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How many different seating arrangements are possible for King Arthur and his 9 knights around their round table?

Short Answer

Expert verified
There are 9! (362,880) different seating arrangements for King Arthur and his 9 knights around their round table.

Step by step solution

01

Understanding the Problem

To find the number of distinct seating arrangements around a round table for King Arthur and his 9 knights, we need to consider rotational symmetry. One way to count is to fix one person’s position and arrange the remaining people around them. Since the table is round, fixing one person's seat does not change the arrangement.
02

Calculate Seating Arrangements

After fixing King Arthur’s position, we have 9 knights left to arrange around the table. The number of ways to arrange n distinct objects in a row is given by n factorial (!). Therefore, we can arrange the 9 knights in 9! ways.
03

Compute Factorial

9 factorial (9!) is computed as follows: 9! = 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Symmetry in Seating Arrangements
When we talk about seating arrangements around a round table, the concept of rotational symmetry becomes incredibly important because it significantly affects the count of possible arrangements. Imagine a circular table with seats all around; if you rotate the table, an arrangement where everyone simply shifts one seat over might look different from above, but actually, it's the same grouping. That's the essence of rotational symmetry in this context: arrangements that can be transformed into each other by rotation are not unique.

To navigate this when arranging King Arthur and his knights, we consider one position fixed, such as King Arthur's seat, and then arrange everyone else around him. Fixing one position helps us create a reference point, keeping the symmetry in check and ensuring that we do not count identical arrangements multiple times. Practical application of this understanding means we focus on how to arrange the knights without worrying about the rotation of the table affecting our total count.
Factorial and Its Role in Combinations
The factorial, denoted by an exclamation mark (!), plays a pivotal role in both combinatorics and our problem of seating arrangements. Essentially, the factorial of a number, say n, is the product of all positive integers less than or equal to n. To express it mathematically, \( n! = n \times (n - 1) \times (n - 2) \times ... \times 3 \times 2 \times 1 \).

Why is the factorial concept so useful in arranging objects? Consider a row of seats. To fill the first seat, you have n options, for the second seat, n-1 options remain, and so on, until only one option for the last seat. Multiplying these options—essentially calculating the factorial—gives us the total number of possible arrangements. In our King Arthur scenario, after fixing his position, we arrange the 9 knights, leading to \( 9! \) arrangements. Always remember, the factorial expresses the number of ways to arrange distinct objects, which is key in understanding its utility in such problems.
Combinatorics: The Mathematics of Counting
The field of mathematics that specializes in counting is known as combinatorics. It doesn't just involve simple counting; it's the math of organized creation and enumeration of possibilities, which ranges from simple combinations to more complex structures like graphs and networks. Combinatorics is essential for solving problems related to possibility and choice, such as our round table arrangement.

Combinatorics uses tools like permutations, which consider the order of arrangement and selections (like in our round table problem), as well as combinations which are concerned with selections when order does not matter. In the case of King Arthur and his knights, combinatorial thinking allows us to understand why we use the factorial to calculate arrangements and account for rotational symmetry. The combination of these concepts results in an accurate count of distinct seating possibilities, demonstrating the power of combinatorics in solving real-world problems.

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Most popular questions from this chapter

Let \(d_{n}\) be the number of derangements of \(n\) objects. For example, using the techniques of this section, we find $$ d_{3}=3 !-\left(\left(\begin{array}{l} 3 \\ 1 \end{array}\right) 2 !-\left(\begin{array}{l} 3 \\ 2 \end{array}\right) 1 !+\left(\begin{array}{l} 3 \\ 3 \end{array}\right) 0 !\right) $$ We can use the formula for \(\left(\begin{array}{l}n \\ k\end{array}\right)\) to write this all in terms of factorials. After simplifying, for \(d_{3}\) we would get $$ d_{3}=3 !\left(1-\frac{1}{1}+\frac{1}{2}-\frac{1}{6}\right) $$ Generalize this to find a nicer formula for \(d_{n} .\) Bonus: For large \(n\), approximately what fraction of all permutations are derangements? Use your knowledge of Taylor series from calculus.

In a recent small survey of airline passengers, 25 said they had flown American in the last year, 30 had flown Jet Blue, and 20 had flown Continental. Of those, 10 reported they had flown on American and Jet Blue, 12 had flown on Jet Blue and Continental, and 7 had flown on American and Continental. 5 passengers had flown on all three airlines. How many passengers were surveyed? (Assume the results above make up the entire survey.)

Gridtown USA, besides having excellent donut shops, is known for its precisely laid out grid of streets and avenues. Streets run east-west, and avenues north-south, for the entire stretch of the town, never curving and never interrupted by parks or schools or the like. Suppose you live on the corner of \(3 \mathrm{rd}\) and \(3 \mathrm{rd}\) and work on the corner of 12 th and 12 th. Thus you must travel 18 blocks to get to work as quickly as possible. (a) How many different routes can you take to work, assuming you want to get there as quickly as possible? Explain. (b) Now suppose you want to stop and get a donut on the way to work, from your favorite donut shop on the corner of 10 th ave and 8 th st. How many routes to work, stopping at the donut shop, can you take (again, ensuring the shortest possible route)? Explain. (c) Disaster Strikes Gridtown: there is a pothole on 4 th ave between 5 th st and 6 th st. How many routes to work can you take avoiding that unsightly (and dangerous) stretch of road? Explain. (d) The pothole has been repaired (phew) and a new donut shop has opened on the corner of 4 th ave and 5 th st. How many routes to work drive by one or the other (or both) donut shops? Hint: the donut shops serve PIE.

Let \(S=\\{1,2,3,4,5,6\\}\) (a) How many subsets are there of cardinality 4 ? (b) How many subsets of cardinality 4 have \\{2,3,5\\} as a subset? (c) How many subsets of cardinality 4 contain at least one odd number? (d) How many subsets of cardinality 4 contain exactly one even number?

How many functions map \\{1,2,3,4,5,6\\} onto \(\\{a, b, c, d\\}\) (i.e., how many surjections are there)?

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