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Show that \(p \downarrow q\) is logically equivalent to \(\neg(p \vee q)\)

Short Answer

Expert verified
\( p \downarrow q \equiv \eg(p \vee q) \)

Step by step solution

01

Understand the Notation

The symbol \(p \downarrow q\) represents the logical NOR operation. It is defined as true when both \(p\) and \(q\) are false. The goal is to show its equivalence to \(eg(p \vee q)\).
02

Express in Terms of Basic Operations

Express \(p \downarrow q\) using basic logical operations. \(p \downarrow q\) means both \(p\) and \ q\ are not true: \(eg p \wedge \eg q\).
03

Distribute the Negation

Apply De Morgan's Law to the expression \(eg p \wedge \eg q\). According to De Morgan's Law, \(eg p \wedge \eg q\) is equivalent to \(eg(p \vee q)\).
04

Conclude the Equivalence

Since \(p \downarrow q\) can be rewritten as \(eg(p \vee q)\), we have shown that \(p \downarrow q\) is logically equivalent to \(eg(p \vee q)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logical NOR
The logical NOR operation, denoted as \(p \downarrow q\), is a fundamental concept in logic and computer science. NOR stands for 'Not OR'. It combines two statements \(p\) and \(q\) and produces a true value only when both \(p\) and \(q\) are false. This operation is essentially the negation of the OR operator \(\vee\). In other words, for any two propositions \(p\) and \(q\), \(p \downarrow q\) is the equivalent of saying that neither \(p\) nor \(q\) are true. It's a versatile operator used in various logic circuits and computational designs due to its simplicity and expressive power.

To understand it better, consider the truth table for the NOR operation:

- When both \(p\) and \(q\) are false (0), \(p \downarrow q\) is true (1).
- If either \(p\) is true (1) and \(q\) is false (0), or \(p\) is false (0) and \(q\) is true (1), \(p \downarrow q\) is false (0).
- When both \(p\) and \(q\) are true (1), \(p \downarrow q\) is false (0).

Understanding the logical NOR operation is key to grasping more intricate logical constructs, as it often serves as a building block for more complex expressions.
De Morgan's Laws
De Morgan's Laws are critical rules in boolean algebra and logic that govern the relationships between conjunctions (AND) and disjunctions (OR) within the context of negations. These laws provide a way to simplify complex logic expressions and are named after the British mathematician Augustus De Morgan.

The laws are articulated as follows:
  • The negation of a disjunction (OR) is equal to the conjunction (AND) of the negations: \( eg (p \vee q) \equiv (eg p \wedge eg q) \).
  • The negation of a conjunction (AND) is equal to the disjunction (OR) of the negations: \( eg (p \wedge q) \equiv (eg p \vee eg q) \).

Applying these laws allows us to move from one form of expression to another logically equivalent form, aiding in the simplification and understanding of logic problems.

In the context of the exercise, we used De Morgan's Law to transform \( eg p \wedge eg q \) into \( eg (p \vee q) \). This transformation helps in demonstrating that the logical NOR operation \( p \downarrow q \) is indeed equivalent to \( eg (p \vee q) \).
basic logical operations
Basic logical operations form the foundation of logic and are crucial for solving more advanced logical problems. The primary operations include:
  • Conjunction (AND) \(\wedge\): This operation is true if and only if both operands are true. For instance, \(p \wedge q\) is true only when both \(p\) and \(q\) are true.
  • Disjunction (OR) \(\vee\): This operation is true if at least one of the operands is true. Thus, \(p \vee q\) is true when at least one of \(p\) or \(q\) is true.
  • Negation (NOT) \(eg\): This operation inverts the truth value of a proposition. If \(p\) is true, \(eg p\) is false, and vice versa.

Understanding these basic operations makes it easier to build and comprehend more complicated logical expressions (like those involving NOR and De Morgan鈥檚 Laws). For instance, being able to express \(p \downarrow q\) in terms of basic operations as \(eg p \wedge eg q\) allows us to apply De Morgan鈥檚 Law smoothly, showing the equivalence \( eg (p \vee q) \).

Mastering these operations is essential for solving logical problems, as they provide the tools needed for constructing and breaking down logical statements effectively.

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Most popular questions from this chapter

Translate in two ways each of these statements into logical expressions using predicates, quantifiers, and logical connectives. First, let the domain consist of the students in your class and second, let it consist of all people. a) Someone in your class can speak Hindi. b) Everyone in your class is friendly. c) There is a person in your class who was not born in California. d) A student in your class has been in a movie. e) No student in your class has taken a course in logic programming.

Find all squares, if they exist, on an \(8 \times 8\) checkerboard such that the board obtained by removing one of these squares can be tiled using straight triominoes. [Hint: First use arguments based on coloring and rotations to eliminate as many squares as possible from consideration. \(]\)

For each of these arguments, explain which rules of inference are used for each step. a) 鈥淟inda, a student in this class, owns a red convertible. Everyone who owns a red convertible has gotten at least one speeding ticket. Therefore, someone in this class has gotten a speeding ticket.鈥 b) 鈥淓ach of five roommates, Melissa, Aaron, Ralph, Veneesha, and Keeshawn, has taken a course in discrete mathematics. Every student who has taken a course in discrete mathematics can take a course in algorithms. Therefore, all five roommates can take a course in algorithms next year.鈥 c) 鈥淎ll movies produced by John Sayles are wonder-ful. John Sayles produced a movie about coal miners. Therefore, there is a wonderful movie about coal miners.鈥 d) 鈥淭here is someone in this class who has been to France. Everyone who goes to France visits the Louvre. Therefore, someone in this class has visited the Louvre.鈥

Use quantifiers and logical connectives to express the fact that a quadratic polynomial with real number coefficients has at most two real roots.

Show that the two statements \(\neg \exists x \forall y P(x, y)\) and \(\forall x \exists y \neg P(x, y),\) where both quantifiers over the first variable in \(P(x, y)\) have the same domain, and both quantifiers over the second variable in \(P(x, y)\) have the same domain, are logically equivalent.

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