/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 \([\mathrm{BB}]\) In the poset \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\([\mathrm{BB}]\) In the poset \((\mathcal{P}(S), \subseteq)\) of subsets of a set \(S\), under what conditions does one set \(B\) cover another set \(A\) ?

Short Answer

Expert verified
Set \( B \) covers set \( A \) if \( B = A \cup \{a\} \) for some \( a \notin A \).

Step by step solution

01

Understanding the terms

We need to understand what it means for a set \( B \) to cover another set \( A \) in the context of a partially ordered set (poset) \( (\mathcal{P}(S), \subseteq) \). In this poset, \( \mathcal{P}(S) \) represents the power set of \( S \), and \( \subseteq \) is the subset relation.
02

Defining covering in a poset

In a poset, a set \( B \) covers another set \( A \) if \( A \subset B \) and there is no subset \( C \) such that \( A \subset C \subset B \). This means that \( B \) is directly above \( A \) in terms of the subset relation, with no other set in between.
03

Relation to the power set

Since \( \mathcal{P}(S) \) is the power set of \( S \), any subset \( A \) can potentially have several elements added to it to form \( B \). For \( B \) to cover \( A \), \( B \) must include exactly one additional element that is in \( S \) but not in \( A \).
04

Condition for covering

Thus, for \( B \) to cover \( A \), \( B \) must be formed by adding exactly one element \( a \in S \setminus A \) to \( A \). Formally, this can be expressed as: \( B = A \cup \{a\} \), where \( a otin A \). This ensures \( A \subset B \) and there is no other subset \( C \) such that \( A \subset C \subset B \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Set
The power set of a set \(S\) is an interesting concept in mathematics. It is defined as the set of all possible subsets of \(S\). If \(S\) is a finite set, suppose it has \(n\) elements, the power set of \(S\) will have \(2^n\) elements. This is because each element can either be present or absent in a subset.
To visualize a power set, let's consider a simple set, \(S = \{1, 2\}\). The power set \(\mathcal{P}(S)\) consists of:
  • The empty set: \(\emptyset\)
  • Single-element subsets: \(\{1\}, \{2\}\)
  • The subset containing both elements: \(\{1, 2\}\)
Hence, \(\mathcal{P}(S) = \{\emptyset, \{1\}, \{2\}, \{1, 2\}\}\). This gives us a clear example of why a power set contains all combinations of the elements in \(S\).
Understanding power sets is essential because it provides a foundation for exploring more complex structures involving sets, like posets and relational concepts in mathematics.
Subset Relation
The subset relation is a fundamental concept in set theory, denoted by \(\subseteq\). When we say \(A \subseteq B\), it means every element of \(A\) is also an element of \(B\). This is a reflexive, antisymmetric, and transitive relationship, giving it the essential properties of a partial order.
There are few key points to remember about subset relations:
  • Reflexivity: For any set \(A\), \(A \subseteq A\).
  • Antisymmetry: If \(A \subseteq B\) and \(B \subseteq A\) hold true, then \(A = B\).
  • Transitivity: If \(A \subseteq B\) and \(B \subseteq C\), then \(A \subseteq C\).
These properties make subset relations naturally suitable for organizing elements in a poset. In practical terms, for two sets \(A\) and \(B\), if one covers another, it's defined as \(A \subset B\) but not \(B \subseteq A\). This feature of the subset relation is vital in defining the coverage aspect of posets.
Covering Relation
In the context of partially ordered sets, or posets, a covering relation helps us understand the direct connection between elements without intermediaries. When one set \(B\) covers another set \(A\), it means \(A \subset B\), and there is no other subset \(C\) such that \(A \subset C \subset B\). This describes a direct, step-wise relationship in the poset structure.
Imagine a set \(S\) with elements. When constructing the power set \(\mathcal{P}(S)\), the covering relation tells us how one subset leaps to the next directly. Let's break it down further:
  • For \(B\) to cover \(A\), \(B\) must be created by adding precisely one new element from \(S\) to \(A\).
  • The formula \(B = A \cup \{a\}\), where \(a otin A\), illustrates this beautifully.
  • This unique addition ensures no other set fits between \(A\) and \(B\) in terms of subset relations.
Understanding this concept is important because it simplifies how we view and organize sets within posets, revealing the proximity and adjacency of elements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The universal set for this problem is the set of students attending Miskatonic University. Let \- \(M\) denote the set of math majors \- \(C S\) denote the set of computer science majors \- \(T\) denote the set of students who had a test on Friday \- \(P\) denote those students who ate pizza last Thursday. Using only the set theoretical notation we have introduced in this chapter, rewrite each of the following assertions. (a) [BB] Computer science majors had a test on Friday. (b) \([B B]\) No math major ate pizza last Thursday. (c) One or more math majors did not eat pizza last Thursday. (d) Those computer science majors who did not have a test on Friday ate pizza on Thursday. (e) Math or computer science majors who ate pizza on Thursday did not have a test on Friday.

\([\mathrm{BB}]\) Let \(A=(\\{a, b\\}\\} .\) Are the following statements true or false? Explain your answer. (a) \(a \in A\). (b) \(A \in A\). (c) \(\\{a, b\\} \in A\). (d) There are two elements in \(A\).

Explain why each of the following binary relations on \(S=\\{1,2,3\\}\) is not an equivalence relation on \(S\). (a) \([\mathrm{BB}] \mathcal{R}=\\{(1,1),(1,2),(3,2),(3,3),(2,3),(2,1)\\}\) (b) \(\mathcal{R}=\\{(1,1),(2,2),(3,3),(2,1),(1,2),(2,3),(3,1),\), \((1,3)\\}\)

Let \(A=\\{(-1,2),(4,5),(0,0),(6,-5),(5,1),(4,3)\\}\). List the elements in each of the following sets. (a) \([\mathrm{BB}]\\{a+b \mid(a, b) \in A\\}\) (b) \(\\{a \mid a>0\) and \((a, b) \in A\) for some \(b\\}\) (c) \(\left\\{b \mid b=k^{2}\right.\) for some \(k \in Z\) and \((a, b) \in A\) for some \(a\\}\)

For \(a, b \in \mathrm{R} \backslash\\{0\\}\), define \(a \sim b\) if and only if \(\frac{a}{b} \in \mathrm{Q} .\) (a) Prove that \(\sim\) is an equivalence relation. (b) Find the equivalence class of 1 . (c) Show that \(\overline{\sqrt{3}}=\overline{\sqrt{12}}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.