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Write out \(\exists ! x P(x),\) where the domain consists of the integers \(1,2,\) and \(3,\) in terms of negations, conjunctions, and disjunctions.

Short Answer

Expert verified
\((P(1) \land eg P(2) \land eg P(3))\lor (P(2) \land eg P(1) \land eg P(3))\lor (P(3) \land eg P(1) \land eg P(2))\).

Step by step solution

01

- Understanding the Statement

The statement \(\exists ! x P(x)\) means 'there exists a unique x such that P(x) is true'. We need to express this using negations (卢), conjunctions (\(\land\)), and disjunctions (\(\lor\)).
02

- Identify the Domain

The domain consists of the integers 1, 2, and 3. So, we will consider each of these integers as the possible values for x.
03

- Express Unique Existence

The unique existence means that there is exactly one x out of 1, 2, and 3 for which P(x) is true, and for the others, P(x) should be false.
04

- Combining Statements

We need to combine all possibilities: \(P(1)\land\( \eg P(2)\land\ \eg P(3)\)\), \(P(2)\ \land\(\ \eg P(1)\land\ \eg P(3)\)\), and \(P(3)\land\(\ \eg P(1)\land\ \eg P(2)\).\)
05

- Form the Final Expression

Finally, write the disjunction of all these combined statements: \((P(1) \land \eg P(2) \land \eg P(3))\lor\ (P(2) \land \eg P(1) \land \eg P(3))\lor\ (P(3) \land \eg P(1) \land \eg P(2))\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negations
Negations are essential in mathematical logic and play a crucial role in expressing statements in a clear and precise manner. A negation essentially denies the truth value of a given proposition. If a proposition P(x) is 'true,' then eg P(x) means 'P(x) is not true,' or 'P(x) is false.'

In our exercise, the domain consists of integers 1, 2, and 3, and we need to express eg P(x) for each of these values. For instance, eg P(1) means that 'P(1) is not true.'

Negations help in forming expressions that capture the true essence of the unique existential quantifier. By using negations, we ensure that none of the other values in the domain satisfy the condition P(x) when one specific value does.
Conjunctions
Conjunctions combine multiple statements and present them as a single joint statement. In logic, this is denoted by \land, which represents the logical 'and.' For a conjunction to be true, all individual components must be true.

In our exercise, we use conjunctions to link the truth value of P(x) with the falsehood of P for other values in the domain. For instance, we write this as \(P(1) \land eg P(2) \land eg P(3)\) to mean 'P(1) is true and P(2) is not true and P(3) is not true.'

Conjunctions are integral in ensuring that all necessary conditions are met simultaneously. They help us express the idea that a particular value makes P(x) true while ensuring other values do not.
Disjunctions
Disjunctions allow for flexibility in statements by presenting options. Denoted by \(\lor\), disjunctions represent the logical 'or'. A disjunction is true if at least one of the individual statements it connects is true.

In our exercise, disjunctions connect the different scenarios where exactly one value in the domain satisfies P(x). For example, \(P(1) \land eg P(2) \land eg P(3))\lor\ (P(2) \land eg P(1) \land eg P(3))\lor\ (P(3) \land eg P(1) \land eg P(2))\) states that either 'P(1) is true and the others are not', 'P(2) is true and the others are not,' or 'P(3) is true and the others are not.'

Disjunctions are essential for combining multiple logical possibilities into a comprehensive statement. They make it possible to express the full range of scenarios that meet the unique existence condition.

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Most popular questions from this chapter

Express each of these statements using quantifiers. Then form the negation of the statement so that no negation is to the left of a quantifier. Next, express the negation in simple English. (Do not simply use the phrase "It is not the case that.") a) No one has lost more than one thousand dollars playing the lottery. b) There is a student in this class who has chatted with exactly one other student. c) No student in this class has sent e-mail to exactly two other students in this class. d) Some student has solved every exercise in this book. e) No student has solved at least one exercise in every section of this book.

Prove that these four statements about the integer \(n\) are equivalent: \((i) n^{2}\) is odd, \((i i) 1-n\) is even, \((i i i) n^{3}\) is odd (iv) \(n^{2}+1\) is even.

For each of these sets of premises, what relevant conclusion or conclusions can be drawn? Explain the rules of inference used to obtain each conclusion from the premises. a) 鈥淚f I play hockey, then I am sore the next day.鈥 鈥淚 use the whirlpool if I am sore.鈥 鈥淚 did not use the whirlpool.鈥 b) 鈥淚f I work, it is either sunny or partly sunny.鈥 鈥淚 worked last Monday or I worked last Friday.鈥 鈥淚t was not sunny on Tuesday.鈥 鈥淚t was not partly sunny on Friday.鈥 c) 鈥淎ll insects have six legs.鈥 鈥淒ragonflies are insects.鈥 鈥淪piders do not have six legs.鈥 鈥淪piders eat dragon-flies.鈥 d) 鈥淓very student has an Internet account.鈥 鈥淗omer does not have an Internet account.鈥 鈥淢aggie has an Internet account.鈥 e) 鈥淎ll foods that are healthy to eat do not taste good.鈥 鈥淭ofu is healthy to eat.鈥 鈥淵ou only eat what tastes good.鈥 鈥淵ou do not eat tofu.鈥 鈥淐heeseburgers are not healthy to eat.鈥 f ) 鈥淚 am either dreaming or hallucinating.鈥 鈥淚 am not dreaming.鈥 鈥淚f I am hallucinating, I see elephants running down the road.鈥

Use resolution to show that the compound proposition \((p \vee q) \wedge(\neg p \vee q) \wedge(p \vee \neg q) \wedge(\neg p \vee \neg q)\) is not satisfiable.

Express each of these statements using mathematical and logical operators, predicates, and quantifiers, where the domain consists of all integers. a) The sum of two negative integers is negative. b) The difference of two positive integers is not necessarily positive. c) The sum of the squares of two integers is greater than or equal to the square of their sum. d) The absolute value of the product of two integers is the product of their absolute values.

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