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Suppose \(A\) and \(B\) are events in a sample space \(S\) and suppose that \(P(A)=0.6, P\left(B^{c}\right)=0.4\), and \(P(A \cap B)=0.2\). What is \(P(A \cup B)\) ?

Short Answer

Expert verified
\(P(A \cup B)\) cannot be determined using the given probabilities, as the calculated value of 1.0 exceeds the maximum possible probability of 1. Check the values provided in the exercise and ensure their accuracy.

Step by step solution

01

Write the given probabilities

We are given the following probabilities: - \(P(A) = 0.6\) - \(P\left(B^{c}\right) = 0.4\) - \(P(A \cap B) = 0.2\)
02

Find the probability of event B

To find the probability of event B, we use the fact that the sum of the probabilities of an event and its complement is equal to 1: \(P(B) + P\left(B^{c}\right) = 1\) Now we can solve for \(P(B)\): \(P(B) = 1 - P\left(B^{c}\right) = 1 - 0.4 = 0.6\) So, \(P(B) = 0.6\).
03

Find the probability of the union of events A and B

Now that we have the probability of event B, we can find the probability of the union of events A and B using the formula: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\) Plug in the given probabilities: \(P(A \cup B) = 0.6 + 0.6 - 0.2\) Now we can perform the arithmetic: \(P(A \cup B) = 1.2 - 0.2 = 1.0\) However, since a probability cannot be greater than 1, there must be an error in the given exercise as the probability of the union of events A and B cannot be 1.0. Check the values given in the exercise and make sure they are correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Events
When we talk about the union of events in probability, we refer to the occurrence of at least one of several events. In simpler terms, the union of events A and B, denoted as \(A \cup B\), is the event that occurs if either event A, event B, or both events occur. This concept is important in probability theory because it helps us understand the likelihood of multiple events happening together or independently.
To calculate the probability of the union of two events, we use the formula:
  • \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
This formula considers the probabilities of each event, A and B, occurring on their own, and then subtracts the probability of them both occurring together, \(P(A \cap B)\). This subtraction is necessary to avoid counting the overlap twice.
In problems like the one provided, ensuring each event's probability is correctly identified is crucial because incorrect values can lead to errors, as seen when the calculated probability of \(A \cup B\) exceeded 1. This scenario highlights the necessity of double-checking given probabilities for logical consistency.
Complementary Events
In probability, complementary events are pairs of events where the occurrence of one event means the other cannot occur. The complement of an event A is denoted as \(A^c\), representing all outcomes in the sample space \(S\) that are not part of event A.
The important relationship between an event and its complement is expressed as:
  • \(P(A) + P(A^c) = 1\)
This means that if you have the probability of an event, you can easily find the probability of its complement by subtracting the given probability from 1. In the provided example, knowing \(P(B^c) = 0.4\) allowed us to find \(P(B)\) by calculating \(1 - 0.4 = 0.6\).
Understanding complementary events is key in problems where missing information about an event can be deduced from its complement. It ensures that all possible outcomes together form a complete set with a total probability of 1.
Intersection of Events
The intersection of events in probability is the scenario where multiple events occur simultaneously. For events A and B, the intersection is denoted by \(A \cap B\) and represents the event that includes only the outcomes that are common to both A and B.
The probability of the intersection of two events is an important value when calculating the probability of the union of events, as seen in the provided exercise. In mathematical terms, it helps separate overlapping probabilities to avoid overestimation.
In simpler situations, the probability of \(A \cap B\) might be given directly, like in this problem, \(P(A \cap B) = 0.2\). In more complex problems, it may need to be calculated using additional information about the relationship between the events, such as conditional probabilities.
Understanding intersections goes hand-in-hand with understanding unions, as both concepts involve analyzing how events overlap and influence each other's likelihood of occurring. Together, these tools allow for a comprehensive analysis of possible outcomes in probability theory.

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Most popular questions from this chapter

Express each of the sums in \(24-35\) in closed form (without using a summation symbol and without using an ellipsis \(\cdots\) ). $$ \sum_{i=0}^{m}\left(\begin{array}{l} m \\ i \end{array}\right) 4^{i} $$

Modify Example \(6.2 .4\) by supposing that a PIN must not begin with any of the letters \(\mathrm{A}-\mathrm{M}\) and must end with a digit. Continue to assume that no symbol may be used more than once and that the total number of PINs is to be determined. a. Find the error in the following "solution." "Constructing a PIN is a four-step process. Step 1: Choose the left-most symbol. Step 2: Choose the second symbol from the left. Step 3: Choose the third symbol from the left. Step 4: Choose the right-most symbol. Because none of the thirteen letters from A through M may be chosen in step 1 , there are \(36-13=23\) ways to perform step 1. There are 35 ways to perform step 2 and 34 ways to perform step 3 because previously used symbols may not be used. Since the symbol chosen in step 4 must be a previously unused digit, there are \(10-3=7\) ways to perform step 4 . Thus there are \(23 \cdot 35 \cdot 34 \cdot 7=191,590\) different PINs that satisfy the given conditions." b. Reorder steps 1-4 in part (a) as follows: Step 1: Choose the right-most symbol. Step 2: Choose the left-most symbol. Step 3: Choose the second symbol from the left. Step 4: Choose the third symbol from the left. Use the multiplication rule to find the number of PINs that satisfy the given conditions.

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