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APPLICATION Write a proportion for each problem, and solve for the unknown number. a. Leaf-cutter ants that live in Central and South America weigh about \(1.5\) grams (g). One ant can carry a \(4 \mathrm{~g}\) piece of leaf that is about the size of a dime. If a person could carry proportionally as much as the leaf- cutter ant, how much could a \(55 \mathrm{~kg}\) algebra student carry? (T) b. The leaf-cutter ant is about \(1.27 \mathrm{~cm}\) long and takes strides of \(0.84 \mathrm{~cm}\). If a person could take proportionally equivalent strides, what size strides would a \(1.65 \mathrm{~m}\) tall algebra student take? c. The \(1.27 \mathrm{~cm}\) long ants travel up to \(0.4 \mathrm{~km}\) from home each day. If a person could travel a proportional distance, how far would a \(1.65 \mathrm{~m}\) tall person travel?

Short Answer

Expert verified
a) 146.67 kg, b) 1.091 meters, c) 51.97 km.

Step by step solution

01

Understand the Problem Statement for (a)

We know that leaf-cutter ants can carry about 2.67 times their weight (4 g / 1.5 g). We need to find out how much weight a 55 kg student could carry if they could manage to carry weight in the same proportion.
02

Set Up the Proportion for (a)

Set up the proportion based on the idea that the ratio of weight carried to body weight for the ant is the same as the ratio for the student. Thus, the equation is:\[ \frac{4}{1.5} = \frac{x}{55} \] where \( x \) is the weight the student can carry.
03

Solve the Proportion for (a)

Cross-multiply to solve for \( x \):\[ 4 \times 55 = 1.5 \times x \]\[ 220 = 1.5x \]Now, divide both sides by 1.5:\[ x = \frac{220}{1.5} \approx 146.67 \text{ kg} \]
04

Understand the Problem Statement for (b)

The leaf-cutter ant has a stride-to-length ratio of \( \frac{0.84}{1.27} \). We need to find the stride size of a 1.65 m tall student if this proportion is maintained.
05

Set Up the Proportion for (b)

We'll use the stride-to-length ratio to find the stride size in proportion:\[ \frac{0.84}{1.27} = \frac{y}{1.65} \] where \( y \) is the stride length of the student.
06

Solve the Proportion for (b)

Cross-multiply and solve for \( y \):\[ 0.84 \times 1.65 = 1.27 \times y \]\[ 1.386 = 1.27y \]Now, divide both sides by 1.27:\[ y = \frac{1.386}{1.27} \approx 1.091 \text{ m} \]
07

Understand the Problem Statement for (c)

The ants' travel-to-length ratio is \( \frac{0.4}{0.0127} \). We need to determine how far a 1.65 m tall student would travel with this ratio.
08

Set Up the Proportion for (c)

Using the distance and length ratio, we set up the proportion:\[ \frac{0.4}{0.0127} = \frac{z}{1.65} \] where \( z \) is how far the student would travel.
09

Solve the Proportion for (c)

Cross-multiply to solve for \( z \):\[ 0.4 \times 1.65 = 0.0127 \times z \]\[ 0.66 = 0.0127z \]Now, divide both sides by 0.0127:\[ z = \frac{0.66}{0.0127} \approx 51.97 \text{ km} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Problem Solving
Problem solving is an essential skill in mathematics. It involves understanding the problem, planning a strategy, carrying it out, and checking the results. When faced with a problem like those involving proportional reasoning, it is important to break down the problem into smaller parts.

Begin by understanding what you are given and what you need to find. Read the question carefully. Identify the quantities involved. For instance, in the first part of the exercise, we know the weight of the ant and how much it can carry. We also know the student's weight and need to find how much they could carry if they were as strong as the ant relative to its weight.

After understanding the problem, the next step is to plan how to solve it. Often, setting up an equation or using a formula helps in solving mathematical problems. Use proportions as the strategy here, which involves setting up a ratio based on the information provided.
Proportional Reasoning
Proportional reasoning comes into play when you need to compare ratios or fractions. It's a way to see the relationship between different quantities.

The key idea is that two ratios or fractions are equivalent, meaning they have the same value when simplified. For example, when you know that an ant can carry a piece of leaf that is a particular multiple of its weight, you can set up a ratio between the weight carried and the body weight for both the ant and the student.

Suppose the ant's carrying capacity is a simple ratio like 4/1.5. For the student problem, set up a similar ratio for the student's weight and identify the unknown variable, which is how much the student can carry. This allows us to solve using cross-multiplication, which preserves the equality between the two ratios.
  • Ant ratio: \( \frac{4}{1.5} \)
  • Student ratio: \( \frac{x}{55} \)
This proportional reasoning is also applied to stride lengths and travel distances in further examples, providing real-world applications of mathematical concepts.
Mathematical Modeling
Mathematical modeling is about using mathematics to represent, analyze, and solve real-world problems. In this exercise, we model the relationships between various physical traits of the ant and a human using proportions.

Modeling starts by translating reality into mathematical expressions. First, identify the part of the real world you are interested in—like the attributes of the leaf-cutter ants—and translate these into mathematical terms like ratios. From there, you create a model by writing equations that express the proportional relationships. For example, we create equations to model the ant's weight-carrying capacity vs. a human's potential capacity to carry weight.

These models can then show us possible outcomes, such as how far a person could travel if they had proportions similar to the ant's. Modeling helps in making predictions and understanding concepts better. Remember, models are simplifications and rely on assumptions that should be taken into account when interpreting results.

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