Chapter 3: Problem 42
Every prime number except 2 and 3 has the form \(6 q+1\) or \(6 q+5\) for some integer \(q\).
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Chapter 3: Problem 42
Every prime number except 2 and 3 has the form \(6 q+1\) or \(6 q+5\) for some integer \(q\).
These are the key concepts you need to understand to accurately answer the question.
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Compute \(\lfloor x\rfloor\) and \(\lceil x\rceil\) for each of the values of \(x\) in \(1-4\). $$ 17 / 4 $$
Definition: The least common multiple of two nonzero integers \(a\) and \(b\), denoted \(\operatorname{lcm}(a, b)\), is the positive integer \(c\) such that a. \(a \mid c\) and \(b \mid c\) b. for all integers \(m\), if \(a \mid m\) and \(b \mid m\), then \(c \mid m\). Prove that for all positive integers \(a\) and \(b, \operatorname{gcd}(a, b)=\) \(\operatorname{lcm}(a, b)\) if, and only if \(a=b\).
a. Prove that if \(a, d, q\), and \(r\) are integers such that \(a=\) \(d q+r\) and \(0
\leq r
Assume that \(m\) and \(n\) are particular integers. \(\begin{array}{ll}\text { a. Is } 6 m+8 n \text { even? } & \text { b. Is } 10 m n+7 \text { odd? }\end{array}\) c. If \(m>n>0\), is \(m^{2}-n^{2}\) composite?
Theorem: The difference between any odd integer and any even integer is odd. "Proof: Suppose \(n\) is any odd integer, and \(m\) is any even integer. By definition of odd, \(n=2 k+1\) where \(k\) is an integer, and by definition of even, \(m=2 k\) where \(k\) is an integer. Then \(n-m=(2 k+1)-2 k=1 .\) But 1 is odd. Therefore, the difference between any odd integer and any even integer is odd."
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