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What is the general form of \(y=(x+4)^{2}\) ? Write a paragraph describing several ways to rewrite this expression in general form.

Short Answer

Expert verified
The general form is \( y = x^2 + 8x + 16 \).

Step by step solution

01

Understand the Expression

The given expression is \( y = (x+4)^2 \). This is a quadratic expression written in vertex form, where the vertex is \(( -4, 0 )\). The task is to rewrite this expression in general form, which is \( y = ax^2 + bx + c \).
02

Expand the Expression

To convert \((x+4)^2\) into general form, expand \((x+4)(x+4)\). Use the distributive property: \((x+4)^2 = x(x+4) + 4(x+4)\).
03

Apply the Distributive Property

Apply the distributive property to both terms: \(x(x+4) = x^2 + 4x\) and \(4(x+4) = 4x + 16\).
04

Combine Like Terms

Combine the like terms from the expanded expression: \(x^2 + 4x + 4x + 16 = x^2 + 8x + 16\).
05

Write the General Form

The general form of the expression is \( y = x^2 + 8x + 16 \). This is written in the form \( y = ax^2 + bx + c \), where \( a = 1 \), \( b = 8 \), and \( c = 16 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expanding Expressions
Expanding expressions is a fundamental skill in algebra, especially important when working with quadratic equations. When you see an expression like
  • \((x+4)^2\),
your goal is to remove the parentheses to find its equivalent expanded form. Here, expanding means simply the removal of parentheses to express each component separately using arithmetic procedures - particularly the distributive property.

To expand
  • \((x+4)^2\),
you recognize it as
  • \((x+4)(x+4)\).
Use the distributive property by multiplying each term in the first expression by each term in the second. This gives you two separate calculations:
  • \(x(x+4)\) and
  • \(4(x+4)\).
Apply the distributive property to get
  • \(x^2 + 4x\) from the first calculation and
  • \(4x + 16\) from the second.
Finally, combine these results to get
  • \(x^2 + 8x + 16\).
Expanding expressions is straightforward once you consistently apply these steps.
Vertex Form
Quadratic equations often appear in different forms, each offering unique insights into the function's properties. The vertex form is one such expression,
  • \(y=a(x-h)^2+k\),
which emphasizes the vertex of the parabola.

In our example,
  • \(y = (x+4)^2\),
the equation is already in vertex form. Here,
  • h = -4
  • and k = 0.
This means the vertex of the parabola is at
  • \((-4,0)\).
Vertex form is particularly useful when you need to quickly identify the maximum or minimum point of a quadratic function, known as the vertex. This is because it also reveals whether the parabola opens upwards
  • \(a>0\)
or downwards
  • \(a<0\).
Understanding vertex form allows you to easily manipulate and graph quadratic functions, making it indispensable for solving problems involving parabolas.
General Form
The general form of a quadratic equation shows its most expanded polynomial state. It's written as
  • \(y=ax^2+bx+c\).
This form is useful for solving quadratic equations using the quadratic formula or determining the roots.

To convert from vertex to general form, we expand
  • \((x+4)^2\) as described earlier,
arriving at
  • \(x^2+8x+16\).
This means in the expression,
  • \(a=1\),
  • \(b=8\),
  • and \(c=16\).
The coefficients correspond respectively to each term of the quadratic, linear, and constant elements in the expression. General form makes it easy to apply further mathematical techniques, such as factoring or completing the square, and is essential for considering the full scope of operations you can perform on a quadratic equation.

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Most popular questions from this chapter

Determine whether each table represents a linear function, an exponential function, a cubic function, or a quadratic function. (Ti) $$ \begin{aligned} &\text { a. }\\\ &\begin{array}{|c|c|} \hline x & y \\ \hline 2 & 4 \\ \hline 5 & 25 \\ \hline 8 & 64 \\ \hline 11 & 121 \\ \hline 14 & 196 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { b. }\\\ &\begin{array}{|c|c|} \hline x & y \\ \hline 2 & 7 \\ \hline 5 & 11 \\ \hline 8 & 15 \\ \hline 11 & 19 \\ \hline 14 & 23 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { c. }\\\ &\begin{array}{|c|r|} \hline x & y \\ \hline 2 & 4 \\ \hline 5 & 32 \\ \hline 8 & 256 \\ \hline 11 & 2,048 \\ \hline 14 & 16,384 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { d. }\\\ &\begin{array}{|c|c|} \hline x & y \\ \hline 2 & 8 \\ \hline 5 & 125 \\ \hline 8 & 512 \\ \hline 11 & 1,331 \\ \hline 14 & 2,744 \\ \cline { 2 } & \\ \hline \end{array} \end{aligned} $$

Consider the equation \(y=(x+1)(x-3)\). a. How many \(x\)-intercepts does the graph have? b. Find the vertex of this parabola. c. Write the equation in vertex form. Describe the transformations of the parent function, \(y=x^{2}\).

If you know the vertex and one other point on a parabola, you can find its quadratic equation. The vertex \((h, k)\) of this parabola is \((2,-31.5)\), and the other point is \((5,0)\). a. Substitute the values for \(h\) and \(k\) into the equation \(y=a(x-h)^{2}+k\). b. To find the value of \(a\), substitute 5 for \(x\) and 0 for \(y\). Then solve for \(a\). c. Use the \(a\)-value you found in \(5 \mathrm{~b}\) to write the equation of the graph in vertex form. d. Use what you learned in \(5 a-c\) to write the equation of the graph whose vertex is \((2,32)\) and that passes through the point \((5,14)\).

Some numbers are both perfect squares and perfect cubes. a. Find at least three numbers that are both a perfect square and a perfect cube. b. Define a rule that you can use to find as many numbers as you like that are both perfect squares and perfect cubes.

Without using a calculator, evaluate the expression \(b^{2}-4 a c\) for the values given. Then check your answers with a calculator. a. \(a=3, b=5, c=2\) b. \(-a=1, b=-3, c=-3\) c. \(a=-2, b=-6, c=-3\) (?) d. \(-a=9, b=9, c=0\)

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