/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Five people are to be seated aro... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Five people are to be seated around a circular table. Two seatings are considered the same if one is a rotation of the other. How many different seatings are possible?

Short Answer

Expert verified
There are 24 unique seatings possible for the 5 people around the circular table, considering that two seatings are the same if one is a rotation of the other.

Step by step solution

01

Determine the total number of permutations

In the most basic scenario without any constraints, we would just use the standard formula for permutations to find the number of ways to arrange the 5 people around the table. The formula for permutations of n objects without repetition is given by P(n) = n!, where n! means the factorial of n. So, for this problem, we have n = 5, and we need to find the permutations P(5) which is equal to 5!. P(5) = 5! = 5 × 4 × 3 × 2 × 1 = 120 This means there are a total of 120 different ways to seat the 5 people around the table without any constraints.
02

Account for the same seating arrangements due to rotation

Now, we need to consider the rotations of the seating arrangements that are considered to be the same. Since there are 5 people seated in a circular table, we can rotate the table 5 times such that we end up with the same seating arrangement with each person displaced to the next seat. To account for these duplicate seating arrangements, we simply divide the total number of permutations by the number of rotations, which in this case is 5. Unique seatings = Total permutations / Number of rotations Unique seatings = P(5) / 5 = 120 / 5 = 24
03

Conclusion

There are 24 unique seatings possible for the 5 people around the circular table, considering that two seatings are the same if one is a rotation of the other.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
When we talk about permutations, we are referring to the different ways in which a set of objects can be arranged in sequence. It's a fundamental concept in combinatorics, a branch of mathematics concerned with counting, arrangement, and combination of objects. Permutations are particularly important when the order of the objects matters.

For instance, if we have three books labeled A, B, and C, they can be arranged in a number of ways: ABC, ACB, BAC, BCA, CAB, and CBA. Each of these arrangements is a unique permutation of the books since the order changes the sequence even if the objects themselves do not change. The number of permutations increases rapidly with the number of objects, which is why mathematicians use factorial notation to express them more simply.

Factorial Notation
Factorial notation is a system used to simplify the expression of permutations. The factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n. So, for example, 4! (4 factorial) is equal to 4 × 3 × 2 × 1, which is 24. Factorial is exceptionally useful because it allows mathematicians and students to calculate the number of permutations without having to list them all out or multiply a large series of numbers each time.

In the context of our exercise, where we have five people to seat around a circular table, the initial calculation would simply be 5! for the linear permutations without considering rotations. However, factorial notation cannot be used directly in non-linear permutations, such as circular arrangements, without adjustments because it accounts for every possible order, including those that are not distinct in a circular setting.

Combinatorics
Combinatorics is an area of mathematics that deals with counting, both as a means and an end in obtaining results, and certain properties of finite structures. It is related to many other areas of mathematics and has applications in various scientific fields including computer science, statistics, and engineering. The combinatorial principles are critical when solving problems that ask for the number of possible arrangements, combinations, or selections of objects.

One interesting aspect of combinatorics is how it accounts for special conditions and restrictions, such as in our circular permutations example. Combinatorial problems can vary greatly in their level of complexity. Some can be solved by simple, direct counting methods, while others may require sophisticated tools and mathematical insight. Understanding these principles allows for accurate counting of configurations, which is why the adjustment for rotational equivalences in circular permutations is a significant example of combinatorial reasoning.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A bakery produces six different kinds of pastry. a. How many different selections of twenty pastries are there? b. Assuming that eclairs are one kind of pastry produced, how many different selections of twenty pastries are there if at least three must be eclairs? c. If a selection of twenty pastries is chosen randomly, what is the probability that at least three are eclairs? d. If a selection of twenty pastries is chosen randomly, what is the probability that exactly three are eclairs?

One urn contains one blue ball (labeled \(B_{1}\) ) and three red balls (labeled \(R_{1}, R_{2}\), and \(R_{3}\) ). A second urn contains two red balls \(\left(R_{4}\right.\) and \(\left.R_{5}\right)\) and two blue balls \(\left(B_{2}\right.\) and \(\left.B_{3}\right)\). An experiment is performed in which one of the two urns is chosen at random and then two balls are randomly chosen from it, one after the other without replacement. a. Construct the possibility tree showing all possible outcomes of this experiment. b. What is the total number of outcomes of this experiment? c. What is the probability that two red balls are chosen?

Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let \(B B G\) indicate that the first two children born are boys and the third child is a girl, let \(G B G\) indicate that the first and third children born are girls and the second is a boy, and so forth. a. List the eight elements in the sample space whose outcomes are all possible genders of the three children. b. Write each of the following events as a set and find its probability. (i) The event that exactly one child is a girl. (ii) The event that at least two children are girls. (iii) The event that no child is a girl.

a. According to Theorem \(6.5 .1\), how many multisets of size four can be chosen from a set of three elements? b. List all of the multisets of size four that can be chosen from the set \(\\{x, y, z\\}\).

A coin is loaded so that the probability of heads is \(0.7\) and the probability of tails is \(0.3\). Suppose that the coin is tossed twice and that the results of the tosses are independent. a. What is the probability of obtaining exactly two heads? b. What is the probability of obtaining exactly one head? c. What is the probability of obtaining no heads? d. What is the probability of obtaining at least one head?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.