Chapter 6: Problem 4
$$ \text { Expand the expressions in 1-9 using the binomial theorem. } $$ $$ (u-v)^{5} $$
Short Answer
Expert verified
The short answer for the expansion of \((u-v)^5\) using the binomial theorem is:
\((u-v)^5 = u^5 - 5u^4v + 10u^3v^2 - 10u^2v^3 + 5uv^4 - v^5\)
Step by step solution
01
Identify a, b, and n in the given expression
In our given expression, \((u-v)^5\), we have:
- a = u
- b = -v
- n = 5
Now we will substitute these values into the binomial theorem formula.
02
Write the formula for binomial expansion
Using the binomial theorem formula, the expansion of \((u-v)^5\) can be expressed as:
\((u-v)^5 = \sum_{k=0}^{5} \binom{5}{k} u^{5-k} (-v)^{k}\)
03
Expand each term in the summation
Now we will expand the summation by calculating each term for k = 0, 1, 2, 3, 4, 5.
When k = 0:
\(\binom{5}{0} u^{5-0} (-v)^{0} = 1 * u^5 * 1 = u^5\)
When k = 1:
\(\binom{5}{1} u^{5-1} (-v)^{1} = 5 * u^4 * (-v) = -5u^4v\)
When k = 2:
\(\binom{5}{2} u^{5-2} (-v)^{2} = 10 * u^3 * v^2 = 10u^3v^2\)
When k = 3:
\(\binom{5}{3} u^{5-3} (-v)^{3} = 10 * u^2 * (-v^3) = -10u^2v^3\)
When k = 4:
\(\binom{5}{4} u^{5-4} (-v)^{4} = 5 * u * v^4 = 5uv^4\)
When k = 5:
\(\binom{5}{5} u^{5-5} (-v)^{5} = 1 * 1 * (-v^5) = -v^5\)
04
Combine terms to find the expansion
Now we will combine the terms we calculated to find the expanded expression of \((u-v)^5\).
\((u-v)^5 = u^5 - 5u^4v + 10u^3v^2 - 10u^2v^3 + 5uv^4 - v^5\)
The expansion of the given expression, \((u-v)^5\), using the binomial theorem is:
\(u^5 - 5u^4v + 10u^3v^2 - 10u^2v^3 + 5uv^4 - v^5\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficients
Understanding binomial coefficients is key to demystifying the binomial theorem expansion. A binomial coefficient, symbolized by the notation \(\binom{n}{k}\), represents the number of ways you can choose k items from a set of n distinct items. These coefficients are central to the binomial theorem as they determine the weights of the terms in the expansion of a binomial expression like \( (u-v)^5 \).
When we expand this expression using the binomial theorem, we calculate the binomial coefficients for each term. For example, \(\binom{5}{0}\) equals 1, as there is one way to select zero items from five. Similarly, \(\binom{5}{1}\) equals 5, meaning there are five ways to choose one item from five. These coefficients follow a pattern known as Pascal's Triangle.
Here's a simplified breakdown for visual learners:
When we expand this expression using the binomial theorem, we calculate the binomial coefficients for each term. For example, \(\binom{5}{0}\) equals 1, as there is one way to select zero items from five. Similarly, \(\binom{5}{1}\) equals 5, meaning there are five ways to choose one item from five. These coefficients follow a pattern known as Pascal's Triangle.
Here's a simplified breakdown for visual learners:
- \binom{5}{0}\ (top of the triangle) - always 1
- \binom{5}{1}\ - corresponds to the first line of the triangle
- ...up to
- \binom{5}{5}\ (bottom of the triangle) - also always 1
Polynomial Expression
A polynomial expression consists of variables, coefficients, and exponents combined using addition, subtraction, multiplication, and non-negative integer exponents of variables. In the context of the binomial theorem, the expansion of a binomial, such as \( (u-v)^5 \), results in a polynomial.
Breaking down the terms of our example, \( u^5 - 5u^4v + 10u^3v^2 - 10u^2v^3 + 5uv^4 - v^5 \), each separate expression like \( 5u^4v \) is a term of the polynomial. The highest exponent in the polynomial indicates its degree; thus \( (u-v)^5 \) is a fifth-degree polynomial. These polynomials not only have numerical coefficients but also follow a pattern where the power of u begins at n (our original exponent) and decreases to zero, while the power of v increases from zero to n.
Part of the beauty of polynomial expressions is their predictability. The expanded form of a binomial raised to any integer power can be quickly constructed once you know the binomial coefficients, allowing for a consistent and organized approach to solving polynomial equations.
Breaking down the terms of our example, \( u^5 - 5u^4v + 10u^3v^2 - 10u^2v^3 + 5uv^4 - v^5 \), each separate expression like \( 5u^4v \) is a term of the polynomial. The highest exponent in the polynomial indicates its degree; thus \( (u-v)^5 \) is a fifth-degree polynomial. These polynomials not only have numerical coefficients but also follow a pattern where the power of u begins at n (our original exponent) and decreases to zero, while the power of v increases from zero to n.
Part of the beauty of polynomial expressions is their predictability. The expanded form of a binomial raised to any integer power can be quickly constructed once you know the binomial coefficients, allowing for a consistent and organized approach to solving polynomial equations.
Summation Notation
Summation notation—indicated by the Greek letter Sigma (Σ)—is a convenient way to express the addition of a sequence of values. It is often used in the binomial theorem to simplify the representation of polynomial expansion. This compact form captures a potentially lengthy process in a single expression.
For instance, the summation notation for our binomial expression \( (u-v)^5 \) is written as \[\sum_{k=0}^{5} \binom{5}{k} u^{5-k} (-v)^{k}\]. This tells us to sum the terms when k takes on each integer value from 0 to 5. Each term consists of a binomial coefficient \(\binom{5}{k}\), a power of u (decreasing as k increases), and a power of v (increasing as k increases).
When using summation notation, it’s vital to carefully calculate each term for every value of k within the stated range, following the binomial theorem pattern.
For instance, the summation notation for our binomial expression \( (u-v)^5 \) is written as \[\sum_{k=0}^{5} \binom{5}{k} u^{5-k} (-v)^{k}\]. This tells us to sum the terms when k takes on each integer value from 0 to 5. Each term consists of a binomial coefficient \(\binom{5}{k}\), a power of u (decreasing as k increases), and a power of v (increasing as k increases).
When using summation notation, it’s vital to carefully calculate each term for every value of k within the stated range, following the binomial theorem pattern.