Chapter 7: Problem 33
In Problems 31 through 35, the values of mass \(m\), spring constant \(k\), dashpot resistance \(c\), and force \(f(t)\) are given for \(a\) mass-spring-dashpot system with external forcing function. Solve the initial value problem $$ m x^{\prime \prime}+c x^{\prime}+k x=f(t), \quad x(0)=x^{\prime}(0)=0 $$ and construct the graph of the position function \(x(t) .\) \(m=1, k=9, c=0 ; f(t)=\sin t\) if \(0 \leqq t \leqq 2 \pi, f(t)=0\) if \(t>2 \pi\)
Short Answer
Step by step solution
Understanding the Differential Equation
Solving the Homogeneous Equation
Finding a Particular Solution
Constructing the General Solution
Applying Initial Conditions
Piecewise Consideration
Graphing the Position Function
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass-Spring-Dashpot System
The equation that describes this system is a second-order linear differential equation: \[ m x'' + c x' + k x = f(t) \]Here,
- \( m \) is the mass,
- \( c \) is the dashpot's damping constant (here it is 0),
- \( k \) is the spring constant,
- \( f(t) \) is any external force applied to the system.
Initial Value Problem
In the case of our mass-spring-dashpot system, we are given the initial conditions:
- \( x(0) = 0 \)
- \( x'(0) = 0 \).
By applying these conditions at specific time points (usually \( t = 0 \)), we are allowed to determine specific values for arbitrary constants in the general solution, leading to a unique solution tailored to the problem.
Homogeneous Solution
To solve the homogeneous equation, we use the characteristic equation derived from the differential equation:\[ r^2 + 9 = 0 \]The solutions to this are the roots, giving us complex solutions: \( r = \pm 3i \).
The solutions with complex roots lead to trigonometric functions:\[ x_h(t) = C_1 \cos(3t) + C_2 \sin(3t) \]Here, \( C_1 \) and \( C_2 \) are constants determined by the initial conditions. The homogeneous solution helps understand the natural behavior of the system when there's no external influence, forming a basis for constructing the full solution in dynamic scenarios.
Particular Solution
We seek a particular solution of the form:\[ x_p = A \sin t + B \cos t \]Substituting it back into the equation and matching coefficients with \( \sin t \), we establish:
- \( 8A = 1 \)
- \( 8B = 0 \).
This part of the solution represents how the system responds directly to the external force applied, considering the time domain affected.