/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A bug is crawling horizontally a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A bug is crawling horizontally along the wall at a constant rate of 5 inches per minute. You first notice the bug when it is in the corner of the room, behind your music stand. a. Define variables and write an equation that relates time (in minutes) to distance traveled (in inches). (a) b. What is the constant of variation of this direct variation relationship, and what does it represent? c. How far will the bug crawl in \(1 \mathrm{~h}\) ? d. How long would you have to practice playing your instrument before the bug completely "circled" the 14-ft-by-20-ft room? (a) e. Draw a graph that represents this situation.

Short Answer

Expert verified
a) Variables: \( t \), \( d \); Equation: \( d = 5t \). b) Constant is 5, representing speed. c) 300 inches in 1 hour. d) 163.2 minutes to circle the room.

Step by step solution

01

Define variables

Let \( t \) represent time in minutes and \( d \) represent the distance traveled by the bug in inches. The bug travels at a rate of 5 inches per minute.
02

Write the equation

Since the bug travels at a constant rate of 5 inches per minute, the relationship between time and distance can be expressed as \( d = 5t \).
03

Identify the constant of variation

In the equation \( d = 5t \), the constant of variation is 5. This means that for every minute, the bug travels 5 inches. The constant of variation represents the bug's speed.
04

Calculate distance traveled in 1 hour

Since 1 hour is 60 minutes, substitute \( t = 60 \) into the equation:\[\begin{align*}d & = 5 \times 60 \& = 300 \text{ inches}.\end{align*}\]The bug will crawl 300 inches in 1 hour.
05

Calculate time to circle the room

The perimeter of the 14-ft by 20-ft room is \( 2 \times (14 + 20) = 68 \) feet. Convert this to inches: \( 68 \times 12 = 816 \) inches. Solving for \( t \) in the equation \( 816 = 5t \), we find:\[t = \frac{816}{5} = 163.2 \text{ minutes}.\]You would practice for 163.2 minutes before the bug completely circles the room.
06

Graph the situation

On a graph where the x-axis represents time (in minutes) and the y-axis represents distance (in inches), plot a line beginning at the origin (0,0) with a slope of 5, indicating the constant speed. The line will continue upwards linearly.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equation
A linear equation is a mathematical equation that forms a straight line when graphed on a coordinate plane. It is typically written in the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. In the case of the crawling bug, we see a simpler version of the linear equation: \( d = 5t \). Here, the distance, \( d \), is directly proportional to the time, \( t \), with no y-intercept since the bug starts at the corner of the room.

This equation shows that the distance traveled by the bug increases constantly at a rate of 5 inches per minute. Since there is no additional constant term added, i.e., \( b = 0 \), the line of the graph begins at the origin, and there is a straightforward linear relationship between time and distance.
Constant of Variation
The constant of variation in a direct variation relationship is the rate at which one variable changes with respect to another. In our scenario, it is represented by the number \( 5 \) in the equation \( d = 5t \).

The constant of variation, or proportionality constant, provides a simple way to understand how fast the bug is traveling. Specifically, it indicates that for every 1 unit increase in time (minute), there is a 5-unit increase in the distance (inches). This is crucial when calculating future positions of the bug or when determining how long it will take the bug to cover a certain distance. The constant characterizes the speed or rate of the bug's travel, making it a vital component of the linear equation.
Graphing Linear Equations
Graphing linear equations helps visualize the relationship between two variables. In the bug's scenario, graphing the equation \( d = 5t \) on a graph with time on the x-axis and distance on the y-axis can show us how the bug's journey progresses over time.

  • The graph is a straight line starting from the origin, indicating that initially, when time is zero, distance is also zero.
  • The line has a slope of 5, meaning the line rises 5 units for each unit it moves to the right, reflecting the rate of 5 inches per minute.
  • Since the slope is constant, the line is straight and does not curve or change direction, showcasing the constant speed of the bug.
Using the graph enables you to estimate time and distance values without calculations, simply by viewing the line and its intersection with the axes.
Unit Conversion
Unit conversion is a critical skill when solving real-life problems, as it ensures that all measurements used in equations and graphs are consistent. In the bug's scenario, we must convert dimensions from feet to inches to solve the problem correctly.

  • Since 1 foot equals 12 inches, all dimensions can be converted by multiplying by 12.
  • For example, when calculating the perimeter of a room that measures 14 feet by 20 feet, we find the perimeter in feet first and then convert: \( 2 \times (14 + 20) = 68 \text{ feet} \).
  • Converting feet to inches means \( 68 \times 12 = 816 \text{ inches} \).
This conversion is necessary for calculating how long it takes the bug to travel around the room since our rate is given in inches per minute. Ensuring all measurements match allows for accurate calculations and meaningful results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which is longer: a 1 -mile race or a 1500 -meter race? Show your reasoning.

APPLICATION A CD is on sale for \(15 \%\) off its normal price of \(\$ 13.95\). What is its sale price? Write a direct variation equation to solve this problem.

Write your own number trick with at least six stages. a. No matter what number you begin with, make the trick result in \(-4\). b. Describe the process you used to create the trick. c. Write an expression for your trick.

APPLICATION Market A sells 7 ears of corn for \(\$ 1.25\). Market B sells a baker's dozen (13 ears) for \(\$ 2.75\). a. Copy and complete the tables below showing the cost of corn at each market. Market A Market B \begin{tabular}{|c|c|c|c|c|c|c|} \hline Ears & 7 & 14 & 21 & 28 & 35 & 42 \\ \hline Cost & & & & & & \\ \hline \end{tabular} \begin{tabular}{|l|l|l|l|l|l|l|} \hline Ears & 13 & 26 & 39 & 52 & 65 & 78 \\ \hline Cost & & & & & & \\ \hline \end{tabular} b. Let \(x\) represent the number of ears of corn and y represent cost. Find equations to describe the cost of corn at each market. Use your calculator to plot the information for each market on the same set of coordinate axes. Round the constants of variation to three decimal places. (Ti) c. If you wanted to buy only one ear of corn, how much would each market charge you? How do these prices relate to the equations you found in \(6 \mathrm{~b}\) ? d. How can you tell from the graphs which market is the cheaper place to buy corn?

To use a double-pan balance, you put the object to be weighed on one side and then put known weights on the other side until the pans balance. a. Explain why it is useful to have the balance point halfway between the two pans. b. Suppose the balance point is off-center, \(15 \mathrm{~cm}\) from one pan and \(20 \mathrm{~cm}\) from the other. There is an object in the pan closest to the center. The pans balance when \(7 \mathrm{~kg}\) is placed in the other pan. What is the weight of the unknown object? (a)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.