Chapter 3: Problem 23
Prove that \(\sqrt{2}+\sqrt{3}\) is irrational.
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Chapter 3: Problem 23
Prove that \(\sqrt{2}+\sqrt{3}\) is irrational.
These are the key concepts you need to understand to accurately answer the question.
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Assume that \(m\) and \(n\) are particular integers. \(\begin{array}{ll}\text { a. Is } 6 m+8 n \text { even? } & \text { b. Is } 10 m n+7 \text { odd? }\end{array}\) c. If \(m>n>0\), is \(m^{2}-n^{2}\) composite?
Use the results of exercises 28 and 30 to determine whether the following numbers are prime. a. 9,269 b. 9,103 c. 8,623 d. 7,917
Prove that there exists a unique prime number of the form \(n^{2}-1\), where \(n\) is an integer that is greater than or equal to 2 .
a. Use the properties of inequalities in Appendix A to prove that for all integers \(r, s\), and \(n\), if \(r>\sqrt{n}\) and \(s>\sqrt{n}\) then \(r s>n\). \(\boldsymbol{H}\) b. Use proof by contraposition and the result of part (a) to show that for all integers \(n>1\), if \(n\) is not divisible by any positive integer that is greater than 1 and less than or equal to \(\sqrt{n_{+}}\)then \(n\) is prime. c. Use proof by contraposition and the result of part (b) to show that for all integers \(n>1\), if \(n\) is not divisible by any prime number less than or equal to \(\sqrt{n}\), then \(n\) is prime.
For all integers \(m\), if \(m>2\) then \(m^{2}-4\) is composite.
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