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How many functions map \\{1,2,3,4,5,6\\} onto \(\\{a, b, c, d\\}\) (i.e., how many surjections are there)?

Short Answer

Expert verified
The number of surjections is \(4^6 - 4 \cdot 3^6 + 6 \cdot 2^6 - 4 \).

Step by step solution

01

Understand Surjections

A surjection (or onto function) from set X to set Y is a function such that every element in set Y has at least one corresponding element in set X. Essentially, there are no unused elements in the target set Y after mapping elements from X. We need to count all such mappings from set \(X = \{1, 2, 3, 4, 5, 6\}\) to set \(Y = \{a, b, c, d\}\).
02

Use the Principle of Inclusion-Exclusion

To count the number of surjective functions, we can use the Principle of Inclusion-Exclusion. Let's calculate the total number of functions and subtract functions that are not onto (functions that miss at least one element in \(Y\)).
03

Calculate Total Number of Functions

The total number of functions from a set with 6 elements to a set with 4 elements is \(4^6\) since each of the 6 elements has 4 choices.
04

Subtract Non-Onto Functions

To subtract the non-onto functions, consider the functions that miss at least one of the elements of \(Y\). If a function misses 1 element, we have \(3^6\) choices for the mapping from 6 elements. If a function misses 2 elements, we have \(2^6\) choices. However, we must account for overcounting caused by subtracting cases that miss multiple elements more than once. For each case, use combinations to calculate the different ways to miss elements. Multiply by the number of functions that miss that exact subset of elements.
05

Apply Combinations and Adjust for Overcounting

When a function misses 1 element, there are \(\binom{4}{1}\) ways to pick which element to miss and \(3^6\) configurations for each of those. For missing 2 elements, there are \(\binom{4}{2}\) ways and \(2^6\) configurations. For missing 3 elements, \(\binom{4}{3}\) ways and \(1^6\) configurations. However, when we subtract cases with more than one missing element, we must add back in those that miss exactly 3 elements to correct overcounting. We don't need to consider functions that miss all 4 elements since they would not be functions.
06

Complete the Calculation

Combining our results from the previous steps, we calculate the number of surjective functions by subtracting the non-onto functions from the total: \((4^6) - \binom{4}{1}(3^6) + \binom{4}{2}(2^6) - \binom{4}{3}(1^6)\). This accounts for the Principle of Inclusion-Exclusion, by alternating between subtracting and adding to correct for overcounts and undercounts.
07

Simplify the Expression

Simplify the expression to get the final answer. Remember that \(\binom{4}{1}=4\), \(\binom{4}{2}=6\), and \(\binom{4}{3}=4\). Plug these values into the expression and perform the arithmetic operations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principle of Inclusion-Exclusion
To understand combinatorial problems like calculating the number of surjective functions between two sets, students must grasp the Principle of Inclusion-Exclusion (PIE). PIE is a counting technique to determine the size of a union of overlapping sets, by adding the sizes of the individual sets and then compensating for the overlap.

When applying PIE, you start by counting all possible outcomes without any restrictions, which is often the easiest part. Then, you subtract the number of outcomes that don't meet your criteria (inclusions), such as all functions that are not onto because they miss mapping to one or more elements. Lastly, you account for overcounting by adding back in the outcomes that were excluded multiple times (exclusions). For instance, if we've subtracted functions missing one element and again for those missing two elements, we've subtracted the cases with two missing elements twice, and we must add them back in once.

Using PIE can initially seem counterintuitive, as we are adding and subtracting quantities to adjust our counts, but it's a fundamental strategy in combinatorics that ensures each scenario is counted only once. This principle is essential when dealing with complex overlapping scenarios in discrete mathematics and combinatorial problems.
Mapping in Discrete Mathematics
Mapping, or more formally, function assignment in discrete mathematics, is the process of linking each element of a 'domain' set to exactly one element of a 'codomain' set. A surjective function, which is at the heart of this exercise, is a type of mapping where each element of the codomain is 'hit' by the function at least once.

Mappings can be visualized as arrows going from elements of the domain to elements of the codomain. Surjections, also known as onto functions, have the characteristic that every element of the codomain has at least one arrow pointing to it from the domain.

To solidify this concept, imagine a set of six people and a set of four different tasks. If each person is assigned to exactly one task, and each task must be assigned to at least one person (to ensure that all tasks are covered), we are visualizing a surjective function. Surjections are immensely important in several areas of mathematics and computer science, including algorithm design, where every potential input must yield an output.
Combinatorics
Combinatorics, the branch of mathematics dealing with combinations, permutations, and counting, is indispensable for solving problems such as determining the number of surjective functions between two finite sets. The key aspect of combinatronics is understanding and applying various counting principles to solve problems involving finite structures.

In this particular problem, we use two combinatorial tools: the total number of functions between sets, which is based on the idea of product rule (every choice for an element in the domain multiplies the total count), and combinations, denoted by the binomial coefficient \( \binom{n}{k} \), which count the ways to select a subset of a particular size from a larger set.

This exercise required recognizing that not all functions are surjective and using combinatorial reasoning to exclude these cases. By considering the various ways elements can be excluded from the mapping, and then utilizing combinations to account for these variations, we are able to calculate the precise number of surjective functions. The skills developed in combinatorics are widely applicable, aiding in fields as diverse as coding theory, probability, and even understanding search algorithms in computer science.

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Most popular questions from this chapter

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