Chapter 9: Problem 13
What is the general form of \(y=(x+4)^{2}\) ? Write a paragraph describing several ways to rewrite this expression in general form.
Short Answer
Expert verified
The general form is \( y = x^2 + 8x + 16 \).
Step by step solution
01
Understand the Expression
The given expression is \( y = (x+4)^2 \). This is a quadratic expression written in vertex form, where the vertex is \(( -4, 0 )\). The task is to rewrite this expression in general form, which is \( y = ax^2 + bx + c \).
02
Expand the Expression
To convert \((x+4)^2\) into general form, expand \((x+4)(x+4)\). Use the distributive property: \((x+4)^2 = x(x+4) + 4(x+4)\).
03
Apply the Distributive Property
Apply the distributive property to both terms: \(x(x+4) = x^2 + 4x\) and \(4(x+4) = 4x + 16\).
04
Combine Like Terms
Combine the like terms from the expanded expression: \(x^2 + 4x + 4x + 16 = x^2 + 8x + 16\).
05
Write the General Form
The general form of the expression is \( y = x^2 + 8x + 16 \). This is written in the form \( y = ax^2 + bx + c \), where \( a = 1 \), \( b = 8 \), and \( c = 16 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Expanding Expressions
Expanding expressions is a fundamental skill in algebra, especially important when working with quadratic equations. When you see an expression like
To expand
- \((x+4)^2\),
To expand
- \((x+4)^2\),
- \((x+4)(x+4)\).
- \(x(x+4)\) and
- \(4(x+4)\).
- \(x^2 + 4x\) from the first calculation and
- \(4x + 16\) from the second.
- \(x^2 + 8x + 16\).
Vertex Form
Quadratic equations often appear in different forms, each offering unique insights into the function's properties. The vertex form is one such expression,
In our example,
- \(y=a(x-h)^2+k\),
In our example,
- \(y = (x+4)^2\),
- h = -4
- and k = 0.
- \((-4,0)\).
- \(a>0\)
- \(a<0\).
General Form
The general form of a quadratic equation shows its most expanded polynomial state. It's written as
To convert from vertex to general form, we expand
- \(y=ax^2+bx+c\).
To convert from vertex to general form, we expand
- \((x+4)^2\) as described earlier,
- \(x^2+8x+16\).
- \(a=1\),
- \(b=8\),
- and \(c=16\).