Chapter 7: Problem 11
For exercises 1-66, simplify. $$ \frac{2 x-8}{10 x} $$
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Chapter 7: Problem 11
For exercises 1-66, simplify. $$ \frac{2 x-8}{10 x} $$
These are the key concepts you need to understand to accurately answer the question.
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The relationship of \(x\) and \(y\) is a direct variation. When \(x=1, y=6\). a. Find the constant of proportionality, \(k\). b. Write an equation that represents this direct variation. c. Find \(y\) when \(x=4\), d. Use slope-intercept graphing to graph this equation. e. Use the graph to find \(y\) when \(x=2\).
For exercises 53-56, the formula \(F=\frac{100 S_{u} C_{p}}{S_{p} C_{u}}\) describes the fractional excretion of sodium, \(F\). Is the relationship of the given variables a direct variation or an inverse variation? $$ S_{u}, S_{p} \text {, and } C_{u} \text { are constant; the relationship of } F \text { and } C_{p} \text {. } $$
For exercises \(45-48\), the formula \(R=\frac{U F}{P}\) describes the glomular filtration rate by a kidney \(R\). Is the relationship of the given variables a direct variation or an inverse variation? $$ U \text { and } P \text { are constant; the relationship of } R \text { and } F \text {. } $$
For exercises 1-10, (a) solve. (b) check. $$ \frac{4}{15} k+\frac{3}{4}=-2 $$
For exercises 1-10, (a) solve. (b) check. $$ \frac{2}{9} x+\frac{5}{3}=\frac{5}{9} x+\frac{7}{3} $$
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