product, power, and quotient rules).
- Rewrite expressions with rational exponents as roots and powers.
- Simplify inside parentheses first.
- Handle negative exponents by taking reciprocals.
In the exercises provided:
1. For \[ 32^{\frac{2}{5}} \], we expressed it as \[ \left( 32^{\frac{1}{5}} \right)^2 = 4 \], knowing \[ 32 = 2^5 \].
2. For \[ 27^{-\frac{2}{3}} \], we first rewrote it as \[ \frac{1}{27^{\frac{2}{3}}} = \frac{1}{\left( 27^{\frac{1}{3}} \right)^2} = \frac{1}{9} \], using \[ 27 = 3^3 \].
3. For \[ 25^{-\frac{3}{2}} \], we expressed it as \[ \frac{1}{25^{\frac{3}{2}}} = \frac{1}{\left( 25^{\frac{1}{2}} \right)^3} = \frac{1}{125} \], knowing \[ 25 = 5^2 \].
By breaking down the expressions into more manageable parts and using the properties of exponents, simplifying complex expressions becomes more approachable.