Chapter 7: Problem 35
$$ \frac{v^{2}+9 v+20}{v^{2}+10 v+24} $$$$ \frac{z^{2}-3 z-40}{z^{2}-64} $$
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Chapter 7: Problem 35
$$ \frac{v^{2}+9 v+20}{v^{2}+10 v+24} $$$$ \frac{z^{2}-3 z-40}{z^{2}-64} $$
These are the key concepts you need to understand to accurately answer the question.
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For exercises 1-10, (a) solve. (b) check. $$ \frac{2}{9} x+\frac{5}{3}=\frac{5}{9} x+\frac{7}{3} $$
For exercises 1-10, (a) solve. (b) check. $$ \frac{4}{15} k+\frac{3}{4}=-2 $$
When the radiation is constant, the relationship of the current in an X-ray tube, \(x\), and the exposure time, \(y\), is an inverse variation. When the current is 600 milliamp, the exposure time is \(0.2 \mathrm{~s}\). Write an equation that represents this variation. Include the units.
For exercises 37-38, \(T=\frac{R}{A}\) represents the relationship of the asset turnover ratio, \(T\); the sales revenue of a company, \(R\); and the total revenues of a company, \(A\). Is the relationship of the given variables a direct variation or an inverse variation? $$ A \text { is constant; the relationship of } R \text { and } T \text {. } $$
The formula \(R=\frac{V}{I}\) represents the relationship of the resistance \(R\), voltage \(V\), and current \(I\) in an electric circuit. Assume that \(V\) is constant. Is the relationship of \(R\) and \(I\) a direct variation or an inverse variation?
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