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Exercises \(61-64\) are based on questions found in the book Symbolic Logic by Lewis Carroll. Let P(x), Q(x), and R(x) be the statements 鈥渪 is a professor,鈥 鈥渪 is ignorant,鈥 and 鈥渪 is vain,鈥 respectively. Express each of these statements using quantifiers; logical connectives; and P(x), Q(x), and R(x), where the domain consists of all people. $$ \begin{array}{l}{\text { a) No professors are ignorant. }} \\ {\text { b) All ignorant people are vain. }} \\ {\text { c) No professors are vain. }} \\\ {\text { d) Does (c) follow from (a) and (b)? }}\end{array} $$

Short Answer

Expert verified
Yes, (c) follows from (a) and (b). Statement (c) logically follows from statements (a) and (b).

Step by step solution

01

Interpret statement (a)

Statement (a) is 'No professors are ignorant.' This can be interpreted as 'For all x, if x is a professor, then x is not ignorant.' Using the symbols: P(x) for 'x is a professor' and Q(x) for 'x is ignorant', we can write this as: \( \forall x (P(x) \rightarrow eg Q(x)) \)
02

Interpret statement (b)

Statement (b) is 'All ignorant people are vain.' This can be interpreted as 'For all x, if x is ignorant, then x is vain.' Using the symbols: Q(x) for 'x is ignorant' and R(x) for 'x is vain', we can write this as: \( \forall x (Q(x) \rightarrow R(x)) \)
03

Interpret statement (c)

Statement (c) is 'No professors are vain.' This can be interpreted as 'For all x, if x is a professor, then x is not vain.' Using the symbols: P(x) for 'x is a professor' and R(x) for 'x is vain', we can write this as: \( \forall x (P(x) \rightarrow eg R(x)) \)
04

Determine if (c) follows from (a) and (b)

To determine whether (c) follows from (a) and (b), we need to check if \( \forall x (P(x) \rightarrow eg R(x)) \) logically follows from the formulas \( \forall x (P(x) \rightarrow eg Q(x)) \) and \( \forall x (Q(x) \rightarrow R(x)) \). From (a), we have: \( \forall x (P(x) \rightarrow eg Q(x)) \). From (b), we have: \( \forall x (Q(x) \rightarrow R(x)) \). Using the contrapositive of (b), we get: \( \forall x (eg R(x) \rightarrow eg Q(x)) \). Therefore, we need to prove: \( \forall x (P(x) \rightarrow eg R(x)) \). Assume P(a) for some arbitrary person a. Then from (a), \( eg Q(a) \). From the contrapositive of (b), \( P(a) \rightarrow eg R(a) \) since \( eg Q(a) \rightarrow eg R(a) \), thus (c) follows from (a) and (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantifiers
Quantifiers are symbols used in logic to express the extent of applicability of a predicate to a subject. There are two main types of quantifiers: universal and existential.
Universal quantifiers (\(\forall\)) denote that a statement applies to all elements within a certain domain. For example, \(\forall x (P(x))\) means 'For all x, P(x) is true.'
Existential quantifiers (\(\there exists\)) indicate that there is at least one element in the domain for which the statement is true. For example, \(\there exists x (P(x))\) means 'There exists at least one x such that P(x) is true.'
In the given exercise:
  • Statement (a) 'No professors are ignorant' uses the universal quantifier \(\forall\) to signify that for every professor, they are not ignorant.
  • Statement (b) 'All ignorant people are vain' also uses the universal quantifier to state that for all ignorant people, they are vain.
  • Statement (c) 'No professors are vain' is expressed similarly using the universal quantifier to declare that no professors possess vanity.
Logical Connectives
Logical connectives are used to combine or modify statements and are crucial for constructing complex logical expressions.
The main logical connectives are:
  • AND (\(\wedge\)): Combines two statements and is true only if both statements are true.
    Example: \(P(x) \wedge Q(x)\) 'x is a professor and x is ignorant.'
  • OR (\(\vee\)): Combines two statements and is true if at least one statement is true.
    Example: \(P(x) \vee Q(x)\) 'x is a professor or x is ignorant.'
  • NOT (\(eg\)): Negates a statement, flipping its truth value.
    Example: \(eg Q(x)\) 'x is not ignorant.'
  • IMPLICATION (\(\rightarrow\)): Indicates that one statement implies another. It's true except when the first statement is true and the second is false.
    Example: \(P(x) \rightarrow eg Q(x)\) 'If x is a professor, then x is not ignorant.'
In our exercise:
  • Statement (a) 'No professors are ignorant' uses \(\rightarrow\) to say 'If x is a professor, then x is not ignorant.'
  • Statement (b) 'All ignorant people are vain' also uses \(\rightarrow\) to imply 'If x is ignorant, then x is vain.'
  • Statement (c) 'No professors are vain' uses \(\rightarrow\) to declare 'If x is a professor, then x is not vain.'
Contrapositive
Contrapositive is a logically equivalent form of an implication, which states that if the negation of the conclusion implies the negation of the premise, then the original implication holds.
In other words, for a statement of the form \(P(x) \rightarrow Q(x)\), its contrapositive is \(eg Q(x) \rightarrow eg P(x)\). If one is true, the other one is also true.
In our exercise, statement (b) 'All ignorant people are vain' or \(\forall x (Q(x) \rightarrow R(x))\) has a contrapositive form: \(\forall x (eg R(x) \rightarrow eg Q(x))\). This helps in proving statement (c).
To determine if statement (c) 'No professors are vain' follows from (a) and (b), we use the contrapositive of (b).
  • From (a): \(\forall x (P(x) \rightarrow eg Q(x))\)
  • From (b): \(\forall x (Q(x) \rightarrow R(x))\) Contrapositive: \(\forall x (eg R(x) \rightarrow eg Q(x))\)
  • Combining these, we deduce: \(\forall x (P(x) \rightarrow eg R(x))\)
This shows that (c) follows from (a) and (b) using contrapositive reasoning.
Implication
Implication (\(\rightarrow\)) is a logical connective that indicates a conditional relationship between two statements. An implication statement \(P(x) \rightarrow Q(x)\) asserts that if the premise \(P(x)\) is true, then the conclusion \(Q(x)\) must also be true.
Key characteristics of implications:
  • The statement \(P(x) \rightarrow Q(x)\) is false only when \(P(x)\) is true and \(Q(x)\) is false.
  • If \(P(x)\) is false, \(Q(x)\) can be either true or false, making the implication true.
In our exercise:
  • Statement (a) 'No professors are ignorant' translates to \(\forall x (P(x) \rightarrow eg Q(x))\), indicating that if x is a professor, then x is not ignorant.
  • Statement (b) 'All ignorant people are vain' translates to \(\forall x (Q(x) \rightarrow R(x))\), indicating that if x is ignorant, then x is vain.
  • Statement (c) 'No professors are vain' translates to \(\forall x (P(x) \rightarrow eg R(x))\), indicating that if x is a professor, then x is not vain.
The exercise involves determining if the statement in (c) can be logically derived using implications from statements (a) and (b). By recognizing that the contrapositive of statement (b) and statement (a) lead to the conclusion in (c), we establish the logical connection.

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Most popular questions from this chapter

Exercises \(61-64\) are based on questions found in the book Symbolic Logic by Lewis Carroll. Let P(x), Q(x), R(x), and S(x) be the statements 鈥渪 is a duck,鈥 鈥渪 is one of my poultry,鈥 鈥渪 is an officer,鈥 and 鈥渪 is willing to waltz,鈥 respectively. Express each of these statements using quantifiers; logical connectives; and P(x), Q(x), R(x), and S(x). a) No ducks are willing to waltz. b) No officers ever decline to waltz. c) All my poultry are ducks. d) My poultry are not officers. e) Does (d) follow from (a), (b), and (c)? If not, is there a correct conclusion?

Determine the truth value of the statement \(\forall x \exists y(x y=1)\) if the domain for the variables consists of a) the nonzero real numbers. b) the nonzero integers. c) the positive real numbers.

For each of these arguments determine whether the argument is correct or incorrect and explain why.a) Everyone enrolled in the university has lived in a dormitory. Mia has never lived in a dormitory. Therefore, Mia is not enrolled in the university. b) A convertible car is fun to drive. Isaac鈥檚 car is not a convertible. Therefore, Isaac鈥檚 car is not fun to drive. c) Quincy likes all action movies. Quincy likes the movie Eight Men Out. Therefore, Eight Men Out is an action movie. d) All lobstermen set at least a dozen traps. Hamilton is a lobsterman. Therefore, Hamilton sets at least a dozen traps.

Use rules of inference to show that if \(\forall x(P(x) \vee Q(x))\) \(\forall x(\neg Q(x) \vee S(x)), \quad \forall x(R(x) \rightarrow \neg S(x)),\) and \(\exists x \neg P(x)\) are true, then \(\exists x \neg R(x)\) is true.

A statement is in prenex normal form (PNF) if and only if it is of the form $$ Q_{1} x_{1} Q_{2} x_{2} \cdots Q_{k} x_{k} P\left(x_{1}, x_{2}, \ldots, x_{k}\right) $$ where each \(Q_{i}, i=1,2, \ldots, k,\) is either the existential quantifier or the universal quantifier, and \(P\left(x_{1}, \ldots, x_{k}\right)\) is a predicate involving no quantifiers. For example, \(\exists x \forall y(P(x, y) \wedge Q(y))\) is in prenex normal form, whereas \(\exists x P(x) \vee \forall x Q(x)\) is not (because the quantifiers do not all occur first). Every statement formed from propositional variables, predicates, \(\mathbf{T},\) and \(\mathbf{F}\) using logical connectives and quantifiers is equivalent to a statement in prenex normal form. Exercise 51 asks for a proof of this fact. Show how to transform an arbitrary statement to a statement in prenex normal form that is equivalent to the given statement. (Note: A formal solution of this exercise requires use of structural induction, covered in Section \(5.3 . )\)

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