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A line passes through the given points. (a) Find the slope of the line. (b) Write the equation of the line in slope-intercept form. $$ \left(3, \frac{5}{12}\right) ;\left(5, \frac{9}{10}\right) $$

Short Answer

Expert verified
Slope: \( \frac{83}{240} \) Equation: \( y = \frac{83}{240}x - \frac{199}{240} \)

Step by step solution

01

- Identify the Coordinates

Identify the coordinates of the two given points. Let \(x_1, y_1\) represent the first point \(3, \frac{5}{12}\) and \(x_2, y_2\) represent the second point \(5, \frac{9}{10}\).
02

- Calculate the Slope

Use the slope formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\) to find the slope. Substitute the coordinates: \[m = \frac{\frac{9}{10} - \frac{5}{12}}{5 - 3} = \frac{\frac{108 - 25}{120}}{2} = \frac{\frac{83}{120}}{2} = \frac{83}{240} \]
03

- Write the Equation in Point-Slope Form

The point-slope form of a line is \(y - y_1 = m(x - x_1)\). Use the slope \(m = \frac{83}{240}\) and one of the points, say \(x_1 = 3\) and \(y_1 = \frac{5}{12}\). Substitute into the formula: \[y - \frac{5}{12} = \frac{83}{240}(x - 3) \]
04

- Convert to Slope-Intercept Form

Convert the point-slope equation to slope-intercept form \(y = mx + b\). Simplify the equation from Step 3: \[y - \frac{5}{12} = \frac{83}{240}x - \frac{83 \times 3}{240} \] \[y = \frac{83}{240}x - \frac{249}{240} + \frac{5}{12} \] \[y = \frac{83}{240}x - \frac{249}{240} + \frac{25}{60} \] \[y = \frac{83}{240}x - \frac{249}{240} + \frac{50}{240} \] \[y = \frac{83}{240}x - \frac{199}{240} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

slope of a line
The slope of a line measures its steepness. It is represented by the letter 'm'.
It shows how much the y-coordinate changes for a unit increase in the x-coordinate.
In mathematical terms, the slope between two points \[ (x_1, y_1) \] and \[ (x_2, y_2) \] is calculated using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
For example, given points \[ (3, \frac{5}{12}) \] and \[ (5, \frac{9}{10}) \], substitute the coordinates into the formula:
\[ m = \frac{\frac{9}{10} - \frac{5}{12}}{5 - 3} = \frac{\frac{108 - 25}{120}}{2} = \frac{\frac{83}{120}}{2} = \frac{83}{240} \]
This slope tells us how much the y-coordinate changes per unit increase in the x-coordinate.
slope-intercept form
Slope-intercept form is a common way to write the equation of a line. It is represented as:
\[ y = mx + b \]
Where 'm' is the slope and 'b' is the y-intercept (the point where the line crosses the y-axis).
Let's convert the point-slope form equation to slope-intercept form using our slope \[ m = \frac{83}{240} \] and the y-intercept 'b'.
Given the point-slope equation:
\[ y - \frac{5}{12} = \frac{83}{240}(x - 3) \]
Simplify to reach slope-intercept form:
\[ y = \frac{83}{240}x - \frac{249}{240} + \frac{25}{60} = \frac{83}{240}x - \frac{249}{240} + \frac{50}{240} = \frac{83}{240}x - \frac{199}{240} \]
Thus, our slope-intercept form equation becomes:
\[ y = \frac{83}{240}x - \frac{199}{240} \]
point-slope form
The point-slope form is another useful way to express the equation of a line. The formula is:
\[ y - y_1 = m(x - x_1) \]
Where \[ (x_1, y_1) \] is a known point on the line and 'm' is the slope.
Using our example points \[ (3, \frac{5}{12}) \] and \[ (5, \frac{9}{10}) \],and the calculated slope \[ m = \frac{83}{240} \], we substitute into the formula:
\[ y - \frac{5}{12} = \frac{83}{240}(x - 3) \]
This form is very useful when you already have a point and need the equation of the line passing through that point.
coordinate geometry
Coordinate geometry, also known as analytic geometry, studies geometry using a coordinate system. It bridges algebra and geometry through graphs and equations.
It involves plotting points, lines, and curves on a coordinate plane, and using algebraic methods to solve geometric problems.
Important components include:
  • Points: Defined by coordinates \[ (x, y) \]. Example: \[ (3, \frac{5}{12}) \]
  • Distance: The distance between two points \[ (x_1, y_1) \] and \[ (x_2, y_2) \] is found using the formula:
    \[ \text{Distance} = \frac{\frac{(x_2-x_1)^2 + (y_2 - y_1)^2}} \]
  • Midpoint: The midpoint between two points \[ (x_1, y_1) \] and \[ (x_2, y_2) \] is \[ \frac{\frac{(x_1 + x_2)}{2}, \frac{(y_1 + y_2)}{2}} \].

The exercise we've solved demonstrates these concepts by identifying points and calculating the slope of a line.
It shows how we use these fundamental ideas to write equations of lines.

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Most popular questions from this chapter

A high-speed Shinkansen train in Japan travels at a speed of \(\frac{270 \mathrm{~km}}{1 \mathrm{hr}}\) for \(18 \mathrm{~min}\). Find the distance it travels.

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For exercises 91-94, use a graphing calculator to graph each equation. Choose a window that shows the \(x\)-intercept and \(y\)-intercept. Sketch the graph; describe the window. \(y=-2 x+5\)

Some learning preferences describe how you prefer to receive, think about, and learn new information. These preferences include visual learning, auditory learning, and kinesthetic learning. Many students use more than one of these categories as they learn mathematics. \- Visual learners prefer to see information. Although you definitely listen to your instructor, you also like to see the example on a white board or screen. You may be able to recall a process by visualizing it in your mind; you may learn better by organizing information in charts, tables, diagrams, or pictures. You may prefer the use of colored markers instead of just black. \- Auditory learners prefer to hear information. Although you definitely watch what your instructor is doing, you also like your instructor to explain things aloud as he or she works. You may find it difficult to take notes because you cannot concentrate enough on what is being said while you write. You may learn better if you have the chance to explain things to others. \- Kinesthetic learners prefer to do. You may find it difficult to sit still and just watch and listen; you want to be trying it out. You may find that you must take notes in order to learn. If you only watch and listen, you may understand the concept but not remember it after you leave the classroom. You often learn better if you can show others how to do things. Have you noticed anything that your instructor does while teaching that you find helps you remember what has been taught?

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