/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 APPLICATION This system of equat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

APPLICATION This system of equations models the profits of two home-based Internet companies. $$ \left\\{\begin{array}{l} P=-12000+2.5 \mathrm{~N} \\ P=-5000+1.6 \mathrm{~N} \end{array}\right. $$ The variable \(P\) represents profit in dollars, and \(N\) represents hits to the company's website. a. Use the substitution method to find an exact solution. (a) b. Is an approximate or exact solution more meaningful in this model?

Short Answer

Expert verified
The exact solution is \(N = 7777.78\) and \(P = 7444.45\). An exact solution is more meaningful, but an approximate one provides practical insights too.

Step by step solution

01

Set Equations Equal

Since both equations are in terms of \(P\), set the two expressions for \(P\) equal to each other: \(-12000 + 2.5N = -5000 + 1.6N\).
02

Solve for N

Isolate \(N\) by subtracting \(1.6N\) from both sides to get: \(-12000 + 2.5N - 1.6N = -5000\). Simplifying gives \(-12000 + 0.9N = -5000\). Then, add \(12000\) to both sides: \(0.9N = 7000\). Divide both sides by \(0.9\) to solve for \(N\): \(N = \frac{7000}{0.9}\approx 7777.78\).
03

Solve for P

Substitute \(N = 7777.78\) back into the first equation to solve for \(P\): \(P = -12000 + 2.5 \times 7777.78\). This simplifies to \(P = -12000 + 19444.45 = 7444.45\).
04

Compare with Other Equation

Check the solution by substituting \(N = 7777.78\) into the second equation: \(P = -5000 + 1.6 \times 7777.78\). This results in \(P = -5000 + 12444.45 = 7444.45\). Since both equations give the same \(P\), the solution is correct.
05

Conclusion About Exact vs. Approximate

The solution depends on precise equations, so an exact solution is meaningful. However, considering practical application, an approximate solution also holds value to account for real-world variables and fluctuations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a technique used in solving systems of equations wherein one variable is expressed in terms of another using one of the equations. We then substitute this expression into the other equation to find the values of these variables. This method is especially useful when equations are arranged to easily express one variable explicitly. For instance, in the given problem, each equation is already solved for the variable \(P\). So, you can set the expressions equal to one another:
  • Start by substituting the expression for \(P\) from one equation into the other equation.
  • By rearranging terms, isolate and solve for the variable \(N\).
  • Finally, use the value of \(N\) to find \(P\) by substituting back into either equation.
This way, you efficiently find the point of intersection for both equations, leading to the exact solution for this linear system.
Profit Models
Profit models refer to mathematical representations used to calculate profit for businesses based on various inputs. In our exercise, the system of equations represents profit for two Internet companies, with \(P\) as profit and \(N\) as website hits. Profit models like these are vital because they help businesses understand potential revenue under different conditions. They consist of:
  • A fixed or baseline profit component reflected by the constant terms in the equations.
  • A variable component that changes with the number of hits, shown by the coefficients multiplying \(N\).
These models enable companies to forecast and make strategic decisions, adapting to changes in the digital landscape. By analyzing these systems of equations, businesses can derive insights into how different variables impact profitability.
Algebraic Problem-Solving
Algebraic problem-solving involves using algebraic techniques and manipulation to find unknown values represented by variables. It is fundamental in understanding systems of equations. By breaking down equations into manageable steps, as shown in the substitution method, we navigate through complex problems effectively. In practice:
  • Simplify expressions by combining like terms.
  • Use operation properties to isolate variables efficiently.
  • Check solutions by substituting back into original equations to ensure consistency.
This approach fosters a logical, step-by-step process that enables accurate computation of solutions. By relying on these principles, solving algebra-based problems becomes a structured routine, ensuring robust and reliable outcomes across various contexts.
Exact vs Approximate Solutions
In mathematical modeling, an exact solution satisfies the equations perfectly, providing precise values for the variables involved. This is reflected in our exercise when substituting back, both equations yield the same \(P\) value, confirming accuracy. However, an exact solution is not always necessary, especially in real-world scenarios where dealing with large data sets or unstable conditions could render exact results impractical. An approximate solution allows flexibility and accommodates potential fluctuations and variations in data.Understanding the importance of both:
  • Exact solutions provide clarity and robustness in controlled, precise conditions.
  • Approximate solutions offer practicality, useful in real-time applications, allowing for margin of error and unforeseen changes.
Thus, deciding between exact and approximate solutions depends on the nature of the problem and the required level of precision needed for effective decision-making.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

APPLICATION Manuel has a sales job at a local furniture store. Once a year, on Employees' Day, every item in the store is \(15 \%\) off regular price. In addition, salespeople get to take home \(25 \%\) commission on the items they sell as a bonus. a. A loft bed with a built-in desk and closet usually costs \(\$ 839\). What will it cost on Employees'Day? (a) b. At the end of the day, Manuel's bonus is \(\$ 239.45\). How many dollars worth of merchandise did he sell? (TI

Write each solution matrix as an ordered pair. a. \(\left[\begin{array}{lll}1 & 0 & 8.5 \\ 0 & 1 & 2.8\end{array}\right]\) b. \(\left[\begin{array}{ccc}1 & 0 & \frac{1}{2} \\ 0 & 1 & \frac{13}{16}\end{array}\right]\) c. \(\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0\end{array}\right]\)

Here is the graph of this system of inequalities: $$ \left\\{\begin{array}{l} y>x \\ y>2-\frac{1}{2} x \end{array}\right. $$ Is each point listed a solution to the system? Explain why or why not. a. \((1,2)\) ( b. \((3,2)\) c. \(\left(\frac{4}{3}, \frac{4}{3}\right)\) d. \((5,-3)\)

Consider this system of equations: $$ \left\\{\begin{array}{l} 2 x-5 y=12 \\ 6 x-15 y=36 \end{array}\right. $$ a. By what number can you multiply which equation to eliminate the \(x\)-term when you combine the equations by addition? Do this multiplication. b. What is the sum of these equations? c. What is the solution to the system? d. How can you predict this result by examining the original equations?

Solve each equation using the method you like best. Then substitute your value for \(x\) back into the equation to check your solution. a. \(0.75 x=63.75\) b. \(18.86=-2.3 x\) c. \(6=12-2 x\) d. \(9=6(x-2)\) e. \(4(x+5)-8=18\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.