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Assume that \(m\) and \(n\) are particular integers. \(\begin{array}{ll}\text { a. Is } 6 m+8 n \text { even? } & \text { b. Is } 10 m n+7 \text { odd? }\end{array}\) c. If \(m>n>0\), is \(m^{2}-n^{2}\) composite?

Short Answer

Expert verified
In summary, the expression \(6m + 8n\) is always even, the expression \(10mn + 7\) is always odd, and the expression \(m^2 - n^2\) is composite when \(m > n > 0\).

Step by step solution

01

Part a - Analyzing \(6m + 8n\)

Given the expression \(6m + 8n\), we need to check if it is even for integer values of \(m\) and \(n\). Recall that an even integer is divisible by \(2\). Let's rewrite the expression to better visualize its factors: \[6m + 8n = 2(3m) + 2(4n) = 2(3m + 4n) \] Since \(3m + 4n\) is an integer, the expression \(6m + 8n\) is divisible by \(2\) and is therefore even.
02

Part b - Analyzing \(10mn + 7\)

Given the expression \(10mn + 7\), we need to check if it is odd for integer values of \(m\) and \(n\). Recall that an odd integer is one that is not divisible by \(2\). Let's rewrite the expression to better visualize its factors: \[10mn + 7 = 2(5mn) + 7 \] As we can see, the expression \(10mn\) will always be even as it is divisible by \(2\). Therefore, \(10mn + 7\) will always be odd, regardless of the specific integer values of \(m\) and \(n\).
03

Part c - Analyzing \(m^2 - n^2\) under given conditions

Given the expression \(m^2 - n^2\) and the conditions that \(m > n > 0\), we need to determine if the expression results in a composite number. Recall that a composite number is a positive integer that has at least three distinct factors - 1, itself, and at least one other number. A prime number, by contrast, has exactly two distinct factors (1 and itself). First, let's factor the expression: \[m^2 - n^2 = (m + n)(m - n) \] Since both \(m + n\) and \(m - n\) are integers that are greater than 1, and neither is equal to itself when multiplied, we can conclude that \(m^2 - n^2\) is a composite number under the given conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Mathematics
Discrete mathematics is a branch of mathematics that deals with distinct and separate values, rather than continuous ranges. It includes a variety of topics such as logic, set theory, graph theory, and number theory. In number theory, concepts like even and odd integers play a crucial role. For instance, in solving an expression like \(6m + 8n\) for integers \(m\) and \(n\), discrete mathematics allows us to understand how integer properties influence the evenness or oddness of the result.

In our exercise, by factoring out the common term of 2, we simplified the algebraic expression to show that the sum will always be even. This step-by-step manipulation of equations is a cornerstone of discrete mathematics, where finite structures are carefully analyzed to reach logical conclusions.
Integer Properties
Integers are the set of whole numbers and their opposites. Understanding the properties of integers is essential in elementary number theory, which is part of discrete mathematics. One fundamental property is the classification of integers into even and odd. An even integer can be written in the form \(2k\), where \(k\) is an integer, indicating it is divisible by 2. An odd integer, however, is of the form \(2k + 1\), and is not divisible by 2.

When we analyze expressions like \(6m + 8n\) and \(10mn + 7\), it is these properties that determine the evenness or oddness of the results. Moreover, the concept of divisibility and factors of integers influence our understanding of composite numbers, as we will see in the next section.
Composite Numbers
Composite numbers are integers that have more than two distinct positive divisors. This means that aside from 1 and the number itself, a composite number can be divided by other integers without leaving a remainder. In contrast to prime numbers, which can only be divided by 1 and themselves, composite numbers can be broken down into smaller factors.

In our exercise, the expression \(m^2 - n^2\) is factored into \((m + n)(m - n)\). Because \(m > n > 0\), both factors \((m + n)\) and \((m - n)\) are greater than 1 and different from each other, proving that the result will always be a composite number. This follows the definition of a composite number having at least three distinct factors. Breaking down this expression helps students grasp the concept of factorization, a pivotal aspect in understanding composite numbers.

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Most popular questions from this chapter

When expressions of the form \((x-r)(x-s)\) are multiplied out, a quadratic polynomial is obtained. For instance, \((x-2)(x-(-7))=(x-2)(x+7)=x^{2}+5 x-14 .\) \(H\) a. What can be said about the coefficients of the polynomial obtained by multiplying out \((x-r)(x-s)\) when both \(r\) and \(s\) are odd integers? when both \(r\) and \(s\) are even integers? when one of \(r\) and \(s\) is even and the other is odd? b. It follows from part (a) that \(x^{3}-1253 x+255\) cannot be written as a product of two polynomials with integer coefficients. Explain why this is so.

Every prime number except 2 and 3 has the form \(6 q+1\) or \(6 q+5\) for some integer \(q\).

In a certain town \(2 / 3\) of the adult men are married to \(3 / 5\) of the adult women. Assume that all marriages are monogamous (no one is married to more than one other person). Also assume that there are at least 100 adult men in the town. What is the least possible number of adult men in the town? of adult women in the town?

Two athletes run a circular track at a steady pace so that the first completes one round in 8 minutes and the second in 10 minutes. If they both start from the same spot at \(4 \mathrm{PM}\)., when will be the first time they return to the start together?

An alternative proof of the infinitude of the prime numbers begins as follows: Proof: Suppose there are only finitely many prime numbers. Then one is the largest. Call it \(p\). Let \(M=p !+1\). We will show that there is a prime number \(q\) such that \(q>p\). Complete this proof.

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