/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Perform the indicated operation ... [FREE SOLUTION] | 91Ó°ÊÓ

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Perform the indicated operation and write the result in lowest terms. State any restrictions on the variable. Verify your answers by using your calculator to compare graphs or tables of values. a. \(\frac{x+4}{x+2} \cdot \frac{x^{2}+4 x+4}{x^{2}-16}\) b. \(\frac{x^{2}+2 x}{x^{2}-4} \div \frac{x^{2}}{x^{2}-6 x+8}\) c. \(\frac{x}{x^{2}+6 x+9}+\frac{1}{x+3}\) d. \(\frac{x-1}{x^{2}-1}-\frac{4}{x+1}\)

Short Answer

Expert verified
(a) \( \frac{x+2}{x-4} \), (b) \( \frac{x-4}{x} \), (c) \( \frac{2x+3}{(x+3)^2} \), (d) \( \frac{-3}{x+1} \); Restrictions: (a) \( x \neq -2, 4, -4 \), (b) \( x \neq -2, 0, 2, 4 \), (c) \( x \neq -3 \), (d) \( x \neq 1, -1 \).

Step by step solution

01

Simplify expression (a)

The expression is \( \frac{x+4}{x+2} \cdot \frac{x^2+4x+4}{x^2-16} \). Start by factoring the numerator and denominator wherever possible.\- Factor \( x^2 + 4x + 4 \) as \((x+2)^2\).\- Factor \( x^2 - 16 \) as \((x-4)(x+4)\).The expression becomes: \( \frac{x+4}{x+2} \cdot \frac{(x+2)^2}{(x-4)(x+4)} \).Now, cancel out the common factor \( x+4 \) from the numerator and denominator:\[ \frac{\cancel{x+4}}{x+2} \cdot \frac{(x+2)^2}{(x-4)\cancel{(x+4)}} = \frac{(x+2)}{x-4} \].The simplified result is \( \frac{x+2}{x-4} \).
02

Identify restrictions (a)

For restrictions, determine the values of \( x \) that make any denominator zero in the original expression:- \( x+2 = 0 \) implies \( x eq -2 \).- \( x^2 - 16 = 0 \) or \((x-4)(x+4)=0\) implies \( x eq 4, -4 \).Therefore, the restrictions are \( x eq -2, 4, -4 \).
03

Simplify expression (b)

The expression is \( \frac{x^2+2x}{x^2-4} \div \frac{x^2}{x^2-6x+8} \). Use the property of division by fraction to multiply by the reciprocal:\[ \frac{x^2+2x}{x^2-4} \times \frac{x^2-6x+8}{x^2} \].Factor the components:- \( x^2 + 2x = x(x+2) \)- \( x^2 - 4 = (x-2)(x+2) \)- \( x^2 - 6x + 8 = (x-4)(x-2) \)The expression becomes: \( \frac{x(x+2)}{(x-2)(x+2)} \cdot \frac{(x-4)(x-2)}{x^2} \).Cancel out the common factors \((x+2)\) and \((x-2)\):\[ \frac{x \cancel{(x+2)}}{\cancel{(x-2)} \cancel{(x+2)}} \cdot \frac{(x-4)\cancel{(x-2)}}{x^2} = \frac{x(x-4)}{x^2} \]Simplify: \( \frac{x(x-4)}{x^2} = \frac{x-4}{x} \).
04

Identify restrictions (b)

Check restrictions for when any denominator equals zero:- \( x^2-4 = 0 \) implies \( x eq 2, -2 \).- \( x^2 = 0 \) implies \( x eq 0 \).- \( x^2-6x+8 = 0 \) implies \( x eq 2, 4 \).The restrictions are \( x eq -2, 0, 2, 4 \).
05

Simplify expression (c)

The expression is \( \frac{x}{x^2+6x+9} + \frac{1}{x+3} \). Factor the quadratics:- \( x^2 + 6x + 9 = (x+3)^2 \).This gives \( \frac{x}{(x+3)^2} + \frac{1}{x+3} \).To add fractions, find a common denominator, which is \((x+3)^2\):Convert \( \frac{1}{x+3} \) to \( \frac{1 \cdot (x+3)}{(x+3)^2} \) or \( \frac{x+3}{(x+3)^2} \).Now, add the fractions: \[ \frac{x + (x+3)}{(x+3)^2} = \frac{2x+3}{(x+3)^2} \].
06

Identify restrictions (c)

Identify when the denominator in the original expression equals zero:- \( x^2+6x+9 = 0 \) implies \( x eq -3 \).Thus, the restriction is \( x eq -3 \).
07

Simplify expression (d)

The expression is \( \frac{x-1}{x^2-1} - \frac{4}{x+1} \).First, factor the denominator \(x^2-1\) as \((x-1)(x+1)\).Express with this factor: \( \frac{x-1}{(x-1)(x+1)} - \frac{4}{x+1} \).A common denominator is \((x-1)(x+1)\): Convert \( \frac{4}{x+1} \) to \( \frac{4 \cdot (x-1)}{(x-1)(x+1)} \).Subtract: \[ \frac{x-1 - 4(x-1)}{(x-1)(x+1)} = \frac{x - 1 - 4x + 4}{(x-1)(x+1)} = \frac{-3x + 3}{(x-1)(x+1)} \].Factor the numerator: \( \frac{-3(x-1)}{(x-1)(x+1)} \).Cancel the \(x-1\) terms: \( \frac{-3}{x+1} \).
08

Identify restrictions (d)

Identify restrictions from original denominators:- \( x^2-1 = 0 \) or \((x-1)(x+1)=0\) implies \( x eq 1, -1 \).- \( x+1 = 0 \) implies \( x eq -1 \).The restrictions are \( x eq 1, -1 \).
09

Verification of results

Use a calculator to graph each of the original and simplified expressions on the same axes. They should be identical except at points removed due to restrictions. Alternatively, use the calculator's table function to compare values at a series of points not at the restrictions. Each pair should yield the same result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
When dealing with rational expressions, factoring polynomials is a crucial step. It allows us to break down complex expressions into simpler, more manageable forms. Let's consider the expression \(x^2 + 4x + 4\). This trinomial resembles a perfect square, which can be factored into \( (x+2)^2\). Similarly, the expression \(x^2 - 16\) fits the difference of squares pattern and can be rewritten as \( (x-4)(x+4)\).
By factoring these polynomials, you can identify common terms that may be cancelled, leading to a simplified expression. This step usually involves recognizing patterns such as perfect squares, difference of squares, or trinomials. Take your time with this step; it makes the entire process of simplifying fractions and solving algebraic equations much easier.
Simplifying Expressions
Once the polynomials are factored, the next step is simplifying the rational expressions. Simplification involves canceling out common factors between numerators and denominators. For example, in the expression \[ \frac{x+4}{x+2} \cdot \frac{(x+2)^2}{(x-4)(x+4)} \], you can cancel the \(x+4\) term in both a numerator and a denominator.
  • Only terms that are \emph{exactly the same} in both the numerator and denominator can be cancelled.
  • Be careful not to mistakenly cancel terms that are part of a sum or difference unless the entire term matches.
After simplification, the rational expression is often easier to work with and can help reveal potential restrictions on the variables, which we discuss next.
Identifying Restrictions
Rational expressions often have restrictions on the variable to ensure the denominator never equals zero. Identifying these restrictions is key to solving and simplifying expressions accurately.
In our examples, you start by setting each denominator equal to zero and solving for \(x\). For \( x+2 = 0 \), \( x = -2 \) is a restriction. Similarly, solving \( x^2 - 16 = 0 \) gives restrictions \( x = 4\) and \( x = -4\).
Remember:
  • Every factor in the denominator potentially contributes to restrictions.
  • Even after cancelling terms in simplifications, the original restrictions still apply, because the expression was undefined for these \(x\) values initially.
Properly identifying these restrictions ensures your answer is mathematically correct and can help avoid pitfalls in problem-solving.
Adding and Subtracting Rational Expressions
When adding or subtracting rational expressions, finding a common denominator is essential. Consider the expression \( \frac{x}{x^2 + 6x + 9} + \frac{1}{x + 3} \). First, factor the denominator of the first fraction as \( (x+3)^2 \). Recognizing that \( x+3 \) is part of this squared term helps determine the common denominator: \( (x+3)^2 \).
To combine these fractions:
  • Convert \ \frac{1}{x+3} \ to \ \frac{x+3}{(x+3)^2} \.
  • Then, you can directly add \ \frac{x}{(x+3)^2} \ and \ \frac{x+3}{(x+3)^2} \, getting \ \frac{2x+3}{(x+3)^2} \ as the result.
Understanding how to manipulate and adjust rational expressions' numerators and denominators is important in solving equations and understanding their graphical representations and behavior.

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Most popular questions from this chapter

In this exercise you will discover whether knowing the \(x\)-intercepts determines a unique quadratic equation. Work through the steps in 9 a-e to find an answer. Graph each equation to check your work. a. Write an equation of a parabola with \(x\)-intercepts at \(x=3\) and \(x=7\). b. Name the vertex of the parabola in 9 a. c. Modify your equation in 9 a so that the graph is reflected across the \(x\)-axis. Where are the \(x\)-intercepts? Where is the vertex? d. Modify your equation in 9 a to apply a vertical stretch with a factor of 2 . Where are the \(x\)-intercepts? Where is the vertex? (a) e. How many quadratic equations do you think there are with \(x\)-intercepts at \(x=3\) and \(x=7 ?\) How are they related to one another?

What is the general form of \(y=(x+4)^{2}\) ? Write a paragraph describing several ways to rewrite this expression in general form.

Edward is responsible for keeping the stockroom packed with the best-selling merchandise at the Super Store. He has collected data on sales of the new video game "Math-a-Magic." $$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|l|l|} \hline \text { Week } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \text { Games sold } & 0 & 186 & 366 & 516 & 636 & 727 & 789 & 821 & 825 & 798 \\ \hline \end{array} $$ a. Find a quadratic model in vertex form that fits the data. Let \(w\) represent the week number and let \(s\) represent the number of games sold. b. If the pattern continues, in what week will people stop buying the game? c. How many total games will have been sold when people stop buying the game? (T1) d. There are 1000 games left in the stockroom at the start of week 11 . How many more should Edward buy?

Decide what number must be added to each expression to make a perfect-square trinomial. Then rewrite the trinomial as a squared binomial. a. \(x^{2}+18 x\) (a) b. \(x^{2}-10 x\) c. \(x^{2}+3 x\) d. \(x^{2}-x\) e. \(x^{2}+\frac{2}{3} x\) f. \(x^{2}-1.4 x\)

In each equation the variable \(x\) represents time and \(y\) represents the height of a projectile. a. \(y=-16(x-3)^{2}+20\) b. \(y=-4.9(x-4.2)^{2}+12\) For each equation: i. Describe the transformations of the graph of \(y=x^{2}\). (11) ii. Name the vertex of the parabola. iii. What is the real-world meaning for each number in the equation?

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