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Prove that there is a positive integer that equals the sum of the positive integers not exceeding it. Is your proof constructive or nonconstructive?

Short Answer

Expert verified
n = 1 is a positive integer that equals the sum of the positive integers not exceeding it. The proof is constructive.

Step by step solution

01

- Define the Problem

We need to find a positive integer, say n, such that n is equal to the sum of all positive integers not exceeding it. This means finding n for which \[ n = 1 + 2 + 3 + \cdots + (n-1) + n \]
02

- Use the Sum Formula

Recall the formula for the sum of the first k positive integers: \[ \text{Sum} = \frac{k(k+1)}{2} \]. We need n to be such that \[ n = \frac{n(n+1)}{2}. \]
03

- Set Up the Equation

Setting our equation from step 2, we get: \[ n = \frac{n(n+1)}{2}. \] Multiply both sides by 2 to clear the fraction: \[ 2n = n(n + 1). \]
04

- Simplify the Equation

Rearrange the equation to isolate n: \[ 2n = n^2 + n. \] Then move all terms to one side to form a quadratic equation: \[ n^2 - n = 0. \]
05

- Solve the Quadratic Equation

Factor out n from the equation: \[ n(n - 1) = 0. \] This gives us two solutions: \[ n = 0 \text{ or } n = 1. \] Since we are looking for a positive integer, we select \[ n = 1. \]
06

- Verify the Solution

Check that n = 1 satisfies the initial condition: \[ 1 = 1, \] which is true. Hence, n = 1 is indeed a solution.
07

- Proof Type

Since we provided a specific example that meets the condition, the proof is constructive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Positive Integers
When we refer to positive integers, we mean numbers that are greater than zero and do not contain any decimal or fractional part. Examples of positive integers include 1, 2, 3, and so on. Understanding positive integers is fundamental when working on many mathematical problems. They are straightforward and matter because they form the basic building blocks of number theory and are used to count discrete objects.
Sum Formula
The sum formula for the first k positive integers is a handy tool in mathematics. It allows you to quickly calculate the sum of any series of consecutive positive integers without having to add each number individually. The formula is: \[ \text{Sum} = \frac{k(k+1)}{2} \]
This formula works by pairing numbers from opposite ends of the range, simplifying the calculation. For example, for the first four positive integers: 1 + 2 + 3 + 4, you can pair them as (1+4) and (2+3), which both sum to 5. Multiplying the number of pairs (2) by 5 gets you 10, which indeed is the sum. Hence, the formula simplifies the addition of large sequences of numbers effortlessly.
Quadratic Equation
A quadratic equation is a polynomial equation of the form \[ ax^2 + bx + c = 0 \]
In our exercise, we derived a quadratic equation while searching for a positive integer, n, where n is equal to the sum of all integers up to and including n. We simplified our equation to: \[ n^2 - n = 0 \]
Solving a quadratic equation often involves factoring, completing the square, or using the quadratic formula. In this case, we factored it as: \[ n(n-1) = 0 \]
This gave solutions n = 0 and n = 1. Since we needed positive integers, we took n = 1 as our solution. Quadratic equations often have two solutions due to the nature of the squared term.
Proof Verification
Proof verification is an essential part of any mathematical proof process. It's what ensures the correctness and reliability of the results obtained. After solving the quadratic equation, we checked if our solution indeed met the initial condition of the problem. In our case, we wanted to ensure that 1 equals the sum of the positive integers not exceeding it.
By substituting n = 1 back into the formula, we verified: \[ 1 = 1 \]
This was true, confirming that our solution was correct. Additionally, we characterized our proof as constructive because we provided a specific example 鈥 n = 1, rather than just showing that at least one such number exists abstractly.

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