/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Prove or disprove that if you ha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Prove or disprove that if you have an 8 -gallon jug of water and two empty jugs with capacities of 5 gallons and 3 gallons, respectively, then you can measure 4 gallons by successively pouring some of or all of the water in a jug into another jug.

Short Answer

Expert verified
Yes, you can measure 4 gallons using the given steps.

Step by step solution

01

- Initial Setup

Start with the 8-gallon jug full (8 gallons), and the 5-gallon and 3-gallon jugs empty.
02

- Fill the 5-gallon jug

Pour water from the 8-gallon jug into the 5-gallon jug until it is full. You now have 3 gallons left in the 8-gallon jug and the 5-gallon jug is full.
03

- Transfer Water to 3-gallon jug

Pour water from the 5-gallon jug into the 3-gallon jug until the 3-gallon jug is full. Now, you have 5 gallons in the 8-gallon jug, 2 gallons in the 5-gallon jug, and 3 gallons in the 3-gallon jug.
04

- Empty the 3-gallon jug

Empty the 3-gallon jug. Now, you have 5 gallons in the 8-gallon jug, 2 gallons in the 5-gallon jug, and 0 gallons in the 3-gallon jug.
05

- Transfer remaining water from 5-gallon to 3-gallon jug

Pour the 2 gallons from the 5-gallon jug into the 3-gallon jug. Now, you have 5 gallons in the 8-gallon jug, 0 gallons in the 5-gallon jug, and 2 gallons in the 3-gallon jug.
06

- Fill the 5-gallon jug again

Pour water from the 8-gallon jug into the 5-gallon jug until it is full. Now, you have 0 gallons in the 8-gallon jug, 5 gallons in the 5-gallon jug, and 2 gallons in the 3-gallon jug.
07

- Transfer water from 5-gallon to 3-gallon jug again

Pour water from the 5-gallon jug into the 3-gallon jug until the 3-gallon jug is full. This action will leave 4 gallons in the 5-gallon jug and 3 gallons in the 3-gallon jug.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Problem-Solving with the Water Jug Problem
The Water Jug Problem is a captivating exercise in discrete mathematics that delves into the practical applications of problem-solving techniques. The goal is to measure exactly 4 gallons using an 8-gallon jug and two empty jugs of capacities 5 gallons and 3 gallons, respectively. The essence of problem-solving here involves identifying a systematic approach and following it meticulously. By breaking the problem into manageable parts, you can track the water movements between the jugs step-by-step, ensuring a logical progression toward the solution.

Problems like this aid in improving critical thinking skills and the use of logic to arrive at solutions. The Water Jug Problem challenges students to think creatively and apply logical reasoning, thereby enhancing their analytical abilities.

Understanding the Algorithm
An algorithm is a step-by-step procedure or formula for solving a problem. The Water Jug Problem can be tackled using a sequence of well-defined steps. Let's walk through the steps to reach our goal of measuring exactly 4 gallons:

Step 1: Start with the 8-gallon jug full and both 5-gallon and 3-gallon jugs empty.
Step 2: Pour water from the 8-gallon jug into the 5-gallon jug until it is full. You will have 3 gallons remaining in the 8-gallon jug.
Step 3: Transfer water from the 5-gallon jug to the 3-gallon jug until the 3-gallon jug is full. This will leave you with 2 gallons in the 5-gallon jug.
Step 4: Empty the 3-gallon jug.
Step 5: Transfer the remaining 2 gallons from the 5-gallon jug into the 3-gallon jug.
Step 6: Refill the 5-gallon jug from the 8-gallon jug.
Step 7: Finally, transfer enough water from the 5-gallon jug to the 3-gallon jug to fill it up. This will leave exactly 4 gallons in the 5-gallon jug.

Following this algorithm ensures that you can measure exactly 4 gallons despite the seemingly complicated setup.

Proof Techniques Applied
In discrete mathematics, proof techniques are essential for demonstrating the validity of a solution. The Water Jug Problem utilizes a constructive proof technique. This means that by constructing a series of steps, we can show how the desired outcome (measuring exactly 4 gallons) can be achieved.

A constructive proof is particularly beneficial because it does more than just claiming the possibility of a solution; it provides the actual method to achieve it. Each step in the solution can be verified individually, ensuring the correctness of the entire procedure. As you follow the steps, you can see that no step violates any of the problem's constraints.

This meticulous verification further solidifies the solution's reliability and represents the application of logical and proof-based approaches in problem-solving.

Step-by-Step Solution Breakdown
Breaking down the solution into smaller, more digestible steps is a great way to understand and solve complex problems. In the Water Jug Problem, each step logically follows from the previous one, allowing for a clear and concise progression towards the goal.

Step 1: Initial Setup: Start with the 8-gallon jug full, and both 5-gallon and 3-gallon jugs empty.

Step 2: Fill the 5-gallon jug from the 8-gallon jug, leaving 3 gallons in the 8-gallon jug.

Step 3: Transfer water to the 3-gallon jug, leaving 2 gallons in the 5-gallon jug.

Step 4: Empty the 3-gallon jug to proceed.

Step 5: Pour the 2 gallons from the 5-gallon jug into the 3-gallon jug.

Step 6: Fill the 5-gallon jug again from the 8-gallon jug.

Step 7: Finally, transfer water from the 5-gallon jug to the 3-gallon jug until the latter is full, leaving 4 gallons in the 5-gallon jug.

By breaking the problem into these steps, it becomes easier to manage and ultimately solve, while gaining a deeper understanding of the underlying concepts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any two unequal bits you insert a 1 to produce nine new bits. Then you erase the nine original bits. Show that when you iterate this procedure, you can never get nine zeros. [Hint: Work backward, assuming that you did end up with nine zeros.]

Formulate a conjecture about the final two decimal digits of the square of an integer. Prove your conjecture using a proof by cases.

Use a proof by cases to show that \(\min (a, \min (b, c))=\) \(\min (\min (a, b), c)\) whenever \(a, b,\) and \(c\) are real numbers.

Express each of these statements using quantifiers. Then form the negation of the statement so that no negation is to the left of a quantifier. Next, express the negation in simple English. (Do not simply use the phrase "It is not the case that.") a) No one has lost more than one thousand dollars playing the lottery. b) There is a student in this class who has chatted with exactly one other student. c) No student in this class has sent e-mail to exactly two other students in this class. d) Some student has solved every exercise in this book. e) No student has solved at least one exercise in every section of this book.

A statement is in prenex normal form (PNF) if and only if it is of the form $$ Q_{1} x_{1} Q_{2} x_{2} \cdots Q_{k} x_{k} P\left(x_{1}, x_{2}, \ldots, x_{k}\right) $$ where each \(Q_{i}, i=1,2, \ldots, k,\) is either the existential quantifier or the universal quantifier, and \(P\left(x_{1}, \ldots, x_{k}\right)\) is a predicate involving no quantifiers. For example, \(\exists x \forall y(P(x, y) \wedge Q(y))\) is in prenex normal form, whereas \(\exists x P(x) \vee \forall x Q(x)\) is not (because the quantifiers do not all occur first). Every statement formed from propositional variables, predicates, \(\mathbf{T},\) and \(\mathbf{F}\) using logical connectives and quantifiers is equivalent to a statement in prenex normal form. Exercise 51 asks for a proof of this fact. Show how to transform an arbitrary statement to a statement in prenex normal form that is equivalent to the given statement. (Note: A formal solution of this exercise requires use of structural induction, covered in Section \(5.3 . )\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.