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Each of Exercises \(20-32\) asks you to show that two compound propositions are logically equivalent. To do this, either show that both sides are true, or that both sides are false, for exactly the same combinations of truth values of the propositional variables in these expressions (whichever is easier). Show that \((p \rightarrow r) \vee(q \rightarrow r)\) and \((p \wedge q) \rightarrow r\) are \(\operatorname{logi}-\)cally equivalent.

Short Answer

Expert verified
Both columns for \(p \rightarrow r \vee q \rightarrow r\) and \(p \wedge q \rightarrow r\) have the same truth values, showing logical equivalence.

Step by step solution

01

- List Truth Values

Consider the truth values for the propositional variables p, q, and r. There are 8 possible combinations of truth values for these variables.
02

- Construct Truth Table

Create a truth table with columns for p, q, r, \(p \rightarrow r\), \(q \rightarrow r\), \(p \rightarrow r \vee q \rightarrow r\), \(p \wedge q\), and \(p \wedge q \rightarrow r\). Fill out the table for all possible truth values of p, q, and r.
03

- Compute p → r and q → r

Use the implication rule to find the truth values of \(p \rightarrow r\) and \(q \rightarrow r\) for each combination of truth values. Recall that \(p \rightarrow r\) is false only when p is true and r is false. Similarly, \(q \rightarrow r\) is false only when q is true and r is false.
04

- Compute (p → r) ∨ (q → r)

Determine the truth values for \(p \rightarrow r \vee q \rightarrow r\) by taking the disjunction (OR) of \(p \rightarrow r\) and \(q \rightarrow r\). The result is true if at least one of \(p \rightarrow r\) or \(q \rightarrow r\) is true.
05

- Compute (p ∧ q)

Determine the truth value of \(p \wedge q\) by taking the conjunction (AND) of p and q. The result is true only if both p and q are true.
06

- Compute (p ∧ q) → r

Determine the truth values for \(p \wedge q \rightarrow r\) using the implication rule. \(p \wedge q \rightarrow r\) is false only when \(p \wedge q\) is true and r is false.
07

- Compare Columns

Compare the columns of \(p \rightarrow r \vee q \rightarrow r\) and \(p \wedge q \rightarrow r\) in the truth table. If these columns match for all combinations of truth values, then the propositions are logically equivalent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Propositional Variables
Propositional variables are the building blocks of propositional logic. They are symbols, usually represented by letters such as p, q, and r, that stand for specific propositions or statements. Each propositional variable can either be true (T) or false (F). These truth values are fundamental in determining the overall truth of compound propositions.
For example, in the exercise where we work with the variables p, q, and r, each one can independently be true or false. This gives us 8 possible combinations of truth values when considering all three variables together.
  • (T, T, T)
  • (T, T, F)
  • (T, F, T)
  • (T, F, F)
  • (F, T, T)
  • (F, T, F)
  • (F, F, T)
  • (F, F, F)
Understanding how these variables interact in logical operations is crucial for working through propositional logic problems.
Truth Table
A truth table is a tool used to systematically determine the truth value of a compound proposition for all possible truth values of its constituent propositional variables. It lists all possible combinations of truth values of the variables and the resultant truth value of the compound proposition.
To show that two propositions are logically equivalent, we use a truth table to compare their truth values for every possible combination of truth values of the variables involved. For our exercise, the truth table includes columns for p, q, r, as well as the intermediate and final expressions like \(p \rightarrow r\), \(q \rightarrow r\), \((p \rightarrow r) \vee \ (q \rightarrow r)\), \(p \wedge q\), and \((p \wedge q) \rightarrow r\).
By filling out this table, we can visually confirm if the columns for two expressions match and hence, determine their logical equivalence.
Implication Rule
The implication rule in propositional logic is expressed by the operator \( \rightarrow \). A proposition \(p \rightarrow r\) (read as 'p implies r') is false only if p is true and r is false. In all other cases, the implication is true.
For example, consider \(p = T\) and \(r = F\). Here, \(p \rightarrow r = F\) because we have a true antecedent leading to a false consequent. However, if p were false regardless of r's truth value, or if both were true, the implication would be true.
This rule is essential for computing truth values in implication expressions in our truth table and plays a central role in determining the logical equivalence of propositions.
Disjunction
Disjunction is another fundamental logical operation, denoted by the operator \( \vee \). It represents an 'OR' operation. A disjunction \(p \vee q\) is true if at least one of p or q is true. It is false only when both p and q are false.
For the expression \((p \rightarrow r) \vee (q \rightarrow r)\), we need to find the truth value of \(p \rightarrow r\) and \(q \rightarrow r\) individually and then apply the disjunction rule. If either \(p \rightarrow r\) or \(q \rightarrow r\) is true, the result will be true.
Understanding disjunction helps us correctly fill out the truth table and determine the truth value of compound propositions involving 'OR'.
Conjunction
Conjunction is represented by the operator \( \wedge \) and signifies an 'AND' operation. A conjunction \(p \wedge q\) is true only if both p and q are true. It is false if either or both of the variables are false.
In our exercise, we calculate the truth value of \(p \wedge q\) to use it in further compound propositions such as \((p \wedge q) \rightarrow r\). The conjunction provides a basis for how these variables combine together under the 'AND' operation.
This is crucial because recognizing these truth values helps us construct and compare the necessary columns in the truth table to show logical equivalence.

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